What is the area of the shaded sector?
The measure of central angle XYZ is 1.257 radians.
O 101 units
O 207 units
O 40 units
O 80 units
N
8
X

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

        thus , ∠ABC=76° .

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

For Diagram, Please Find in Attachment  

Answer:

x = ±2

 x = ±i

Step-by-step explanation:

(x^2+4)^2 – 11(x^2+4) + 24 = 0

Let m = x^2 +4

(m)^2 – 11(m) + 24 = 0

Solving this quadratic

What two numbers multiply to 24 and add to -11

-8*-3 =24

-8-3 = -11

(m-8)(m-3) =0

m = 8   m=3

Now substitute back

x^2 +4 = 8    x^2 +4 = 3

x^2 +4-4 = 8-4    x^2+4-4 = 3-4

x^2 = 4                      x^2 = -1

Taking the square root

sqrt(x^2) = sqrt(4)                      sqrt(x^2) = sqrt(-1)

x = ±2                                           x = ±i

Answer:

one value of x = 2

Step-by-step explanation:

[tex](x^2 + 4 )^2 - 11(x^2 + 4 ) + 24 = 0\\\\x^4 + 16 + 8x^2 - 11x^2 -44 + 24 = 0\\\\x^4 - 3x^2 -4 = 0\\\\[/tex]   ------ ( 1 )

[tex]Let \ x^2 \ = \ u[/tex]

( 1 ) => [tex]u^2 - 3u - 4 = 0[/tex]

         [tex]u^2 -4u + u - 4 = 0\\\\u(u - 4) + 1 (u - 4) = 0\\\\(u + 1) (u - 4) = 0\\\\u = -1 \ , \ u = 4[/tex]

   [tex]=> x^2 = - 1 \ and \ x^2 = 4[/tex]

      [tex]x = \sqrt {-1} = i[/tex]

      [tex]x = \sqrt{4} = \pm 2[/tex]

Answer:

56+8√2=8(7+√2)

Step-by-step explanation:

1. P= AB+BC+CD+DE+EF+FG+GA

2. AB=DC=12

BC=16

AG=ED=4

AG+ED+GE=16

4+4+GE=16

GE=16-8

GE=8

GF²= EF²+GE²

GF²=64+64

GF²=128

GF=8√2

3.P= 12+16+12+4+8+8√2+4= 56+8√2

Answer:

Area = 160 sq cm

Perimeter = 67.31 cm

Step-by-step explanation:

Area of the figure = Area of rectangle with dimensions 16 cm and 12 cm - Area of the right triangle with base and height ecah 8 cm.

=16*12 - 1/2 * 8 *8

= 192 - 32

= 160 sq cm

GEF is a right triangle.

Therefore, by Pythagoras theorem:

[tex] FG^2 = FE^2 + GE^2 [/tex]

[tex] \therefore FG^2 = 8^2 + 8^2 [/tex]

[tex] \therefore FG^2 = 64+64 [/tex]

[tex] \therefore FG^2 = 128 [/tex]

[tex] \therefore FG =\sqrt {128}[/tex]

[tex] \therefore FG =11.3137085[/tex]

[tex] \therefore FG = 11.31\: cm[/tex]

Perimeter of the figure

= 12 + 16 + 12+4+8+11.31+4

= 67.31 cm

QUESTION:- Given 3x+y=1

Write the equation in general form Ax+By+C =0

3x-y+1=0

-3x +y-1=0

3x-y=-1

[tex]3x + y - 1 = 0 \: \: ✔[/tex]

ANSWER:-

[tex]3x + y = 1 [/tex]

Form of the given equation->

[tex]Ax + By = C[/tex]

so we need to change the side of the C !

while changing side of C we need to change the sign of C !

[tex] \bold{ \red{SO :- }}[/tex]

[tex]3 x + y = 1 \\ 3x + y - 1 = 0[/tex]

FORM OF THE RESULTED EQUATION:-

[tex]Ax + By + C = 0 \\

A = 3 \\ B = 1 \\ C = - 1[/tex]

Answer:

a. 125 – 7d

Step-by-step explanation:

Let d be the number of days.

Given the following data;

Total distance (month) = 125 miles

Distance covered per day = 7 miles

To determine how many miles he has left to run after running for "d" days, this mathematical expression can be used;

Total distance - distance covered per day = number of miles remaining

[tex] 125 - 7d [/tex]

Answer:

35 oz =  2.1875 lb

Step-by-step explanation:

There are 16 ounces in a pound.

35/16 = 2.1875

35 oz =  2.1875 lb.

Hope this helps.

