Answer:
D.
Explanation:
Tempered glass is the less expensive alternative, and is best for lower temperature applications. It can withstand constant temperatures of up to 470 degrees F. Tempered glass is regular glass that has been strengthened through a thermal or chemical treatment. Tempering not only strengthens the glass but also changes its breakage pattern, causing it to shatter into small pieces instead of large sharp angles, reducing the chance of injury. It is best used for applications where the fire will not be near the glass, as constant temperatures of 500 degrees or more will cause it to weaken and shatter.
A block slides down a rough ramp with a 30-degree incline as shown.
Which diagram represents the forces acting on the block?
Answer:
Image 4 ?
Explanation:
Answer:
Image 4
Explanation:
Took Test
During a spacewalk, an astronaut lets go of a tool, causing it to float away and bounce off the side of the space shuttle. The astronaut saw the the tool hit the shuttle but did not hear it hit the shuttle. Why would the astronaut be able to see the tool hit the shuttle but not hear it hit the shuttle?
A.
Neither sound waves nor light waves can travel through a vacuum.
B.
Sound waves can not travel through a vacuum but light waves can.
C.
Both sound waves and light waves can travel through a vacuum.
D.
Light waves can not travel through a vacuum but sound waves can.
Answer:
B mate
Explanation:
Which statements describe why organisms are classified? Check all that apply.
Answer:
what are the options for me
What two types of motion are the same in which they both are under the influence of gravity?
Answer:
Orbit and Gravity
Explanation:
May I have brainliest please I would appreciate it! Have a great day!
One particle has a charge of 4.2 x 10-°C, while another particle has a charge
of 1.10 10-9 C. If the two particles are separated by 0.005 m, what is the
electromagnetic force between them? The equation for Coulomb's law is
F = kongs, and the constant, k, equals 9.00 x 10°Nm2/C2
Answer:
1.66*10^-3N
Explanation:
Yodelin has fifty quarters and dimes. Their total value is $9.80. Which of these systems of equations can be used to find the number of quarters (q) and
dimes (d) Yodelin has?
Answer:
q + d = 50
25q + 10d = 980
Explanation:
The equation that can be employed to determine the number of quarters(q), as well as, dimes(d) that Yodelin has would be:
q + d = 50...(1)
25q + 10d = 980...(2)
Multiplying (1) by 25
25q + 25d = 1250 ...(3)
25q + 10d = 980...(4)
subtracting (4) from (3)
15d = 270
d = 18
q = 50 - 18
= 32
The system of the equations could be
q + d = 50
25q + 10d = 980
Calculation of the equation and the number of quarters and dimes:Since Yodelin has fifty quarters and dimes. Their total value is $9.80.
So here the equations be
q + d = 50...(1)
25q + 10d = 980...(2)
Now we have to Multiplying (1) by 25
So,
25q + 25d = 1250 ...(3)
25q + 10d = 980...(4)
Now
subtracting (4) from (3)
15d = 270
d = 18
So,
q = 50 - 18
= 32
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12. Describe Binding energy and how it plays a role in nuclear fusion up to 56Fe (the synthesis of iron
nuclei). Include a description of the relationship between the strong nuclear force, the
electromagnetic force, and the number of nucleons involved in the fusion in your answer.
Help me on thiss one once again ughh ! asap ! hurry
A motorbike reaches a speed of 20 m/s over 60m, whilst
accelerating at 3m/s?, determine the bike's initial speed.
Initial speed = 2√10 m/s
Further explanationLinear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
An equation of uniformly accelerated motion
V = vo + at
Vt² = vo² + 2a (x-xo)
x = distance on t
vo / vi = initial speed
vt / vf = speed on t / final speed
a = acceleration
vf=20 m/s
d = 60 m
a = 3 m/s²
[tex]\tt vf^2=vi^2+2.ad\\\\20^2=vi^2+2\times 3\times 60\\\\400=vi^2+360\\\\40=vi^2\\\\vi=\sqrt{40}=2\sqrt{10}~m/s[/tex]
A water skier is towing by motorboat at a constant velocity of magnitude 15 km /h. The boat speed up, and after a short interval the skier is towed at a new constant velocity of magnitude 20 km/h. What is the net force on the skier when she is moving at 15 km/h? And at 20 km/h?
Answer:
The skier is experimenting a net force of 0 newtons in both cases. ([tex]v_{1} = 15\,\frac{km}{h}[/tex], [tex]v_{2} = 20\,\frac{km}{h}[/tex])
Explanation:
According to Newton's First Law, an object is in equilibrium when it is either at rest or moving at constant velocity, which means that net force is equal to 0 newtons.
