Answer:
Radiation therapy uses high-energy particles or waves, such as x-rays, gamma rays, electron beams, or protons, to destroy or damage cancer cells.Hope that helps
The decomposition of H2O2 is a first-order reaction given by the formula: Rate = k [H2O2]1. How would the reaction rate be affected if the H2O2 concentration were double its original value?
Answer: The decomposition of H₂O₂ is a first-order reaction. Then, the reaction rate will be 2 times the original rate, if we double its concentration value.
Explanation: To find the answer, we need to know about the decomposition of H₂O₂.
What is the rate of reaction, if we double the concentration of H₂O₂?We have the equation of decomposition of H₂O₂ as,2H₂O₂→ 2 H₂O+ O₂
We have given that, the equation of reaction rate of the first order reaction as,Rate = k [H₂O₂]1
As we know that the equation of reaction rate is,Rate = rate constant × concentration of [H₂O₂]
Thus, by comparing both the equations, we get,rate constant=k and the concentration of [H₂O₂] = 1[H₂O₂].
Given that the concentration is doubled. Then the expression for rate will be,Rate = 2k [H₂O₂].
Thus, we can conclude that the rate of reaction will be 2 times the initial rate if we double the concentration.
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If we double the concentration value, the reaction rate will be twice as fast as before.
In order to determine the solution, we must understand how H2O2 breaks down.
If we double the concentration of H2O2, what will happen to the reaction rate?The formula for the breakdown of H2O2 is,2H₂O₂→ 2 H₂O+ O₂
We have provided the first order reaction's reaction rate equation as,Rate = [H2O2] k
As we are aware, the reaction rate equation isRate = rate constant × [H2O2] concentration
As a result, by comparing the two equations, we obtain, rate constant is k, and the [H2O2] concentration is 1 [H2O2].The concentration has doubled as a result. Afterward, the rate expression will be,Rate = [H2O2] 2k.
As a result, we can infer that doubling the concentration will cause the reaction rate to double.
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To lower the risk of a collision, you should keep at least __________ of space to one side of your vehicle at all times.
One must keep one car width of space to side of vehicle to avoid collision.
What is collision?
Collision is the sudden striking of two bodies that exerts forces on each other thus acelerating the objects in relatively very short time. One must maintain atleast one car width of space to side of vehicle to lower the risk of collision. If the space is lower than one car width than you should lower the speed of car to avoid collision.
One can also follow the two second disciple to avoid collision. According to this rule, the car should maintain two second safe distance behind any other vehicle .It acts as a safety buffer or defensive mechanism to avoid the risk of collision at all times at any speed. Also according to impulse momentum change theorem, the force on each object can be minimized by maintaing more distance. As force and time are inversely proportional in collision.
Therefore, one car width distance is the safest minimum distance to avoid risks of collision .
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During World War II, the United States government forced thousands of _____ to be relocated to internment camps.
Answer:
Japanese Americans
Explanation:
prevented them from buying land and sent them back to japan after the war
hope this helps :)
Answer:
Japanese Americans
Explanation:
Since Japan was helping the Axis, the United States were afraid that if Japan attacked the Continental United States, then Japanese Americans would help them.
This fear led to the government placing Japanese Americans in internment camps.
The path of a charged particle moving parallel to a uniform magnetic field will be a:______.
The path of a charged particle moving parallel to a uniform magnetic field will be straight line
Force on a charged particle moving in a magnetic field can be calculated by = q.(v*B )
q = charge of the particle
v = velocity of the particle
B = magnetic field
theta = angle between v and B
q . (v B sin (theta) )
Since, particle is parallel to the magnetic field
hence , theta = 0°
so sin(theta) = sin 0° = 0
hence , force = 0
since , there is no force acting on the particle it will remain in that motion in hat it was when it initially came in the magnetic field . Hence It will be moving along a straight line path because the magnetic force on the charged particle is zero.
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A mass m is attached to an ideal massless spring. When this system is set in motion, it has a period t. What is the period if the mass is doubled to 2m?.
The period is √2 *T if the mass is doubled to 2m.
What is the time period?
The time period is the length of time during which an activity occurs or a condition remains.
The equation for the period T is given as:
[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]
where k is the spring constant
mass of the system = m
Here,
If the mass id doubled to 2m for the system that is set in motion,
new mass is now 2m
So the equation for time period becomes,
[tex]T' = 2\pi \sqrt{\frac{2m}{k} }[/tex]
[tex]T' = \sqrt{2} * 2\pi \sqrt{\frac{m}{k} }[/tex]
[tex]T' = \sqrt{2}* T[/tex]
Hence,
The period is √2 *T if the mass is doubled to 2m.