Answer:

275, 300, 450, 490, 675

Median: 450

Q1: 287

Step-by-step explanation:

Answer:

(If the x means the variable in your equation) 2a^2y+6x^2+3xy

Step-by-step explanation:

We have to simplify the equation to find the answer

6x^2+3xy−2a(−a)y

=6x^2+3xy+2a^2y

Answer:

x = 80

Step-by-step explanation:

x + .1x = 88

or

x(1+.1) = 88

which ever makes more sense to you

1.1 x = 88

x = 88/1.1

x = 80

Answer:

Hy^2 = H^2 + B^2

= 7^2 + 12^2

D.) = 193 square root

1) angle LKM

2) angle MKL

Answer: 12 and 24

Step-by-step explanation:

Answer:

Area of a triangle=1/2base x height

1/2x12x4

6x4

24units

Perimeter is the distance round the given figure

9+12+5

26units

Answer:

Step-by-step explanation:

Answer:

[tex]b = \dfrac{11}{x} + 1[/tex]

Step-by-step explanation:

The equation is given as follows;

[tex]x + 3 - \dfrac{1}{2} \cdot x = \dfrac{1}{2} \cdot (b \cdot x - 5)[/tex]

By expanding and collecting terms in x we get;

[tex]3 + \dfrac{x}{2} = \dfrac{b \cdot x}{2} - 2.5[/tex]

[tex]\therefore 3 + 2.5 + \dfrac{x}{2} = 5.5 + \dfrac{x}{2} = \dfrac{b \cdot x}{2}[/tex]

b = (11 + x)/x = 11/x + 1

The equation has exactly one solution when b = 11/x + 1

Answer:

Can I get the full question please

Step-by-step explanation:

x + y = 10 - - - 1

x=2y - - - - - 2

Putting the value of x in eqn 1,

2y+y=10

y=10/3

=3.33 yrs

Which i feel is incorrect

Answer:

gal = 663902.4

11 pavers

Step-by-step explanation:

V = l × w × h

V = 164 × 82 × 6.6

V = [tex]88757ft^3[/tex]

**********************************

The Swimming pool is a

rectangular prism. Write

the formula for its volume

and calculate it.

l...length of this prism

w...width of this prism

h...height of this prism

V ...volume

*********************************

To know how many

gallons are in the pool,

multiply the volume by

the number of gallons

in [tex]1ft^3[/tex] gal...number of

gallons

********************************

gal = 88757 × 7.48

gal = 663902.4

********************************

First to not confuse

anybody on this, we need

to convert the meters into

centimeters.

Rule: 1 m = 100 cm

        3 m = 300 cm

        2.5 m = 250 cm

********************************

so for every meter, we

multiply 100 to get the

amount of centimeters

********************************

so then add the

centimeters of 3 m and

2.5 m

Answer: 550 cm

so then now compare

the measurings...

3 m = 300 cm

50cm × y = 300cm

50cm × 6 = 300cm

y = 6

2.5 m = 250 cm

50cm × y = 250cm

50cm × 5 = 250cm

y = 5

6 + 5 = 11 pavers

so Oliver will need 11 pavers

Answer:

13 : 8

Step-by-step explanation:

Number of plain bagels sold = 8

Number of rye bagels sold = 13

Ratio of the number of rye bagels to the number of plain bagels sold = 13 : 8

Also written as

13/8

Or

13 to 8

A bagel shop sold 8 plain bagels and 13 rye bagels. What is the ratio of the number of rye bagels to the number of plain bagels sold?

Answer: It is 13: 8.

Answer:

x=0;y=2

Step-by-step explanation:

4(-x+2)=2x+8 -4x+8=2x+8 -4x-2x=8-8 -6x=0 x=0 y=-x+2 y=0+2 y=2

Answer:

circumference of a circle =2 pi r

radius=14/2=7

2×3.14×7=43.96ft

The circumference of the circle is 43.96 ft.

Given,

Diameter of the circle = 14 ft

π = 3.14

We need to find the circumference of a circle.

The circumference is the total length of the surface of the circle.

The circumference is given by:

= 2πr

r = radius of the circle

Diameter = 2radius

Example:

We have,

Diameter = 14 ft

π = 3.14

Radius = diameter / 2 =  14/2 = 7 ft

Circumference:

= 2πr

= 2 x 3.14 x 7

= 43.96 ft

Thus the circumference of the circle is 43.96 ft.

Learn more about circles here:

https://brainly.com/question/16125353

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Answer:

12.21

Step-by-step explanation:

Explanation:

This is a right triangle, so the Pythagorean Theorem applies.

The Pythagorean Theorem states that the sum of the squared legs of a triangle is equal to the squared hypotenuse.

The legs of a triangle are the sides that form the right angle.

