which is larger
8/k^2+2 and k^2+2

There are 238 passengers in the plane in 2010

The given parameters are:

Weight = 150 pounds and Passenger = 270 --- Year 2000

Weight = 170 pounds --- Year 2010

Represent the parameters using the following inverse proportion

Weight * Passenger= Fixed

So, we have:

150 * 270 = 170 * Passenger

Divide both sides by 170

150 * 270/170 = Passenger

Evaluate

238 = Passenger

Rewrite as

Passenger = 238

Hence, there are 238 passengers in the plane in 2010

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The volume of the figure to the nearest whole number = 756π m³.

The figure shown exists composed of a cone and a cylinder.

The volume of the figure = volume of cone + volume of the cylinder

Height of cone = 12 - 8 = 4

Radius (r) of cone = 18/2 = 9 m

The volume of the cone V = 1/3hπr²

= 1/3 [tex]*[/tex] 4π [tex]*[/tex] 9² = 108π

The volume of the Cylinder = πr²h

radius (r) = 18/2 = 9 m

height (h) = 8 m

Volume of cylinder = π [tex]*[/tex] 9² [tex]*[/tex] 8 = 648π m³

Volume of the figure = 108π + 648π = 756π

The volume of the figure to the nearest whole number = 756π m³.

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Answer:

I didn't got the question well

The given differential equation has characteristic equation

[tex]r^5 - 4r^4 + 4r^3 - r^2 + 4r - 4 = 0[/tex]

Solve for the roots [tex]r[/tex].

[tex]r^3 (r^2 - 4r + 4) - (r^2 - 4r + 4) = 0[/tex]

[tex](r^3 - 1) (r^2 - 4r + 4) = 0[/tex]

[tex](r^3 - 1) (r - 2)^2 = 0[/tex]

[tex]r^3 - 1 = 0 \text{ or } (r-2)^2=0[/tex]

The first case has the three cubic roots of 1 as its roots,

[tex]r^3 = 1 = 1e^{i0} \implies r = 1^{1/3} e^{i(0+2\pi k)/3} \text{ for } k\in\{0,1,2\} \\\\ \implies r = 1e^{i0} = 1 \text{ or } r = 1e^{i2\pi/3} = -\dfrac{1+i\sqrt3}2 \text{ or } r = 1e^{i4\pi/3} = -\dfrac{1-i\sqrt3}2[/tex]

while the other case has a repeated root of

[tex](r-2)^2 = 0 \implies r = 2[/tex]

Hence the characteristic solution to the ODE is

[tex]y_c = C_1 e^x + C_2 e^{-(1+i\sqrt3)/2\,x} + C_3 e^{-(1-i\sqrt3)/2\,x} + C_4e^{2x} + C_5xe^{2x}[/tex]

Using Euler's identity

[tex]e^{ix} = \cos(x) + i \sin(x)[/tex]

we can reduce the complex exponential terms to

[tex]e^{-(1\pm i\sqrt3)/2\,x} = e^{-x/2} \left(\cos\left(\dfrac{\sqrt3}2x\right) \pm i \sin\left(\dfrac{\sqrt3}2x\right)\right)[/tex]

and thus simplify [tex]y_c[/tex] to

[tex]y_c = C_1 e^x + C_2 e^{-x/2} \cos\left(\dfrac{\sqrt3}2x\right) + C_3 e^{-x/2} \sin\left(\dfrac{\sqrt3}2x\right) \\ ~~~~~~~~ + C_3 e^{-(1-i\sqrt3)/2\,x} + C_4e^{2x} + C_5xe^{2x}[/tex]

For the non-homogeneous ODE, consider the constant particular solution

[tex]y_p = A[/tex]

whose derivatives all vanish. Substituting this into the ODE gives

[tex]-4A = 69 \implies A = -\dfrac{69}4[/tex]

and so the general solution to the ODE is

[tex]y = -\dfrac{69}4 + C_1 e^x + C_2 e^{-x/2} \cos\left(\dfrac{\sqrt3}2x\right) + C_3 e^{-x/2} \sin\left(\dfrac{\sqrt3}2x\right) \\ ~~~~~~~~ + C_3 e^{-(1-i\sqrt3)/2\,x} + C_4e^{2x} + C_5xe^{2x}[/tex]

Answer:

you have to put the formula of perimeter

Answer:

12a. L+8m + 14m

12b. 10m+8m +14m

12c. 66

12d.420m

12e.252m

quick questions

volume= 288cm cubed

Answer:

2

Step-by-step explanation:

[tex]\frac{3[2(-2)-6] + (-2)^{2} +4[2(-2)+1]}{3[(-2)-5]+2}[/tex]

[tex]\frac{3(-10) - 4 + 4(-3)}{-16}[/tex]

[tex]\frac{-30-4-12}{-16}[/tex]

[tex]\frac{-46}{-16}[/tex]

okay you know what i dont know what im doing but i know the answer is for sure 2..