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A loop rests in the plane of a page of textbook while a magnetic field is directed into the page. A clockwise current is induced.
(b) when the magnetic field gets stronger.
correct option :
When a loop rest in the plane of the page and magnetic field is directed into the page then we will apply here right hand thumb rule in which thumb represent the direction of magnetic field and curling fingers represent direction of induced current. So, in this case the direction of magnetic field is into the page and curling fingers shows induced current in clockwise direction.
Thus, option (b) is correct.
Incorrect options:
option (A) is incorrect because when magnetic field will change
according to flux.
option (C) is incorrect because field is stronger so it does not matter
size of loop increases or decreases.
option (D) is incorrect because it moves any other side the field will be
stronger.
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[Your question is incomplete, but most probably your full question was-Check all that apply:
A. when the magnetic field is tilted so it is no longer perpendicular to the page
B. when the magnetic field gets stronger
C. when the size of the loop decreases
D. when the loop is moved sideways across the page]
Select the correct answers. which two pieces of information show that a research source is reliable?\
Answer:
2
Explanation:
just took the assignment
A 67 V power supply is connected to three identical resistors in series. If the current through the resistors is measured at 0.95 A, what is the value of each resistor? Round your answer to 2 decimal places.
The value of the identical resistors would be 70. 53 Ohms
How to determine the valuesWe have the formula for resistance to be;
Resistance = Voltage/ current
Voltage = 67 V
Current = 0. 95A
Substitute the values
Resistance =
[tex] \frac{67}{0.95} [/tex]
Resistance = 70.53 Ohms
Thus, the value of the identical resistors would be 70. 53 Ohms
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Frank and Lisa are analyzing the chart, which shows the speed at which light travels through different media.
Frank is correct because light travels through diamond at the slowest speed, and speed and frequency have an inverse relationship .
Lisa is correct because light travels through air at the fastest speed of ,and speed and frequency have a direct relationship .
Neither Frank nor Lisa is correct because light does not change frequency when it travels through different media .
Both Frank and Lisa are correct because light has both inverse and a direct relationship with frequency ,depending on the type of media .
Neither of the two is correct because light does not change frequency when it travels through different media .
Disclaimer :The question given on the portal is incomplete .Here is the complete question .
Question :Frank and Lisa are analyzing the chart, which shows the speed at which light travels through different media. Frank says that light travels through diamond with the greatest frequency. Lisa says that light travels through air with the greatest frequency. Which best describes the accuracy of these statements?
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A tank, shaped like a cone has height 6 meters and base radius 5 meters long. It is placed so that the circular part is upward. It is full of water, and we have to pump it all out by a pipe that is always leveled at the surface of the water. Assume that a cubic meter of water weighs 10 000 N , i.e. the density of water is 10000 N m 3 . How much work does it require to pump all water out of the tank
The work required to pump out the liquid is 2.35 MJ.
What is work?
Work can be defined as the scalar product of the force and the displacement.
The formula to calculate the work done W is,
[tex]W=F.d[/tex]
where F is the force and d is the displacement.
Note: It is assumed that the weight of one cubic unit of the liquid is [tex]10000 \text{ N/m}^3[/tex].
Break down the vertical tank into parallel disc elements whose thickness is dh and are located at a height h from the ground. The radius of the element at height h is r.
It is given that the height of the tank is 6 m and the base radius is 5 meters. Using these, the ratio of the radius r at height h to the height h by using the triangle similarity criterion is,
[tex]\frac{h}{r}=\frac{6}{5} \\ r=\frac{5h}{6}[/tex]
Using the above value of r, the volume of the element is given by,
[tex]V= \pi r^2dh\\V=\pi (\frac{5h}{6})^2dh\\V= \frac{25\pi h^2}{36} dh[/tex]
The weight of the volume element is the force required.
The weight of one cubic unit of the liquid is [tex]10000 \text{ N/m}^3[/tex].
So the weight F of the volume element at height h is given by,
[tex]F=10000 (\frac{25 \pi h^2}{ 36})dh\\F= 6944.44\pi h^2dh[/tex]
At the height h, the difference in the height of the top of the tank and the volume element is (6-h). So the work required to pump out the volume of liquid at height h is given by the integrating the equation,
[tex]W=6944.44\pi\int\limits^6_0 {(6h^2-h^3)} \, dx \\\\W=69.44\pi \left[ 2h^3-\frac{h^4}{4}\right]^6_0\\W=2,.35\times10^6\text{ J}[/tex]
The value of the W obtained is 2.35*10^6 J or 2.35 MJ.