Therefore, the skier is experimenting a net force of 0 newtons in both cases.
A long jumper leaves the ground at an angle of 25 degrees with respect to the horizontal with a resultant velocity of 30 ft/s. What was the horizontal velocity of the jumper at takeoff? What was the vertical velocity at takeoff? How high did the COM rise above the point of takeoff?
Answer:
The horizontal component of the velocity is 27.19 ft/s
The vertical component of the velocity at takeoff is 12.68 ft/s
The vertical distance traveled by the jumper is 8.2 ft
Explanation:
Given;
angle of projection or takeoff, θ = 25°
the resultant velocity, v = 30 ft/s
The horizontal component of the velocity is given by;
[tex]v_x = vcos \theta\\\\v_x = 30 * cos(25)\\\\v_x = 27.19 \ ft/s[/tex]
The vertical component of the velocity at takeoff is given by;
[tex]v_y = vsin \theta\\\\v_y = 30 * sin(25)\\\\v_y = 12.68 \ ft/s[/tex]
The vertical distance traveled by the jumper is given by;
[tex]v_y_f^2 = v_y_o^2 +2(-g)h\\\\v_y_f^2 = v_y_o^2 -2gh\\\\0 = 12.68^2 - (2*9.8)h\\\\0 = 160.78 - 19.6h\\\\19.6h = 160.78\\\\h = \frac{160.78}{19.6}\\\\ h = 8.2 \ ft[/tex]
Radiation transfers thermal energy through _________. Which accurately completes the statement? waves
direct contact
particles
liquid movement
Answer:
waves
Explanation:
The correct word that completes the statement is that radiation transfers thermal energy in the form of waves. So, option A is correct.
What is Radiation?Radiation is the movement of atomic and subatomic atoms as well as waves, like those that define X-rays, heat rays, and light rays. Radiation of both types, from cosmic and earthly sources, is constantly being thrown at all matter. The qualities and behavior of radiation, as well as the matter it interacts with, are outlined in this article, which also explains how energy is transmitted from radiation to its environment.
The effects of such an energy conversion to living things are given a lot of consideration, including how many aspects of life—such as photosynthesis in plants and sight in animals—are affected normally as well as any abnormal or harmful effects that may arise from exposing organisms to radiation of unusual types or to radiation doses that are higher than those found in nature.
Therefore, in radiation, the energy transfer through waves.
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The chart shows data for four different moving objects.
A 3 column table with 4 rows. The first column is labeled object with entries W, X, Y, Z. The second column is labeled mass in kilograms with entries 10, 18, 14 and 30. The last column is labeled velocity in meters per second with entries 8, 3, 6, 4.
Which shows the order of the objects’ kinetic energies, from least to greatest?
W, Y, X, Z
Z, X, Y, W
W, Y, Z, X
X, Z, Y, W
Answer: X, Z, Y, W.
Explanation: From the formula the velocity is squared which means it can have a significant impact on kinetic energy, thus the higher the velocity the higher the kinetic energy. The kinetic energy is also impacted by the mass of a body, such that the higher the mass the higher the kinetic energy.
Answer:
D
Explanation:took the test
Which describes what happens when fuel is ignited in a heat engine?
Chemical energy is converted into thermal energy.
Thermal energy is converted into solar energy.
Solar energy is converted into chemical energy.
O Thermal energy is converted into chemical energy.
Answer:
A
Explanation:
a car ends up at x = -245 m after a displacement of -103 m. what was its initial position?
Answer:
-142m
Explanation:
To find the initial position of the car, we can add the displacement.
-245 + 103 = -142
Best of Luck!
What is the coefficient of friction of an object with a weight of 300 N and a force of friction of 150 N?
1
0.75
.5
0
Answer:
0.5
Explanation:
Given parameters:
Weight of object = 300N
Force of friction = 150N
Unknown:
Coefficient of friction = ?
Solution:
Frictional force is a force that resists the motion of a body.
It is mathematically expressed as;
frictional force = uN
Where u is the coefficient of friction
N = Normal force = weight of the object
Now input the parameters and find u;
150 = u x 300
u = [tex]\frac{150}{300}[/tex] = 0.5
The coefficient of friction here is 0.5
In the qualifying round of the 50-yd freestyle in the sectional swimming championship, Dugan got an early lead by finishing the first 25.00 yd in 10.01 seconds. Dugan finished the return leg (25.00 yd distance) in 10.22 seconds. Determine Dugan's average velocity for the entire race. Number only, round to the nearest hundredth.
