What is the empirical formula for a compound if 300. 00 g of it is known to contain 82. 46224 g of molybdenum, 45. 741 g of chlorine and the rest is bromine?

Because of the very short period in which nucleosynthesis occurred before it was stopped by expansion and cooling (about 20 minutes), no elements heavier than beryllium (or possibly boron) could be formed.

Big Bang nucleosynthesis occurred inside the first three minutes of the start of the universe and is chargeable for an awful lot of the abundance of H (protium), H (D, deuterium), He (helium-three), and He (helium-4).

Although He remains produced by stellar fusion and alpha decays and hint quantities of H remain produced by way of spallation and certain sorts of radioactive decay, most of the mass of the isotopes inside the universe is thought to be produced in the Big Bang.

The nuclei of these elements, together with a few Li and Be are taken into consideration to have been fashioned between 100 and 300 seconds after the Big Bang whilst the primordial quark-gluon plasma froze out to form protons and neutrons.

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A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

Dalton's Law of partial pressure states that the total pressure exerted by non reacting gaseous mixture at a constant temperature and given volume is equal to the sum of partial pressure of all gases.

It is expressed as:

[tex]P_{A} = X_{A} P_{T}[/tex]

where,

[tex]P_{A}[/tex] = Partial pressure of gas A

[tex]X_{A}[/tex] = Mole fraction of gas A

[tex]P_{T}[/tex] = Total pressure

Mole Fraction of Nitrogen

= [tex]\frac{930}{930 + 850}[/tex]

= 0.52

Mole Fraction of Oxygen

= [tex]\frac{850}{850 + 930}[/tex]

= 0.47

Now,

Mole fraction of nitrogen + Mole fraction of oxygen + Mole fraction of carbon dioxide = 1

⇒ 0.52 + 0.47 + Mole fraction of carbon dioxide = 1

⇒ 0.99 + Mole fraction of carbon dioxide = 1

⇒ Mole fraction of carbon dioxide = 1 - 0.99

⇒ Mole fraction of carbon dioxide = 0.01

Now put the value in above expression we get

[tex]P_{A} = X_{A} P_{T}[/tex]

     = 0.01 × 2710

     = 27.1 torr

Thus from the above conclusion we can say that A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

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The molar solubility of AgCl:

The molar solubility of AgCl in a 0.050 M NaCl solution is 8 x [tex]10^{-8}[/tex] M [tex]Ag^{+}[/tex]

What is solubility?

The solubility is the quantity of reagent required to saturate the solution or bring about the dissociation reaction's equilibrium.

Reaction:

The dissociation reaction of AgCl in water is:

[tex]AgCl[/tex]  ⇄ [tex]Ag^{+} + Cl^{-}[/tex]

Each mole of AgCl that dissolves in this reaction yields 1 mole of both [tex]Ag^{+}[/tex] and  [tex]Cl^{-}[/tex]. The concentration of either the Ag or Cl ions would then be equal to the solubility.

Solubility= [[tex]Ag^{+}[/tex]] = [[tex]Cl^{-}[/tex]]

Calculation:

in 0.050 M NaCl, the [[tex]Cl^{-}[/tex]] = 1 x [tex]10^{-2}[/tex]

ksp = [[tex]Ag^{+}[/tex]] x [[tex]Cl^{-}[/tex]]

1.6 x [tex]10^{-10}[/tex] = [[tex]Ag{+}[/tex]] x ( 5 x [tex]10^{-2}[/tex])

[[tex]Ag^{+}[/tex]] = 5 x [tex]10^{+2}[/tex] x 1.6 x [tex]10^{-10}[/tex]

[[tex]Ag^{+}[/tex]] = 5 x 1.6 x [tex]10^{-10+2}[/tex]

[[tex]Ag^{+}[/tex]] = 8 x [tex]10^{-8}[/tex] M

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The law that relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions is ideal gas law (option C).

Ideal gas law in physics refers to the equation of state of an ideal gas. The law equation is as follows:

PV = nRT

Where;

Therefore, it can be said that the law that relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions is ideal gas law.

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Answer:

C. Ideal Gas Law

Explanation:

edge ;)

Answer:

196J, but C. at 200 J comes close.

Explanation:

Potential energy due to gravity is given by:

PEgrav = mass • g • height

where g is the acceleration due to gravity.  We'll use 9.8 N/kg (on Earth).