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What mass will accelerate at 3 m/s² when a net force of 150 N acts on it?
Answer:
[tex]\huge\boxed{\sf m = 50\ kg}[/tex]
Explanation:
Given data:Acceleration = a = 3 m/s²
Force = F = 150 N
Required:Mass = m = ?
Formula:F = ma
Solution:Put the givens in the formula
150 = m (3)
Divide 3 to both sides
150/3 = m
50 kg = m
m = 50 kg
[tex]\rule[225]{225}{2}[/tex]
A 75.0-kg man standing on a bathroom scale in an elevator. Calculate the scale in N, reading if the elevator moves upward at a constant speed of 1.5 m/s
A 75.0-kg man standing on a bathroom scale in an elevator, if the elevator moves upward at a constant speed of 1.5 m/s then the scale in N will be 885N accordance with Newton's law
The extent of the force being applied downward. If the human is selected to be the system of interest with a free-body diagram, the one-dimensional problem appears to be considerably more difficult. Both sections (a) and (b) of this example's analysis can be answered by analyzing the free-body diagram in accordance with Newton's laws, along with some other potential problems. In order to determine what the scale reads, the only forces operating on the subject are his weight w and the upward force of the scale, which are equal in strength and directed in opposing directions. Newton's law, as usual, can be used to do this.
F=Ma = F−w=ma⇒F=m(a+g)=75(2+9.8)=885 N.
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In a circuit consisting of two lamps connected in series, if the current in one lamp is 1 a, what is the current in the other lamp?
The current in the second lamp will also be 1amp seeing that the connection is a series connection.
See the explanation bellow.
What is circuit in series?The simple rule of a series connection is such that for each load, the current flowing is the same and the resistance varies across the loads.
However, the reverse is the case for a parallel circuit connection, where the current varies and the resistance is the same for each circuit element.
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Answer the following regarding Momentum Change and Force
1. Find the force necessary to gain a velocity of 60 m s-1 within 5 minutes, when acted on a mass of 200 kg which is initially at rest.
2. A force of 150 N acts on an object of mass 600 kg for 2 minutes, which was initially at rest. Find the velocity gained by the object at the end of the second minute.
The force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
Force of the objectF = mv/t
where;
m is mass of the object = 200 kgv is velocity of the object = 60 m/st is time of motion = 5 mins = 300 secondsF = (200 x 60)/(300)
F = 40 N
Velocity of the objectF = mv/t
Ft = mv
v = Ft/m
where;
m is mass = 600 kgF is force = 150 Nt is time = 2 mins = 120 sv = (150 x 120)/(600)
v = 30 m/s
Thus, the force necessary to gain the velocity is 40 N.
The velocity gained by the object at the end of the second minute is 30 m/s.
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A 2.50 × 105 w motor is used for 26.4 s to pull a boat straight toward shore. how far does the boat move toward shore if a force of 4.20 × 104 n is applied by the motor? 157 m 1,590 m 1.11 × 106 m 6.60 × 106 m
The distance travelled by the boat towards shore if a force of 4.20x10⁴N is applied is 157.14 m.
Power is a unit of measurement for the amount of work completed in a particular period of time; it may be computed using both work and time. Divide the amount of work by the length of time it takes to do the work to find power. The unit of work is the joule. The unit of power measurement is known as joules of work per second.
The power of the motor = 2.50x10⁵ W
= 2.50x10⁵ N m/s
The time it takes to pull the boat = 26.4 s
The force applied = 4.20x10⁴ N
Using the formula;
[tex]d = \frac{Pt}{F}[/tex]
where,
P = Power
t = Time taken
F = Force applied
d = Distance travelled
The distance traveled by the boat = 2.50x10⁵ N m /s (26.4 s) /(4.20x10⁴ N)
=157.14 m
Therefore, the distance travelled by the boat if a force of 4.20x10⁴N is applied is 157.14 m.
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A parallel plate capacitor fully charged to voltage V is connected to the battery (the voltage on the plates remains fixed). If the plates are pulled away from each other, how would it affect the charge on the capacitor
Charge will decreases.
A parallel plate capacitor when it is fully charged to voltage V is given as:
C = Q/V
The capacitance of parallel plate capacitor with two plates of Area A separated by distance d and no dielectric material between plates is
C = ε₀ A /d
since from above equation it shows C is proportional to Q and also C is inversely proportional to distance d.
So, ATQ when d increases C will decrease which in result decreases charge on the capacitor.
Thus, Charge will decrease.