Answer:
v = 0
Explanation:
Given that,
Total distance is 50 yards
Dugan got an early lead by finishing the first 25.00 yd in 10.01 seconds
Dugan finished the return leg (25.00 yd distance) in 10.22 seconds.
We need to find Dugan's average velocity for the entire race. As he returns at the initial position. As a result, the net displacement is equal to 0. So,
Average velocity = net displacement/time
v = 0
Hence, his average velocity for the entire race is 0.
If a racer maintained a constant speed, during which sections of the race would the racer's velocity be the same?
Sections 1 and 2
Sections 2 and 3
Sections 2 and 4
Sections 3 and 4
pls help!!
Answer:
Sections 3 and 4
Explanation:
The correct answer would be sections 3 and 4.
The velocity of an object is the speed of the object in a particular direction. In this case, the speed of the racer is constant irrespective of the distance or the direction. Hence, the sections of the race during which the racer's velocity would be the same would be the sections in which the racer faces the same direction - which is sections 3 and 4.
How many meters did the car go in the first 4 seconds?
Choose the scientific theories that have been disproved through scientific advancement. Select all that apply.
a) steady-state theory
b) theory of evolution
c) big bang theory
d) geocentric universe
e) phrenology
Describe a way to separate a mixture of fine sand and table salt without having to directly sort tiny crystals using tweezers.
Answer:
you can add water to the mixture and dissolve the salt
The method used is by solubility which is dissolving the sand and salt mixture into water and heating.
This is just about methods of separations of mixtures.
There are three major methods that can be used to separate a mixture of sand from salt. They are;
- Physical separation by use of magnifying glass and tweezers.
- Dissolving the mixture in water
- Melting the salt
The first method can't be used because we are told to use another method.
In that case, we will use the second option which involves solubility.Now, salt is made up of sodium chloride which means it is an ionic compound and it will be soluble in water whereas sand is not soluble in water as it contains mainly silicon dioxide.
Now, the process involved in this separation is as follows;- Pour the mixture into a container.
- Add water to the mixture in the container.
- Turn on a burner and heat this solution in the container till the salt has dissolved completely.
- Then after that, turn of the burner and allow the heated solution to cool off a bit.
- After it has cooled a bit, pour the salt solution on top into another empty container.
- Then collect the sand out of the heated container.
- Then heat the salt solution until the water dries and only the salt is left.
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Alguien ayudeme con estos problemas de fisica porfa 1. Una persona recorre 4200 m en 25 minutos, luego 4.54 Km en un hora y finalmente 9000 m en 55 minutos. Halle, el tiempo total empleado en minutos, su velocidad y rapidez. 2. Una partícula en una circunferencia de 40 cm de diámetro da 30 vueltas completas en dos minutos. Halle la velocidad y rapidez de la partícula. 3. Una persona da 500 pasos de 40 cm al oeste, luego 400 pasos de 35 cm al norte y finalmente 300 pasos de 30 cm al este utilizando en total 2 min y 120 segundos. Halle la distancia recorrida, desplazamiento, velocidad y rapidez. 4. Una persona recorre una pista circular de 250 metros de radio, ¿Cuál es su distancia, desplazamiento, velocidad y rapidez en dar media vuelta a la pista si el tiempo empleado es de 90 segundos
Answer:
1) t_total = 140 min , v = 126.7 m / min , 2) v = 0.628 m / s ,
3) v = 0.592 m / s , θ = -39.3 º
Explanation:
Here we have some short kinematics problems
1) d₁ = 4200 m at T1 = 25 min
d₂ = 4.54 km at t2 = 1 h
d₃ = 9000 m at t3 = 55 min
of the statement the direction of each route is the same
Let's reduce the distances to the SI system
d₂ = 4.54 km (1000 m / 1 km) = 4540 m
t₂ = 1 h (60 min / 1 h) = 60 min
Total time is
t_total = t1 + t2 + t3
t_total = 25 + 60 +55
t_total = 140 min
the distance is
d_total = 4200 + 4540 +9000
d_total = 17740 m
with movement it is in one dimension and all displacement is in the same direction, distance equals displacement.