PEgrav = mass • g • height

PEgrav = (2 kg) • (9.8 N/kg) • (10 m)

PEgrav = 196 N*m

1 N*m = 1 Joule

PEgrav = 196 J

C. at 200 J comes close.  The solution probably used a value of g equal to 10 N/kg)

Answer:

20 J

Explanation:

The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose because the activation energy of the reaction is high.

Hence, Option (B) is correct answer.

The minimum amount of energy that must be provided by a reacting molecules to get converted into the product is called Activation energy.

It is expressed as:

[tex]k = Ae^{\frac{-E_a}{RT}}[/tex]

where,

k = rate constant

A = pre-exponential factor

Eₐ = activation energy

R = universal gas constant

T = absolute temperature in K

Thus from the above conclusion we can say that The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose because the activation energy of the reaction is high.

Hence, Option (B) is correct answer.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The hydrolysis of sucrose to glucose and fructose is exergonic. However, if sucrose is dissolved in water and the solution is kept overnight at room temperature, there is no detectable conversion to glucose and fructose. Why?

A. The change in free energy of the reaction is positive.

B. The activation energy of the reaction is high.

C. The change in free energy of the reaction is negative.

D. This is a hydrolysis reaction, so it requires an input of energy.

E. The free energy of the products is higher than the free energy of the reactants.

The total percent yield:

After the combustion reaction with methane, the percent yield was 66.7%.  

Combustion of Methane:

The other reactant, air's excess oxygen, is always present, making methane the limiting reactant. As a result, the amount of CH₄ burned will determine how much CO₂ and H₂O are produced.

The following chemical process produces carbon dioxide from methane:

CH₄ + 2O₂ ⇒ CO₂ + 2H₂O

Calculations:

1. Theoretical quantity of carbon dioxide:

All calculations will be based on the amount of methane because the problem specifies that it is the limiting reagent:

12.0g of CH₄ × (1 mol of CH₄/16g CH₄) × (1 mole of CO₂/1 mole of CH₄) × (44g CO₂/1 mole of CO₂)

= 33g of CO₂

2. Percent yield:

= Actual yield/Theoretical yield × 100

= 22.0g/33g × 100

= 66.7%

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Answer:

renewable energy sources such as solar and wind DONT emit carbon dioxide and other greenhouse gases that contribute to global warming

Explanation:

The Part of Nicotinamide Adenine Dinucleotide NADH that is a vitamin is niacin, a type of B vitamin.

This cofactor acts as a hydrogen acceptor in oxidation-reduction reactions.

NADH  is the reduced form of the NAD+, which means that it gains the electron lost by NAD+. NADH is a very important coenzyme central to metabolism.

   NADH is a dinucloetide because it consists of two nucleotides joined through their phosphate groups.

 One nucleotide contains an adenine nucleobase and the other nicotinamide.

A cofactor is a non-protein chemical compound or metallic ion that is required for an enzyme's role as a catalyst in a chemical reaction. A cofactor binds to an enzyme to bring about its  catalytic reaction.

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The total mass of the reactants equals the total mass of the products

Answer:

(a) Gas pressure ---------------------> (iii) force per unit area

(b) One mole of substance -------------------> (i) 6.02 x 10²³

(c) One mole of any gas ----------------------> (ii) 22.4 dm³ at STP

(d) Avogadro's number -----------------> (iv) 6.02 x 10²³ particles

Answer:

This is an example of an exothermic reaction.

Explanation:

When the heat of combustion is negative, the reaction is exothermic. This means the reaction releases heat as a product.

Answer:

10.2 °C

Explanation:

If all other variables are held constant, you can find the new temperature using the Charles' Law equation. The equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can find the new temperature by plugging the given values into the equation and simplifying.

V₁ = 122 mL                     V₂ = 50 mL

T₁ = 25 °C                        T₂ = ? °C

V₁ / T₁ = V₂ / T₂                                         <----- Charles' Law equation

122 mL / 25 °C = 50 mL / T₂                    <----- Insert values

4.88 = 50 mL / T₂                                     <----- Divide 25 from 122

4.88 x T₂ = 50 mL                                    <----- Multiply both sides by T₂

T₂ = 10.2 °C                                             <----- Divide both sides by 4.88

Answer:

.129 J / g-C

Explanation:

specific heat =  J / g-°C

                     = 3000 J / ( 465 g  * 50C ) =.129 J /g-C

Taking into account the reaction stoichiometry, 15.33 grams ethanol could be obtained from 30 grams of glucose.

