What is the monthly payment on a 15-year loan of $57,900 if the annual interest rate is 12%?​

Answer:

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Answer:

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.

A Let tower be AB

Let point be C

Distance of point C from foot of tower = 30m Hence,

BC = 30m

Angle of elevation = 30°

So < ACB = 30°

Since tower is vertical,

< ABC = 90°

Answers:

=======================================================

Explanation:

So far that accounts for 15+30+35 = 80 people who work in the field, the office, or both.

The remaining 90-80 = 10 people are absent.

The venn diagram is below.

Answer:

I guess it is the Answer C

Answer:

C

The distance around the edge of the circle

Answer:

m = +/- 12

Step-by-step explanation:

A quadratic function has only one x-intercept when the discriminant is equal to 0. The discriminant is b^2 - 4(a)(c).

When we plug in what we know, we have:

m^2 - 4(18)(2) = 0.

Then using algebraic properties, solve for m.

m^2 - 144 = 0

m^2 = 144

m = +/- 12

When you plug in positive or negative 12, and then factor you will see that it comes out to a difference of squares, proving that there is only one x-intercept.

Answer: C

Step-by-step explanation:

EDGE 2023

Answer:

The answer is A

Step-by-step explanation:

Answer:

The value of equipment after 2 years is $58,800

Step-by-step explanation:

f(n) = 67,500(14/15)ⁿ

where f(n) is the value after n years.

1 – 1 / 15 = 14 / 15.

Answer:

Yes, because they are identical to eachother

Step-by-step explanation:

Answer:

8x+(-20x)

Step-by-step explanation:

Answer:

1) V = 336mm

2) V = 64.33ft

Step-by-step explanation:

1) V = lwh + lwh

V = 4(6)(5) + 9(6)(4)

V = 120 + 216

V = 336mm

2) V = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex]r^{2}[/tex]h +  

Cone = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex]r^{2}[/tex]h

Cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h

V = [tex]\frac{1}{3}[/tex][tex]\pi[/tex][tex](1.5)^{2}[/tex](3) +

V = [tex]\pi[/tex][tex](1.5)^{2}[/tex] +

V = 7.07 + 57.26

V = 64.33ft

Answer:

no we can't

Step-by-step explanation:

(-4)÷(-2). (-16÷(-2)

2. 8

[tex]\longrightarrow{\blue{[( - 16)\div 4) \div ( - 2)] \:is\:not\:equal\:to\:( - 16) \div [4 \div( - 2) ] }}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex][( - 16 )\div 4) \div ( - 2)] = ( - 16) \div [4 \div( - 2) ][/tex]

Let us first solve for L. H. S.

[tex] = [( - 16 )\div 4) \div ( - 2)][/tex]

[tex] = [ (\frac{ - 16}{4} )\div ( - 2)][/tex]

[tex] = \frac{( - 4)}{( - 2)} [/tex]

[tex] = 2[/tex]

Now, R. H S.

[tex]( - 16) \div [4 \div ( - 2)][/tex]

[tex] = \frac{ - 16}{ - 2} [/tex]

[tex] = 8[/tex]

[tex]\sf\purple{L. H. S.\: ≠ \:R. H. S. }[/tex]

Hence, [tex][( - 16) \div 4) \div( - 2)] ≠(-16)\div [4 \div( - 2) ][/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

Answer :

70.5% weight increase

Given:

The system of equations is:

[tex]x+3y=5[/tex]

[tex]x-3y=-1[/tex]

The given matrices are [tex]\left[\begin{array}{cc}5&3\\-1&-3\end{array}\right] [/tex], [tex]\left[\begin{array}{cc}1&5\\1&-1\end{array}\right][/tex], [tex]\left[\begin{array}{cc}1&3\\1&-3\end{array}\right][/tex].

To find:

The correct names for the given matrices.

Solution:

We have,

[tex]x+3y=5[/tex]

[tex]x-3y=-1[/tex]

Here, coefficients of x are 1 and 1 respectively, the coefficients of y are 3 and -3 respectively and constant terms are 5 and -1 respectively.