The hypotenuse of a triangle is the longest side.

Formula/solve:

[tex]a^2+b^2=c^2[/tex]

[tex]a,b-legs[/tex]

[tex]c-hypotenuse[/tex]

Here, I am solving for the hypotenuse.

[tex]7^2+10^2=c^2[/tex]

[tex]49+100=c^2[/tex]

[tex]149=c^2[/tex]

Conclude:

The last step is the cancel out c² by finding the square root of 149.

149 is not a perfect square, so I must round the square root to the nearest hundredth.

[tex]12.2065556157[/tex] ≈ [tex]12.21[/tex]

I, therefore, believe the length of the hypotenuse is 12.21 feet.

1) angle LJK

2) angle KJL

The marked angle can be named as angle LJK and angle KJL.

An angle is a corner whether constituting a projecting part or a partially enclosed space. It is a combination of two rays with a common endpoint.

The angle can be named in two ways depending on the rays that are making angle.In our question the marked angle can be named as LJK and opposite if this KJL because it does not change the value of angles. Whether we start writing from one point to second point and from second point to first point. Main point is that the point at which the angle is formed comes in between both the points of rays.

Hence the marked angle can be named as angle LJK and angle KJL.

Learn more about angles at https://brainly.com/question/25716982

#SPJ2

Answer:

[tex]h^2-3h+5\:\text{remainder }3 \text{ or }h^2-3h+5-\frac{3}{h+3}[/tex]

Step-by-step explanation:

Question: [tex]\frac{h^3-4h+12}{h+3}[/tex] (divide using long division)

To start, our quotient must have a degree of 2, since [tex]h\cdot h^2=h^3[/tex].

From long division, multiply by the highest degree possible with appropriate constants to ride terms of the dividend when necessary. When you finish, the final term at the bottom will be your remainder and your quotient will be on top (in long division form).

The result is [tex]\frac{h^3-4h+12}{h+3}=h^2-3h+5\text{ with a remainder of } 3[/tex]. You can write it in quotient-remainder form, or as one long polynomial: [tex]\implies h^2-3h+5-\frac{3}{h+3}[/tex].

Verify:

[tex](h^2-3h+5)(h+3)=h^3-4h+15=\bold{h^3-4h+12}+\underline{3} \:\checkmark[/tex]

Answer: A = 4400(1 + 0.0825 x 22)

Step-by-step explanation:

A = accumulated amount

P = original amount  unloaded- $4400

r = rate - 8.25% = 0.0825

t = years = 22

= 4400(1 + 0.0825 x 22)

Answer:

y = 25169.04

Step-by-step explanation:

Answer: the 24 oz hazelnuts

Step-by-step explanation:

Answer:

hazelnuts

Step-by-step explanation:

pecans = $15.2/16= .95

cashews = 5.60/8=.7

almonds = 20.48/32= .64

hazelnuts = 13.5/24 = .56

Answer:

$ 5.98

Step-by-step explanation:

20/100 × 22.42/1 = $ 4.48

$ 22.42 - $ 4.48 = $ 17.94

If they split that bill in two each would pay $ 5.98

I hope this helps.

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]

[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]

[tex]\huge\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{mass \: 1 \: = \: 6000 \: kg}[/tex]

[tex]\quad\quad\quad\quad\sf{velocity\: 1\: = \: 2.0\: m/s}[/tex]

[tex]\quad\quad\quad\quad\sf{mass \: 2\: = \: 3000 \: kg}[/tex]

[tex]\quad\quad\quad\quad\sf{velocity\: 2\: = \: 3.0\: m/s}[/tex]

[tex]\huge\underline{\sf{\red{Fomula:}}}[/tex]

[tex]\quad\quad\quad\quad\boxed{\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}}[/tex]

[tex]\huge\underline{\sf{\red{Solution:}}} [/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}[/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(6000 \: kg)(2.0\:m/s)+(3000\:kg)(3.0\:m/s)}{(6000\:kg)+(3000\:kg)}}[/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(12,000kgm/s)+(9,000\:kgm/s)}{(9,000kg)}}[/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \: kgm/s}{9000kg}}[/tex]

[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \cancel{ \red{ kg}}m/s}{9000 \cancel{ \red{kg}}}}[/tex]

[tex]\quad\quad\quad\quad \sf{vf\: = \boxed{ \sf{ 2.33 \:m /s}}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad\quad \underline{ \sf{\boxed{ \sf{ \red{ 2.33 \:m /s}}}}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]

[tex]\sf{\red{︎✰}ShineBrighter\red{︎✰}}[/tex]

[tex]\sf{✍︎ C.Rose\red{❀}}[/tex]

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