In first place, the balanced reaction is:

C₆H₁₂O₆  → 2 C₂H₅OH + 2 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 180 grams of glucose form 92 grams of ethanol, 30 grams of glucose form how much mass of ethanol?

[tex]mass of ethanol=\frac{30 grams of glucosex 92 grams of ethanol}{180 grams of glucose}[/tex]

mass of ethanol= 15.33 grams

Then, 15.33 grams ethanol could be obtained from 30 grams of glucose.

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The rate of reaction at 150 degrees is 1.878.

We have the formula as;

ln(k2/k1) = Ea/R (1/T1 - 1/T2)

ln(2( 0.0110)/0.0110) = 45.5  * 10^3/8.314(1/294 - 1/T2)

0.693 = 5473(1/294 - 1/T2)

0.693/ 5473 = (1/294 - 1/T2)

1.27 * 10^-4 = 1/294

1/T2 = 1/294  - 1.27 * 10^-4

1/T2 = 340 * 10^-4 - 1.27 * 10^-4

T2 = 30 degrees

Again;

ln(k2/0.0110) =  45.5  * 10^3/8.314(1/303 - 1/423)

ln(k2/0.0110) = 5473(3.3 * 10^3 - 2.36  * 10^3)

ln(k2/0.0110) = 5.14

k2/0.0110 = e^5.14

k2 = 0.0110 * e^5.14

k2 = 1.878

The temperature that the reaction will go twice as fast is 30 degrees while the rate construction at 150 degrees is 1.878.

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The reaction is completed by the equation below: [tex]3H_2 + N_2 --- > 2NH_3[/tex]

They are chemical reactions in which two or more molecules react to produce a single product.

In this case, the synthesis reaction is that of ammonia. Molecules of hydrogen gas and nitrogen gas combine to produce ammonia.

The equation of the reaction is as follows: [tex]3H_2 + N_2 --- > 2NH_3[/tex]

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H - C ≡ C - CH₂ - CH₃ this is an alkyne molecule.

Hence, Option C is correct answer.

The saturated hydrocarbon which have only single bonds between the carbon atoms is called Alkanes.

The unsaturated hydrocarbon which have at least one carbon carbon double bond is called Alkene.

The unsaturated hydrocarbon which have one or more than one carbon carbon triple bonds is called Alkynes.

H - C ≡ C - CH₂ - CH₃ in this molecule one triple bond is present so it is alkyne.

Thus from the above conclusion we can say that H - C ≡ C - CH₂ - CH₃ this is an alkyne molecule.

Hence, Option C is correct answer.

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Answer:

0.638 M NaOH

Explanation:

To find the molarity of the solution, you need to (1) convert grams NaOH to moles NaOH (via the molar mass of NaOH) and then (2) calculate the molarity (via the molarity formula). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator).

(Step 1)

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.996 g/mol

25.5 grams NaOH                 1 mole
-----------------------------  x  ----------------------------  =  0.638 moles NaOH
                                           39.996 grams

(Step 2)

Molarity = moles / volume (L)

Molarity = 0.638 moles / 1 L

Molarity = 0.638 M

To successfully adjust the pH, as there was no equipment to measure and transfer the correct volume of acid, then A. Use a less concentrated acid to adjust the pH so the required volume would be larger.

This is a substance that changes the taste in water solution and changes blue litmus paper to red, reacts with some metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions (acid catalysis).

Hence because there was no equipment available to measure and transfer the correct volume of acid, the best and safest and most successful thing to be done is to use a less concentrated acid to adjust the pH so the required volume would be larger.

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The ΔG° for the reaction in kJ/mol is -17.09.

Calculation,

The reaction is given below.

[tex]ICl(g)+Cl_{2} (g)[/tex]  → [tex]ICl_{3} (s)[/tex]

The ΔG° for [tex]ICl(g)[/tex] = -5.5  kJ/mol

The ΔG° for [tex]ICl_{3} (s)[/tex]  = -22.59  kJ/mol

The ΔG° for  [tex]Cl_{2} (g)[/tex]  = 0  kJ/mol ( change in gibb's free energy of standard state )

ΔG° for the reaction =  ΔG° (product) -  ΔG° (reactant)

ΔG°  for the reaction = -22.59  kJ/mol - ( -5.5  kJ/mol + 0  kJ/mol )

 ΔG°  for the reaction = -17.09  kJ/mol

The value of change standard gibb's free energy for the standard state ( most stable form of elements) is zero.

