The percentage reduction can be written as 16.6667% of 300. 83.3333 percent decrease (%↓) or reduction from 300 is 50.
Answer:
83.33%
Step-by-step explanation:
300-50=250
250/300=83.33%
Description:- Note down postal pin code of your place where you reside. Take x times of last 2 digits of that pin code and add number of family members to it. Put it equal to your age and solve for x.
Answer:
x = 2/3
Step-by-step explanation:
The last two digit of postal code here is 12
We multiply this by x
so we have x * 12 = 12x
The number of family members is 6 ; and we are to equate it to my age which is 14
thus, we have the equation as;
12x + 6 = 14
12x = 14-6
12x = 8
x = 8/12
x = 2/3
30 points for 2 questions if you got the question correct I’m gonna give you brainlist
the girls heights in inches are as follows:62,70,60,63,66,what is their average height?
Answer:
Average height = 64.2 inches
Step-by-step explanation:
[tex]Average = \frac{sum \ of \ the \ values }{number \ of\ value}[/tex]
[tex]=\frac{62 + 70 + 60 + 63 + 66}{5}\\\\=\frac{321}{5}\\\\=64.2 \ inches[/tex]
The average of the given heights is 64.2 inches
What is an average?
An average of a list of data is the expression of the central value of a set of data. It is defined as the ratio of summation of all the data to the number of units present in the list.
According to the given problem,
Given data = { 62, 70, 60, 63, 66 }
Sum of the given heights = ( 62 + 70 + 60 + 63 + 66 )
= 321
Average = [tex]\frac{321}{5}[/tex]
= 64.2 inches
Hence, we can conclude, the average of the given data is 64.2 inches.
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The variable 100 POINTS!!!!
What is the value of 2 + (-2/3) ^2 ÷1/3 ?
16
3 1/3
-2
0
Answer:
second option is correct
The weight of three articles is 856 kg. If two of the articles weigh 502kg, what is 1/2 the weight of the third article?
Answer:
177 kg
Step-by-step explanation:
Find the weight of the third article by finding the difference between 502 and 856, since 856 kg is the total weight and 502 kg is the weight of the other 2 articles:
856 - 502
= 354
Now, find 1/2 of the weight, by dividing this by 2:
354/2
= 177
So, 1/2 the weight of the third article is 177 kg
If 1=3
2=3
3=5
4=4
5=4
Then, 6=?
9514 1404 393
Answer:
3
Step-by-step explanation:
For "a = b" it appears that the intention is b = f(a). It appears that f(a) is the number of letters in the spelling of 'a'.
"One" has 3 letters
"Two" has 3 letters
"Three" has 5 letters
"Four" has 4 letters
"Five" has 4 letters
"Six" has 3 letters
so, 6 = 3.
_____
Additional comment
This appears to be a non-standard use of the equal sign, in which it has no relation to the usual meaning of "equals." Using standard symbols with non-standard meanings should generally be avoided, unless the intended meaning is explained.
Which definition best describes vertical angles?
O A. A pair of angles whose sum is 180°
B. A pair of angles that combine to form a straight angle
C. A pair of angles whose sum is 90°
D. A pair of opposite angles formed by intersecting lines
SUBM
I need help again please!
Answer:
C = 28
Step-by-step explanation:
6/42 = 32-x/x
Answer:
C = 28
I hope this helped you
find the value of x in the given right triangle 90 20. please help!
Answer:
X = 3.6
Step-by-step explanation:
tan x = O/A
tan 20° = x/10
x = tan 20°(10)
x = 3.6
Answer:
x = 3.6 cm
Step-by-step explanation:
Using trigonometric ratios :
[tex]sin \theta = \frac{ opposite} {hypotenuse} \\\\cos \theta = \frac{adjacent }{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}\\\\[/tex]
[tex]where \ \theta = 20, \ opposite = x \ , hypotenuse = y \ , \ adjacent = 10cm[/tex]
[tex]we \ will \ take \ tan \ 20 , \ because\ we \ have \ to \ find \ opposite \ and \ adjacent \ is\ given.\\\\tan 20 = \frac{x}{10}\\\\x = 10 \times tan 20\\\\x = 10 \times 0.36397\\\\x = 3.6397\\\\x = 3.6 \ cm[/tex]
Sonya wants to sew ribbon along each side of a square pillow if the pillow has an area of 144 square inches, how much ribbon must she buy to have the exact amount that she needs
Answer:
48 inches
Step-by-step explanation:
The area of a square is given by
A = s^2 where s is the side length
144 = s^2
Taking the square root of each side
sqrt(144) = sqrt(s^2)
12 = s
The side length is 12
We want to find the perimeter to determine the amount of ribbon
P =4s
P =4*12
48 inches
Leona has a large bag of apples. There are 180 apples in the bag. She uses 14of the apples to make some juice. She uses 20% of the apples to make some pies. How many apples are left?