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An ideal ammeter would have zero resistance while an ideal voltmeter would have infinite resistance, why?.
Answer: An ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance. Similarly, an ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter.
Explanation: To find the answer, we need to know about the Ammeter and Voltmeter.
What is an ammeter?An ammeter is a device, that can be used to measure the electric current flows through a circuit in amperes.An ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance when it is connected in series to measure the current.What is voltmeter?A voltmeter is a device, that can be used to measure the electric potential difference generated between the terminals of an electric circuit in volts.An ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter, when it is connected in parallel to measure the voltage.Thus, we can conclude that, an ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance. Similarly, an ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter.
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Two harmonic waves traveling in opposite directions interfere to produce a standing wave described by y
The wavelength of the interfering waves is 3.14 m.
Calculation:The general equation of a standing wave is given by:
y = 2A sin (kx) cos (ωt) ......(1)
The given equation represents the standing wave produced by the interference of two harmonic waves:
y = 3 sin (2x) cos 5t .......(2)
Comparing equations (1) and (2):
k = 2
We know that,
k = 2π/λ
λ = 2π/k
λ = 2 (3.14)/ 2
λ = 3.14 m
Therefore, the wavelength of the interfering waves is 3.14 m.
I understand the question you are looking for is this:
Two harmonic waves traveling in opposite directions interfere to produce a standing wave described by y = 3 sin (2x) cos 5t where x is in m and t is in s. What is the wavelength of the interfering waves?
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How does the fur of the polar bear help it to live in the arctic region?
Answer:
It has 2 uses
1. Polar bears have white fur so that they can camouflage into their environment. Their coat is so well camouflaged in Arctic environments that it can sometimes pass as a snow drift.
2. They have a thick layer of body fat, which keeps them warm while swimming, and a double-layered coat that insulates them from the cold Arctic air.
Cindy's eye exam reveals that the reason she cannot get a sharp focus is that she has ___, an uneven curvature of the cornea or lens that prevents a sharp focus of an image on her retina.
Answer: Cindy's eye exam reveals that the reason she cannot get a sharp focus is that she has Astigmatism, an uneven curvature of the cornea or lens that prevents a sharp focus of an image on her retina.
Explanation: To find answer, we need to know more about the Astigmatism.
What is astigmatism?It is the defect of vision in which a person cannot simultaneously see both the vertical and horizontal views of an object with the same clarity.It is due to the irregular curvature of cornea, or the lens prevents a sharp focus of an image on retina.It can be corrected using a cylindrical lens.Thus, from the above explanation, we can conclude that, the reason she cannot get a sharp vision is due to Astigmatism.
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When driving on a highway, sudden strong cross wind gusts: Select one: a. Do not affect a car as much as a strong head wind b. Affect large cars more than small cars c. Always cause severe dust problems d. Can move a car sideways into another lane
When driving on a highway, sudden strong cross wind gusts move a car sideways into another lane (option D).
What is a crosswind?A crosswind is a wind blowing across a line of travel.
Accidents have been reported to be caused by strong winds and can cause heavy distractions that will cause the driver to lose control.
However, a strong and sudden crosswind will cause the car to move sideways into another lane, and can lead to severe accident.
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A drop of oil is floating between two parallel plates with a separation of 8.3 mm. If the mass of the oil drop is 2.7 x 10-15 kg, and its charge is -9.612 x 10-19 C, determine the voltage across the charged plates and determine which plate is positive.
The voltage across the charged plates is 228.5 V.
Voltage across the platesV = Fd/q
V = (mgd)/q
where;
m is mass of the oilg is acceleration due to gravityd is the distance of separationq is chargeV = (2.7 x 10⁻¹⁵ x 9.8 x 8.3 x 10⁻³) / (9.612 x 10⁻¹⁹)
V = 228.5 V
Thus, the voltage across the charged plates is 228.5 V.
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A person performs a bench press. The bar's mass is 40 kg. When this person's arms are extended, the bar is 0.6 m above the starting point. How much work did the person do to push the bar off his chest to full extension of his arms
The work done by the person is 235.2 J.
Work done by the person
The work done by the person is calculated as follows;
W = mgh
where;
m is mass of the barheight through which the bar is raisedW = 40 x 9.8 x 0.6
W = 235.2 J
Thus, the work done by the person is 235.2 J.