In the x-determinant, the coefficients of x are in the first column and the constant terms are in the second column. So, the x-determinant is:

[tex]\left[\begin{array}{cc}1&5\\1&-1\end{array}\right][/tex]

In the y-determinant, the constant terms are in the first column and the coefficients of y are in the second column. So, the y-determinant is:

[tex]\left[\begin{array}{cc}5&3\\-1&-3\end{array}\right] [/tex]

In the system determinant, the coefficients of x are in the first column and the coefficients of y are in the second column. So, the system determinant is:

[tex]\left[\begin{array}{cc}1&3\\1&-3\end{array}\right][/tex]

Therefore, the first matrix is y-determinant, second matrix is x-determinant and the third matrix is the system determinant.

Answer:

domain of function refers to the various values that can be passed through to the function.

Step-by-step explanation:

The zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3

The function is given as:

y = 6x^2 + x - 35

Expand the function

y = 6x^2 + 15x - 14x - 35

Factorize the function

y = (2x + 5) * (3x - 7)

Set the function to 0

(2x + 5) * (3x - 7) = 0

Split

2x + 5 = 0 or 3x - 7 = 0

Solve for x

x = -2.5 or x = 7/3

Hence, the zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3

Read more about quadratic functions at:

https://brainly.com/question/1214333

#SPJ1

Answer:

Step-by-step explanation:

b = sqrt(2 * L)                 Given

L = 4.5                            Given

b = sqrt(2 * 4.5)

b = sqrt(9)

b = 3

Answer:

b = 9

Step-by-step explanation:

Given :-

[tex] \small \sf \: b = \sqrt{2 \it \: l} [/tex]

[tex] \small \: l = 4.5[/tex]

Solution :-

[tex] \small \sf \: b = \sqrt{2 \it \: l} [/tex]

plug the values of l in the equation

[tex] \small \sf \leadsto \: b = \sqrt{2 × 4.5} [/tex]

[tex] \small \sf \leadsto \: b = \sqrt{9} [/tex]

[tex] \small \sf \leadsto \: b = 9 [/tex]

Answer:

Step-by-step explanation:

According to the Question,

Then, For any u,w ∈ V ⇒ u+w ∈ V

And u∈V and z∈C ⇒ z u ∈ V

So, If we take any z= i ∈ C

then, z,v ∉ V  ∴z,v Has Complex entries

So, the Scalar Closure axiom is not satisfied

Hence, V is not a Vector Space of C

Any u,w ∈ W ⇒ u+w ∈ V

So, The Additive Closure axiom is satisfied.

Answer:

x = 18

y = 38

Step-by-step explanation:

Let the smaller number be = x

Let the larger number be = y

Sum of the number, x + y = 56 --------- ( 1 )

Seven  times smaller number = 7x

Three times larger number = 3y

Seven times smaller = 12 more than 3times larger , 7x = 12 + 3y ----- ( 2 )

Solve ( 1 ) and ( 2 )

x + y = 56  => x = 56 - y

Substitute x in ( 2 )

7x - 3y = 12

7(56 - y) - 3y = 12

392 - 7y - 3y = 12

-10y =  12 - 392

-10y = - 380

y = 38

Substitute y in ( 1 )

x + y = 56

x + 38 = 56

x = 56 - 38

x = 18

Answer:

f(3) = 12

Step-by-step explanation:

f(3) = (3 x 2) + 24 - 12

     = 6 + 24 - 12

f(3) = 12

If this helps you, please give brainliest!

Answer:

Step-by-step explanation:

f(x) = [tex]x^{2}[/tex] + 24 - 12

substitute 3 inplace of x

f(3) = [tex]3^{2}[/tex] + 24 - 12

=9 + 24 - 12

21

If the question is f(x) = x2 + 24 - 12     {x*2 + 24 - 12}

now substitute 3 in place of x

f(3) = 3*2 + 24 - 12

=6 + 24 - 12

18

Answer:

27

Step-by-step explanation:

every 30 men = 9 men with beards

you have 30 3 times in 90 so you get 27

60÷2=30

18÷2=9

30 men normal = 9 men with beards

90÷30=3

3×9=27

Answer/Step-by-step explanation:

1.