Answer:
132.8 are left enjoy
Determine the equation of the line perpendicular to y = 1/5x – 7 and passes through the point (-3,6).
Answer:
y = -5x - 9
Step-by-step explanation:
y = -5x + b
6 = -5(-3) + b
6 = 15 + b
b = -9
Please please help help please
Answer:
maybe the answer is equal. not sure.
Answer:
The answer is smaller
Step-by-step explanation:
because when we multiply two small ones we get a big one
Someone started fishing at 15.30 am after fishing for 2hours 15 min he rested for half an hour he then continued until 11am how long did he fish?
Answer:
7 Hours
Step-by-step explanation:
According to the Question,
Given, Someone started fishing at 3:30 am after fishing for 2hours 15min. he rested for half an hour(30min). Thus, Now The Clock is Rotating to 3:30 am + 2hour 15 min. + 30 min. = 6:15 am .He then continued doing Fishing until 11 am. As a result, he fished for 4 h 45 min. more after resting.
So the Total Time he Spends Fishing is 4 hour 45 min. + 2 hours 15 min.
7 hours
Pls give an actuel answer to this question. Thx :). WIll give brainest.
Answer:
47
Step-by-step explanation:
47
4 is 3 less than 7 so fits the requirement for the first part
47 reversed = 74
47 + 74 = 121
Answer:
47
So the number in the unit digit is x since it is unknown.
the number in the tens digit is 3 less than x which can be expressed as x-3.
we have to multiply x-3 by 10 since x-3 is supposed to represent the digit in the tens place. so we have 10(x-3)+x (we are adding x because in any number we always add the tens digit by the ones, for example, 13, 10 + 3)
the reverse number would instead be x in the tens place and (x-3) in the ones place so the equation would be 10x+(x-3)
10(x-3)+x + 10x+(x-3) is equal to 121.
distribute 10(x-3), 10x-30
10x - 30 + x +`10x+x-3
Add like terms, 10x+x and -30-3
11x-33+11x
11x+11x = 22x
so we have 22x-33=121
add 33 to both sides to isolate 22x
121+33= 154
22x=154, divide both sides by 22
154/22 = 7
x=7 but this is only the ones digit.
10(x-3)+x is the equation, so replace x with 7
10(7-3)+7
7-3 = 4 and 4*10 = 40
40 + 7 = 47
original number is 47
angad was thinking of a number. angad halves the number and gets an answer of 78.5. form an equation with x from the information
Answer:
157
Step-by-step explanation:
Let the number Angad was thinking be 'x'
Equation:-
1/2(x) = 78.5
x = 78.5(2)
x = 157
A rental car costs $36 for one day plus an additional $0.50 per mile. What is the cost of renting a car for two days and driving it a total of 100 miles?
Question Progress
Homework Progress
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Find the Lowest Common Multiple of 3, 5 and 6.
solve for the missing sidebof the triangle shown in the figure
Answer:
∠B = 74°
a ≈ 14.5 inches
c ≈ 11.4 inches
Step-by-step explanation:
The given parameters of triangle ΔABC are;
∠A = 62.2°, ∠C = 43.8° and side [tex]\overline{AB}[/tex] = b = 15.8 in
By sine rule, we have;
[tex]\dfrac{a}{sin(\angle A)} = \dfrac{b}{sin(\angle B)} = \dfrac{c}{sin(\angle C)}[/tex]
[tex]a = {sin(\angle A)} \times \dfrac{b}{sin(\angle B)}[/tex]
By angle sum property, we have;
∠B = 180° - (∠A + ∠C)
∴ ∠B = 180° - (62.2° + 43.8°) = 74°
∠B = 74°
[tex]\therefore {a} = {sin(62.2^{\circ})} \times \dfrac{15.8}{sin(74^{\circ})} \approx 14.5[/tex]
a ≈ 14.5 in.