Answer:

-4

Step-by-step explanation:

in order to get from -6 to 24, you need to multiply x by -4 since -6* -4 is 24

Answer: 4

Step-by-step explanation:

[tex]1102_{3}=2+0(3)+1(9)+1(27)=38\\\\212_{n}=2+1(n)+2(n^2)=2n^2 + n+2\\\\\implies 2n^2 + n+2=38\\\\2n^2 + n-36=0\\\\(n-4)(2n+9)=0\\\\n=-\frac{9}{2}, 4[/tex]

However, as the base must be positive, n=4.

The amount that the insurance company will pay is $1800.

It should be noted that the insurance company will pay John for the expenses of his injuries and repair of the car.

For the injury, he will get:

= $500 + ($1400 - $100)

= $500 + $2300

= $1800

Therefore, the amount is $1800.

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The centre and the radius of the circle is (-7, -1) and 6 units

The equation of the circle in standard from is expressed as:

x^2+y^2+2gx+2fy+C = 0

where;

(-g, -f) is the centre

r= √g²+f²-C

Given the equation below

x^2+y^2+14x+2y+14 = 0

2g = 14

g = 7

2f = 2

f =1

Hence the centre of the circle is (-7, -1)

Radius = √49+1-14

Radius = √36 = 6 units

Hence the centre and the radius of the circle is (-7, -1) and 6 units

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The height of candle 4 is twice that of candle B after 2.4 hours.

For candle, A time is taken for 100% bearning=4hour.

For 1 hour, it burns for 25%(100/4)

After 1 hr.[tex]\frac{25}{100}[/tex]

After x hours, the amount burnt[tex]=\frac{x}{4}[/tex]

Amount left[tex]=1-\frac{x}{4} =\frac{4-x}{4}[/tex]

Let's not presume that candle B's height will be half that of candle A after x hours.

After x hours, part vemacing [tex]=1-\frac{x}{3} =\frac{3-x}{3}[/tex]

[tex]\frac{4-x}{4} =1\frac{3-x}{3}[/tex]

Height of candle A[tex]=2[/tex]×Height of candle B.

[tex]12-3x=24-8x[/tex]

   ⇒[tex]5x=12[/tex]

        [tex]x=\frac{12}{5}[/tex]

           [tex]=2.4[/tex]

The height of candle 4 is twice that of candle B after 2.4 hours.

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The first car consumed 25 gallons of fuel while the second car consumed 30 gallons of fuel.

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the first car consumption and y represent the second car consumption, hence:

x + y = 55   (1)

Also:

15x + 20y = 975   (2)

From both equations:

x = 25, y = 30

The first car consumed 25 gallons of fuel while the second car consumed 30 gallons of fuel.

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The electricity that is used, on average, by a security system in 2 years is 4.3Kw.

The average power consumption of the security system given is 2.7 watt.

(a) Electricity consumption in 2 years

in KW-h = (24*365*2.7)/1000 = 4.304 KWh

(b) As per US data CO2 emissions = 0.99 pound per kilowatt-h.

Hence here CO2 emissions = 4.3 × 0.99 = 4.2610 pounds / KW-h.

= 4.3 pound / KW-h.

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Answer:

[tex]f(x) = 20x - 4 \\ substitute \: y \: for \: f(x) \\ y = 20x - 4 \\ interchange \: x \: and \: y \\ x = 20y - 4 \\ swap \: the \: sides \: of \: the \: equation \\ 20y - 4 = x \\ move \: the \: constant \: to \: the \: right \: hand \\ 20y = x + 4 \\ divide \: both \: sides \: by \: 20 \\ y = \frac{1}{20} x + \frac{1}{5} \\ substitute \: f {}^{ - 1} (x) \: for \: y \\ f {}^{ - 1} (x) = \frac{1}{20} x + \frac{1}{5} [/tex]

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

Thus, domain of f(x): x∈R = range of f¯¹(x)

and range of f(x): x∈R =domain of f¯¹(x)

Answer:

Second option

Step-by-step explanation:

The range is the set of output values a function can take. As shown in the table, as x is substituted in, y is the corresponding value.

Answer:

top left graph

Step-by-step explanation:

The function is not defined for negative x.

Also, the range should not include positive numbers.

So, the answer is the top left graph.