✔️Coordinates of vertices ABC:

A(2, 2)

B(6, 2)

C(2, -1)

✔️AC = |2 - (-1)| = 3 units

AB = |2 - 6| = 4 units

2. Distance formula => [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Distance between B(6, 2) and C(2, -1):

[tex] BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Where,

[tex] B(6, 2) = (x_1, y_1) [/tex]

[tex] C(2, -1) = (x_2, y_2) [/tex]

[tex] BC = \sqrt{(2 - 6)^2 + (-1 - 2)^2} [/tex]

[tex] BC = \sqrt{(-4)^2 + (-3)^2} [/tex]

[tex] BC = \sqrt{16 + 9} = \sqrt{25} [/tex]

[tex] BC = 5 units [/tex]

Answer:

The person above me has the correct answer and solves it in the correct way.

Step-by-step explanation:

This is what I used as my answer though.

Distance Formula: d = √(x2-x1)^2 + (y2-y1)^2 

BC = √(x2-x1)^2 + (y2-y1)^2 

B = (6,2)

C = (2,-1)

BC = √(2-6)^2 + (-1-2)^2 

BC = √(-4)^2 + (-3)^2 

BC = √16+9

BC = √25

BC = 5

I can't understand tell me in english

Step-by-step explanation:

Derive an expression for the equivalent width in a saturated line. Assume a Voigt profile, with the difference in optical depth between the center of the line and the wings being ~104. The wings of the line can be ignored. Define a frequency x1 = (v1 − v0)/ΔvD, where the optical depth τv = 1. Inside of x1 the line is fully saturated, and outside x1 the line is optically thin. Show that the equivalent width is



Note that the equivalent width is practically insensitive to the number density of absorbing material.

Answer:

27.5 miles per gallon

1 full tank = 15.45 gallons

27.5 x 15.45 = 424.875 miles

rounded to the nearest 100th: 424.88 miles

nearest 10th: 424.9 miles

nearest whole #: 425 miles

Answer:

The monthly payment will be $ 162.50. In turn, the interest paid will be $ 33,750, constituting 69.23% of the total amount paid.

Step-by-step explanation:

Since there is a student loan of 15,000 at a fixed APR of 9% for 25 years, to calculate the monthly payment, determine the tiaras amount paid over the term of the loan, and determine, of the total amount paid, what percentage is paid toward the principal and what percentage is paid for interest, the following calculations must be performed:

((15,000 x 0.09) x 25) + 15,000 = X

33,750 + 15,000 = X

48,750 = X

48,750 / (25x12) = X

48,750 / 300 = X

162.5 = X

48,750 = 100

33,750 = X

33,750 x 100 / 48,750 = X

69.23 = X

Therefore, the monthly payment will be $ 162.50. In turn, the interest paid will be $ 33,750, constituting 69.23% of the total amount paid.

Answer:

46degrees

Step-by-step explanation:

From the question, we are told that both triangles are similar, hence;

<E = <S

<D = <R

<F = <T

From triangle DEF

<D + <F + <E = 180

Since <D = <F = 67

67 + 67 + <E = 180

134 + <E = 180

<E = 180 - 134

<E = 46degrees

Since <E = <S, hence the measure of <S  is 46degrees

2.) Find the zeros of the quadratic function y = x2 – 3x + 2 by factoring method.

[tex]\sf{Set\:y = 0. Thus, }[/tex]

[tex]\sf\rightarrow{0 = x2 – 3x + 2} [/tex]

[tex]\sf\rightarrow{0 = ( x – 2) ( x – 1)}[/tex]

[tex]\sf\rightarrow{x – 2 = 0 or x – 1 = 0} [/tex]

[tex]\sf{Then\:x = 2\:and\:x = 1}[/tex]

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