[tex]c = {sin(\angle C)} \times \dfrac{b}{sin(\angle B)}[/tex]
[tex]\therefore {c} = {sin(43.8^{\circ})} \times \dfrac{15.8}{sin(74^{\circ})} \approx 11.4[/tex]
c ≈ 11.4 in.
3n^5 ÷ 6n^3, using properties of exponents
Answer:
Step-by-step explanation:
[tex]\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\frac{3n^{5}}{6n^{3}}=\frac{3}{6}*n^{5-3}\\\\=\frac{1}{2}n^{2}[/tex]
Answer:
[tex]\frac{n^{2} }{2}[/tex]
Step-by-step explanation:
Rewrite the division as a fraction.
[tex]\frac{3n^{5} }{6n^{3} }[/tex]
Cancel the common factor of 3 and 6.
[tex]\frac{3(n^{5}) }{6n^{3} }[/tex]
[tex]\frac{n^{5} }{2n^{3} }[/tex]
Cancel the common factor
[tex]\frac{n^{2} }{2}[/tex]
Hope this helps!
If you need more help with questions like these please reach out to me!
if G is the number of seconds that a traffic light says green and n is the average number of cars in each lane per light cycle, then the relationship would be G= 2.1n + 3.7
if the light stays green for 70 seconds then how many cars can cross the intersection in one cycle?
(linear equations)
Answer:
31.57 cars is the answer rounded to the hundredth, but since its cars you might want to put just 31 since half a car cant pass through. it depends on what your teacher wants really.
Step-by-step explanation:
70=2.1n+3.7
70-3.7=2.1n
66.3=2.1n
66.3/2.1=n
31.57=n
Someone PLEASE HELP ME. The diagram above shows a plan for a park.
ABCD is a rectangle.
APB and DQC are semicircles centred at X and Y.
Given AB = 7 cm and AC = 25 cm.
Calculate the perimeter of the park in cm.
Answer:
84 m
Step-by-step explanation:
Perimeter of the park = perimeter of rectangle + perimeter of 2 semicircles
62
ForEASY BRAINLIEST!!!
Answer:
A.
B.
C.
Answer:
A. x-3
B. x-14
C. x-10
Step-by-step explanation:
Answer: THXS FOR MAKIN THIS SO FRIKIN EASY. I think I may done b or c wrong-
Step-by-step explanation:
a) x - 3
b) x - 14
c) x − 10
Pls I beg someone to finish ALL of this :(. I’ve stayed up all night to do this but I couldn’t figure all of them out. Pls pls pls!!! ill mark you brainliest n I can give you a thank you such as 5 Stars in return. Please take your time and I hope you all have a amazing day!
Answer:
Question 1: 75 minutes
Question 2: 4:07
Question 3: 30 minutes
Question 4: 8:35
Step-by-step explanation:
An hour is sixty minutes; that's the key to solving these questions.
The time basketball was played is 75 minutes or 1 hour 15 minutes
The time I get home is at 4:07
The cook was cooked for 30 minutes.
The cheerleading was over at 8:35.
What is unit conversion?It is the conversion of one unit to another unit with its standard conversion.
We have,
Trey and Na Asia played basketball from 10:30 - 11:45.
From 10 to 11 we have 60 minutes.
= 60 minutes - 30 minutes [10:30] + 45 minutes [ 11:45]
= 105 minutes - 30 minutes
= 75 minutes
The time basketball was played.
= 75 minutes
= 1 hour 15 minutes
I left school at 3:15 on the bus. I got home 52 minutes later.
1 hour = 52 minutes
= 3:15 + 52 minutes
= 3 + 15 minutes + 52 minutes
= 3 + 67 minutes
= 3 + 1 hour + 7 minutes
= 4:07
The time I get home is at 4:07
Antavious makes Macaroni and cheese. He begins making it at 6:35 and finished at 7:05.