The equation of the parabola is [tex]y=\frac{1}{24} x^2+3[/tex]

None of the given options is correct

Given:

Focus: (0, 3)

Directrix: y = -3

Note that:

f - k = k - (-3)

f - 3 = 3 + 3

f = 6 + 3

f = 9

The equation of the parabola is of the form:

[tex]y=\frac{1}{4(f-k)} (x-h)^2+k[/tex]

Substitute f = 9, k = 3, h = 0 into the equation

[tex]y=\frac{1}{24} (x-0)^2+3\\\\y=\frac{1}{24}x^2+3[/tex]

The equation of the parabola is [tex]y=\frac{1}{24} x^2+3[/tex]

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Answer:

0.7

Step-by-step explanation:

Because 0.4 is $5 and 0.3 is $25. So 0.3+0.4=0.7

Answer:

122,599

Step-by-step explanation:

In words, what I am is asking is 17.7% of what number is 21,700.  I will need to change 17.7% to a decimal.  To do that, I move the decimal 2 places to the left.  Then solve.

.177 x w = 21700  Divide both sides by .177

w = 122,599

Answer:

Step-by-step explanation:

ascxne rdsjazs bcbnnnncccd

Based on the angles of a + b and b + c, the value of b can be calculated to be 40°.

As this is a triangle, all the internal angles must add up to 180°.

This means that:

a + b + c = 180°

As we have the value of b + c, this becomes:

a + 100 = 180

a = 80°

b is therefore:

a + b = 120

80 + b = 120

b = 120 - 80

= 40 °

Full question is:

If in triangle abc, angle a + angle b= 120° and angle b + angle c = 100°, then find angle b.

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The area of the desktop is 12. 5 feet square

The formula for area of a rectangle;

Area = length × width

Length = 2. 5 feet

Width = 5 feet

Area = 2. 5 × 5

Area = 12. 5 feet square

Thus, the area of the desktop is 12. 5 feet square

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Using the binomial distribution, we have that:

a) There is a 0.2111 = 21.11% probability that a six will occur exactly twice.

b) The expected number of sixes is of 3.2.

c) The variance of the number of sixes is of 2.35.

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

For this problem, the parameters are given by:

p = 8/30 = 0.2667, n = 12.

Item a:

The probability is P(X = 2), hence;

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{12,2}.(0.2667)^{2}.(1-0.2667)^{10} = 0.2111[/tex]

Item b:

The expected number of the binomial distribution is:

E(X) = np.

Hence:

E(X) = 12 x 8/30 = 3.2.

Item c:

The variance of the binomial distribution is:

V(X) = np(1-p).

Hence:

E(X) = 12 x 8/30 x 22/30 = 2.35.

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answer : 2 1/2

divide y by x

divide  2 1/2 by 1

its 2 1/2

10 divided by 4 is also

2 1/2

17 1/2 divided by 7 is also

2 1/2

Using the Poisson distribution, we have that:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

For this problem, the mean is given as follows:

[tex]\mu = 13[/tex]

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859[/tex]

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0[/tex]

[tex]P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003[/tex]

[tex]P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019[/tex]

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

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The solution set that represent the solution to the inequality is (16,+infinity)

The mathematical representation of the statement given is expressed as shown below;

4 1/2 x - 9 1/2 >62.5

Convert to improper fraction to have:

9/2 x - 19/2 > 62.5

Find the LCM

9x-19/2 > 62.5

9x-19 > 125

9x > 125 + 19

9x > 144

x > 16

Hence the solution set that represent the solution to the inequality is (16,+infinity)

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Answer:

12u²

Step-by-step explanation:

area of a regular quadrilateral is always base x vertical height.

the base here is clearly 4 (just count the squares)

draw an imaginary line connecting the bottom right corner to the line before the top right corner (the line should be vertical)

count the squares here too and you get 3.

so the area = 3 x 4,

the area is 12u²

Applying the triangle sum theorem, we have:

First angle measure = 35°

Second angle = 70°

Third angle = 75°

According to the triangle sum theorem, all angles in a triangle will give a sum of 180 degrees.

First angle measure = x

Second angle = 2x

Third angle = (2x + x) - 30 = 3x - 30

x + 2x + 3x - 30 = 180 [triangle sum theorem]

6x - 30 = 180

6x = 180 + 30

6x = 210

x = 210/6

x = 35

First angle measure = x = 35°

Second angle = 2x = 2(35) = 70°

Third angle = 3x - 30 = 3(35) - 30 = 75°

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Answer:

0.6

Step-by-step explanation:

Given what we know, we can set up a proportion to convert 1,056 yards into miles

[tex]\frac{1760 yd}{1mi} =\frac{1056 yd}{x mi} \\\\1760x=1056\\\\x=0.6[/tex]