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A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward. If the velocity at the bottom of the drop is 10.0 m/s and the mass of the cart and passengers is 3.5 x 104 kg, how much potential energy was converted into thermal energy (heat)
The energies which is converted into thermal energy is
2280.9 × 10^4 J
According to the question when the ride will go upward then there will a potential energy acquired and when it comes down then kinetic energy starts to increase. since, the ride is starting from rest then kinetic energy will be maximum at lowest. So, now we will calculate P.E and K.E at various points.
Potential Energy at top when the vertical drop is 126.5 m is given as- P.E = m ×g× h
= 3.5 × 10^4 × 9.8 × 126.5
= 4338.95 × 10^4 J
Kinetic Energy at bottom when ride has velocity of 10 m/s then it is
given as -
K.E = 1/2 mv²
= 1/2 × 3.5×10^4 × 10²
= 175 × 10^4 J
Now the energy which converted to thermal energy is given as:
Thermal energy = Potential energy - kinetic energy
= 2455.9 × 10^4 - 175 × 10^4
= 2280.9 × 10^4 J
Thus, the ride Potential energy was converted to thermal energy is 2280.9 × 10^4 J.
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A transformer usefully transfers 190,000 W of the 200,000 W of energy supplied to it. How efficient is the transformer?
an object has a mass of 50kg, a final height of 20m and an initial height of 8m. what is the amount of work done
amount of work done is 5880 J
Given:
mass of object = 50kg
Final height = 20m
initial height = 8m
To Find:
amount of work done
Solution:
work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
The work done by gravity is given by the formula,
W = mgh
W = 50 x 9.8 x ( 20-8)
= 5880 J
So the work done is 5880 J
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A multidimensional database (MDDB) is a type of database in which data can be viewed from multiple dimensions; commonly used with ____.
A multidimensional database (MDDB) is a type of database in which data can be viewed from multiple dimensions; commonly used with MOLAP.
A multidimensional database offers the capacity to swiftly process records and generates answers quickly. MDBs allow customers ask questions about agencies' operations and traits.
The multidimensional databases employ MOLAP (multidimensional on line analytical processing) to get entry to its records. They allow the customers to speedy get solutions to their requests through producing and studying the information as a substitute speedy. The information in multidimensional databases is saved in a statistics dice layout.
In a dimensional database, you've got rows and columns, represented by way of X and Y. In a multidimensional database, you've got were given X, Y, Z, etc. depending on the number of dimensions to your statistics. below is an example of a 3-Dimensional information Array represented in a relational desk and in three-D.
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A car increases its speed from 30 km/h to 60 km/h in 5 seconds. Its acceleration
Answer:6km/sec
Explanation: Acceleration = Change in velocity / Time
Change in velocity = 60km/h minus 30km/hr
Time = 5seconds
Which of the following is correct? Multiple Choice When AP is rising, MC is falling, and when AP is falling, MC is rising. When MP is rising, MC is falling, and when MP is falling, MC is rising. There is no relationship between MP and MC. When MP is rising, MC is rising, and when MP is falling, MC is falling.
The statement which is correct is that when MP is rising MC is falling, and when MP is falling MC is rising and is denoted as option B.
What is MP?This is referred to as marginal product and is referred as the extra output derived as result of additional inputs.
MC on the other hand is known as marginal cost and they have an inverse relationship such that when MP is rising , MC is falling and vice versa thereby making it the most appropriate choice.
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Rolls of aluminum foil are 304-mm wide and 0.016-mm thick. what is the maximum length of aluminum foil that can be made from 1.10-kg of aluminum, al? density of al = 2.70 g/cm3
Answer:
See below
Explanation:
The units in this question need to be all the same
Volume = L x W x H where 'H' is thickness of the foil
1.10 kg = 1100 g
The volume given = mass / density = 1100 g / 2.70 g/cm^3= 407.407 cm^3
304 mm = 30.4 cm .016 mm = .0016 cm
LWH = L * 30.4 cm * .0016 cm = 407.407 cm^3
L = 8375.97 cm = 83.76 meters
The maximum length of aluminum foil that can be made from 1.10-kg of aluminum would be 87.76 meters.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
By using the above formula for density
ρ = mass / volume
As given in the problem Rolls of aluminum foil are 304 mm wide and 0.016-mm thick.
the mass of the aluminum = 1.10-kg
mass = 1100 grams
the density of the aluminum = 2.70 g/cm3
density = 17/3
2.70 g/cm3 = 1100 grams /volume
volume = 1100/ 2.70
=407.40 cm3
volume = width×thickness×length
407.40 cm3 = 30.4 ×.0016 ×length
length = 8375.97 cm
= 87.76 meters
Thus, the maximum length of aluminum foil that can be made from 1.10-kg of aluminum would be 87.76 meters.
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