= 6:35 to 7:05
From 6 to 7 we have 60 minutes.
So,
= 60 minutes - 35 minutes [6:35] + 5 minutes [7:05]
= 65 minutes - 35 minutes
= 30 minutes
The cook was cooked for 30 minutes.
Makhiya and Madison went to cheerleading at 7:15. It was over 1 hour and 20 minutes later.
= 7:15 + 1 hour + 20 minutes
= 7 + 15 minutes + 1 hour + 20 minutes
= 8 + 35 minutes
= 8:35
The cheerleading was over at 8:35.
Thus,
The time basketball was played is 75 minutes or 1 hour 15 minutes
The time I get home is at 4:07
The cook was cooked for 30 minutes.
The cheerleading was over at 8:35.
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Help I’m stuck!!!! Solve the equation below for x. Enter your answer as a fraction in lowes
terms, using the slash mark (/) as the fraction bar. 4/21 + 2/9
X=
Answer:
26/63
Step-by-step explanation:
Try to make the denominators equal so that you can add them:
4(3)/21(3)= 12/63
2(7)/9(7)= 14/63
And now you add, which will give you:
12/63 + 14/63= 26/63
f(x) = 6r + 2
g(x) = - 5x - 9
Find the product of F and G.
which one is the smallest 4/5 1/6 2/3 1/5
Answer:1/6
Step-by-step explanation:
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\mathsf{\dfrac{4}{5}=\boxed{\bf 0.80\ or\ 80\%}}\\\\\\\mathsf{\dfrac{1}{6}=\boxed{\bf 0.166667\ or\ 16.6667\% }}\\\\\\\mathsf{\dfrac{2}{3}=\boxed{\bf 0.666667\ or \ 66.6667\%}}\\\\\\\mathsf{\dfrac{1}{5}=\boxed{\bf 0.20\ or \ 20\%}}[/tex]
[tex]\large\textsf{After converting the fractions to decimals and percentages, we can}\\\large\textsf{now out them from descending (least) to ascending (greatest) order}\\\large\textsf{to determine your result to this question}[/tex]
[tex]\boxed{\mathsf{\dfrac{1}{6}, \ \dfrac{1}{5}, \ \dfrac{2}{3}, \& \ \dfrac{4}{5}}}[/tex]
[tex]\large\textsf{The SMALLEST one out of your set is: }\boxed{\mathsf{\bf \dfrac{1}{6}}}\large\checkmark[/tex]
[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{1}{6}}}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
The perpendicular room is 4m long, 3m wide and 2.5m high. They tiled and painted the interior walls of the room. How many square meters of tiles should be used? Answer only
Answer:
12m²
Step-by-step explanation:
are the files to be used only for the floor, or also for the walls ? ceiling ?
if it is only for the floor, then the height of the room is irrelevant.
perpendicular clearly stands here for rectangular.
so, the good of the room is a rectangle of 4m length and 3m width.
the area of a rectangle is length×width.
area = 4×3 = 12m²
so, 12m² of tiles will be needed (in reality there would be at least 10% to 20% added for bad tiles, wrong cuts, ...).
if walls need to be included, then you will have to add the areas of 4 more rectangles of length×height.
which would be 2 times 3×2.5 = 7.5m² and 2 times 4×2.5 = 10m².
so, the total area incl. walls would be
12 + 7.5 + 7.5 + 10 + 10 = 47m²
if the ceiling has to be included too, then you need to add the area of another rectangle of the same size as the floor.
so, that total would then be
47 + 12 = 59m².
please hurry i want the answer of this question please
B
Please mark me as a brainlist
Answer:
900
Step-by-step explanation:
3²×5 = 45
3×2²×5² = 300
LCM = 900
Hope this helps... pls vote as brainliest
When the park opened for the day, four people were in attendance. Every hour, the number of people tripled from the previous hour's attendance.
Part A: Determine the common ratio between the attendance each hour.
Part B: Write an equation that can be used to determine the attendance for the nth hour the park is open.
Part C: How many people were at the park during the second, fifth, and eighth hours the park was open? Show all work.