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The complete equation representing the synthesis reaction for the formation of ammonia is: 3 H₂ + N₂ ⇒ 2 NH₃

It is a reaction in which 2 or more substances combine to form 1 product.

Let's consider the following incomplete synthesis reaction.

3 H₂ + ____ ⇒ 2 NH₃

According to Lavoisier's law, the mass and the elements must be conserved in a chemical reaction. So, since there is nitrogen to the right, the missing element to the left must be nitrogen. Molecular nitrogen is diatomic.

The complete reaction is:

3 H₂ + N₂ ⇒ 2 NH₃

The complete equation representing the synthesis reaction for the formation of ammonia is: 3 H₂ + N₂ ⇒ 2 NH₃

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From the calculations, the pH of the buffer is 3.1.

The  Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;

pH = pKa + log[(salt/acid]

Amount of the salt = 25/1000 *  0.50 M = 0.0125 moles

Amount of the acid = 75/1000 *  1.00 M = 0.075 moles

Total volume = ( 25 + 75)/1000 = 0.1 L

Molarity of salt = 0.0125 moles/0.1 L = 0.125 M

Molarity of the acid = 0.075 moles/0.1 L = 0.75 M

Given that the pKa of lactic acid is 3.86

pH = 3.86 + log( 0.125/0.75)

pH = 3.1

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The surface area of the statute covered with the gold is 9,627.32 m².

Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

The volume of the statute covered with gold is calculated as follows;

Volume = mass/density

Volume = (279 kg) / (19,320 kg/m³)

Volume = 0.0144 m³

The surface area of a solid object is a measure of the total area that the surface of the object occupies.

V = S.A x h

where;

S.A = V/h

S.A = (0.0144) / (0.0015 x 10⁻³)

S.A = 9,627.32 m²

Thus, the surface area of the statute covered with the gold is 9,627.32 m².

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With a good mask-to-face seal and an oxygen flow rate of 15 L/min, the nonrebreathing mask is capable of delivering up to  90% inspired oxygen.

FiO2 is the fraction of inspired oxygen which is explained as the concentration of oxygen inhaled by a person.

It delivers a high concentration of oxygen. Hence the liter flow will be 8-15L/min with the percentage of oxygen between 60-90%.

The liter flow of nonbreathing mask must not be less than 8L/min.

From the above information we can conclude that the fraction of inspired oxygen for a nonbreathing mask is 90%

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Answer:

B.)  in front of the formula of a reactant or product.

Explanation:

Coefficients modify the amount of a particular molecule. As such, they are placed directly in front of the molecule's formula.

We use a solution, such as a cabbage ph indicator, to measure the ph of household items :

Anthocyanin, a water-soluble pigment found in red cabbage, can change color when combined with an acid or a basic. The color changes to red in situations with a pH under 7, and to bluish-green in alkaline (basic) environments with a pH above 7. Cabbage isn't known to cause acid reflux, but plenty of other common foods are.

Anthocyanin turns pink when it interacts with the hydronium ions in an acid, and blue or green when it interacts with the hydroxide ions in a base. Because it may inform us if a substance is acidic or basic by changing color, cabbage juice is referred to as a pH indicator.

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Hydrochloric acid is a different kind of acid than chloric acid.

Ternary Acids (Oxy-acids) Ternary acids are also referred to as “Oxy-acids. Include hydrogen and oxygen and yet another (normally) nonmetallic detail. Those acids comprise each hydrogen and oxygen but their names make no reference to either hydrogen or oxygen.

A ternary acid is an acid that has the elements hydrogen and oxygen together with every other element, frequently a nonmetal. Or, they comprise hydrogen in addition to a polyatomic ion. An -ate complicated ion is named an -ic acid. as an example, HClO3(aq) consists of the chlorate ion and is known as chloric acid.

A binary acid is an acidic compound that always has hydrogen boned to every other chemical element, most of the time a nonmetal. Ternary acids are acidic compounds that comprise hydrogen and oxygen blended with some other detail. Binary acid has one style of a chemical element (hydrogen bonded to a nonmetal) .

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n = m/M = 2/18 = 1/9 ~0,1 mol

Answer:

.111 mole    (using 3 significant digits)

Explanation:

Mole weight of H2O  = 2 x 1.008  + 15.999 = 18.015 gm/mole

2 gm / 18.015 gm/mole = .111 mole