Speed is
v = 17740/140
v = 126.7 m / min
in the direction of travel
Speed is the modulus of speed
| v | = 126.7 m / min
2) the angular velocity is
w = θ / t
In this exercise
t = 2 min (60 s / 1min) = 120 s
θ = 30 rev (2π rad / 1 rev) = 60π rad
w = 60π / 120
w = 1.57 rad / s
linear velocity is
v = w r
v = 1.57 0.40
v = 0.628 m / s
velocity is the speed tangential to the trajectory
3) the data for this exercise are
distance = (number of steps) (distance of one step)
d₁ = 500 0.40 m = 200 m West
d₂ = 400 0.35 m = 140 m North
d₃ = 300 0.30 m = 90 m East
in a total time of t = 2 min and 120 s
t = 2 60 + 120 = 240 s
the distance traveled is
x axis we assume the direction towards + x (East) positive
x_total = d₃ -d₁
x_total = 90-200 = -110 m
y axis
y_total = d₂
y_total = 140 m
we use the Pythagorean theorem to find the distance0
D = √ (x_total² + y_total²)
D = √ (110² + 90²)
D = 142.13 m
The speed is
v = D / t
v = 142.13 / 240
v = 0.592 m / s
speed is
v = 0592 m / s
tan θ = Y / X
θ = tan -1 y / x
θ = tan -1 (90 / (- 110))
θ = -39.3 º
4) This angle is measured on the positive side of the x axis in a clockwise direction
θ = 1.5 rev (2π rad / 1 rev) = 3π rad
t = 90 s
the angular velocity is
w = θ / t
w = 3πi / 90
w = 0.1047 rad / s
the speed is
v = w R
v = 0.14047 250
v = 26.17 m / s
velocity is tangent to path
Five mL of ethanol has a mass of 3.9 g, and 5.0 mL of benzene has a mass of 44 g. Which liquid is denser?
Answer:
Benzene
Explanation:
A denser substance will have a higher or larger mass in the same volume. Therfore benzene will be a denser liquid as the mass is bigger in the same volume compared to ethonal.
You can also work this out by using the density formula which is mass of the substance over the unit of volume.
Which is a physical property of matter that is always the same regardless of size or amount
Answer:
ntensive properties: A physical property that will be the same regardless of the amount of matter.
Explanation:
lily took 57 seconds to walk from schoolroom to library. if the distance between the classroom and library was 38m, at what average speed did lily walk in m/min?
Answer:
7mph
Explanation:
a tennis ball is thrown straight up with an initial velocity of 22.5 m/s how much total time is the ball in the air
Answer:
4.6s
Explanation:
v=u+at
0=22.5+(-9.8)t
-22.5=-9.8t
t=-22.5/-9.8
t=2.295 s
The total time will double
2.295×2=4.59s
=4.6s
What made the Fertile Crescent a good place for growing crops
Answer:
The Fertile Crescent was good for farming because of the fertility of its land, a result of irrigation from numerous large rivers in the region.
Explanation:
A 5 Kg mass has an initial speed of 5m/s. After 3 sec, it has come to a speed of 70 m/s.
a. What is the acceleration of the mass?
b. What net force is acting on the mass during those 3 seconds?
Answer:
a
[tex]a = 21.7 \ m/s^2[/tex]
b
[tex]F = 108.5 \ N[/tex]
Explanation:
From the question we told that
The mass is m = 5 kg
The initial speed [tex]u = 5 m/s[/tex]
The time taken to attain [tex]v = 70 \ m/s[/tex] is t = 3 s
Generally from kinematic equation we have that
[tex]v = u + at[/tex]
=> [tex]70 = 5 + a * 3[/tex]
=> [tex]a = 21.7 \ m/s^2[/tex]
Generally the force acting is mathematically represented
[tex]F = m * a[/tex]
=> [tex]F = 5 * 21.7[/tex]
=> [tex]F = 108.5 \ N[/tex]
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In Video 2, you observed a "Frictionless Pendulum", the frictionless pendulum can only be simulated. Go back and see if you can observe any changes in motion. How would the motion of the pendulum change if that was a demonstration rather than a simulation? Use the CER (claim, evidence, reasoning) template to answer.
CLAIM: Write your answer to the question given: The motion of a real pendulum would ______________________ (describe how it would or would not change).
EVIDENCE: This is your example, model, observation, or idea demonstrating your claim, you could begin with “According to…” or “Based on...”, or "Watch how..."
REASONING: You could begin with, “This is because…” or “The fact that supports this evidence is…”. ONLY state science facts to support your example, do not guess, use opinion, or use inferences here.
Answer:
When the mass is drawn upwards and let go, the force of gravity accelerates it,
Explanation:
if you send me the video i can give you a better answer its just hard without seeing it
If you poke a hole into a plastic bottle, and stick a straw in it, and then let the straw connect to a glass cup, and then blow a balloon and stick it on the top of the mouth of the bottle, we will measure how long it takes for the water to move from the plastic bottle to a cup.
Will a larger bottle size increase or decrease how fast water goes from the plastic bottle to the cup?
How Can the human ear detect the sound
Answer:
Sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.
Explanation:
The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.