Write a math expression for total number of sticks in one pack of red sticks and one pack of blue sticks. There’s 8 red in a pack and 12 blue in a pack.

Answer:

C

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]40 - 10g[/tex]

Rewrite 40 as 4 × 10

[tex]4 \times 10 - 10g[/tex]

Factor out 10

[tex]10(4 - g)[/tex]

Answer:

y=1/3x+10.5

Step-by-step explanation:

y=mx+b, the equation of the parallel line is  y=1/3x+1/2. So we know the slope is 1/3 and all we need is the Y intercept (b). We can find that manually with arithmetic because we know the slope. It turns out to be 10.5

We know that :

The sum of two angles that are complementary = 90°

Smaller angle = x

Larger angle = 2x

We can make the formula as

= 2x + x = 90°

= 3x = 90°

= x = 90 ÷ 3

= x = 30

The smaller angle = x = 30°

The larger angle = 2x = 30 × 2 = 60°

Therefore , the measure of each of the angles are 30° and 60° .

Answer:

Tom wants to go to disneyland this weekend with 23 adults including himself and 4 children Ashley 3, Leslie 1, Brit 4, Victor 2. Children under the age of 6 pay "x" amount while anyone older pay "y" amount. What equation can tom use to find out how much the tickets in total will be.

Step-by-step explanation:

Y = Adults pay y amount - There are 23 adults

X =kids under 6 pay x amount - there are 4 children

4x+23y

4 (kids under 6 ticket cost)+ 23 (Adults ticket cost)

Answer:

(4x - 3)(x-2) = 0

Step-by-step explanation:

             4x² - 11x + 6 = 0

        To factorize this equation,

        -11

     4x6

These numbers are the key to the solution:

   find two numbers whose sum is -11 and the product is + 24 (4 x 6)

   So, the numbers are -3 and -8

    4x² - 8x - 3x + 6 = 0

   4x(x -2) - 3(x - 2) = 0

    (4x - 3)(x-2) = 0

Answer:

(4x - 3)(x - 2) = 0

That's your answer!!

Answer:

The 99% confidence interval is  [tex] 403.33 <  \mu < 462.67 [/tex]  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  =  100

   The sample mean is  [tex]\= x = 433[/tex]

    The standard deviation is [tex]\sigma = 115[/tex]

From the question we are told the confidence level is  99% , hence the level of significance is    

      [tex]\alpha = (100 - 99 ) \%[/tex]

=>   [tex]\alpha = 0.01[/tex]

Generally from the normal distribution table the critical value  of  [tex]\frac{\alpha }{2}[/tex] is  

   [tex]Z_{\frac{\alpha }{2} } =  2.58[/tex]

Generally the margin of error is mathematically represented as  

      [tex]E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }[/tex]

=>   [tex]E = 2.58 *  \frac{115 }{\sqrt{100} }[/tex]

=>   [tex]E = 29.67 [/tex]

Generally 99% confidence interval is mathematically represented as  

      [tex]\= x -E <  \mu <  \=x  +E[/tex]

=>    [tex]433 -29.67 <  \mu < 433 + 29.67[/tex]    

=>    [tex] 403.33 <  \mu < 462.67 [/tex]  

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 [tex]\mu_{\hat p}= p[/tex]

The standard deviation of this sampling distribution of sample proportion is:

 [tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]

(a)

The sample selected is of size n = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

[tex]\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204[/tex]

So, the sampling distribution of sample proportion is [tex]\hat p\sim N(0.75,0.0204^{2})[/tex].

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

[tex]P(p-0.04<\hat p<p+0.04)=P(\frac{-0.04}{0.0204}<\frac{\hat p-p}{\sigma_{\hat p}}<\frac{0.04}{0.0204})[/tex]

                                          [tex]=P(-1.96<Z<196)\\=P(Z<1.96)-P(Z<-1.96)\\=0.975-0.025\\=0.95[/tex]

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size n = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

[tex]\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306[/tex]

So, the sampling distribution of sample proportion is [tex]\hat p\sim N(0.75,0.0306^{2})[/tex].

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

[tex]P(p-0.04<\hat p<p+0.04)=P(\frac{-0.04}{0.0306}<\frac{\hat p-p}{\sigma_{\hat p}}<\frac{0.04}{0.0306})[/tex]

                                          [tex]=P(-1.31<Z<196)\\=P(Z<1.31)-P(Z<-1.96)\\=0.9049-0.0951\\=0.8098\\\approx 0.81[/tex]

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

Answer:

the answer is d because 0.978 cool number like yaaaa.

Step-by-step explanation:

Answer:

2.99

Step-by-step explanation:

1.) 2 goes into 5 2 times. So the 2 goes on top of the division sign

2.) 2x2=4

3.) Move 4 below 5

4.) Subtract 5-4=1

5.) Bring down 9

6.) 2 Goes into 19 9 times

7.) 2x9=18

8.) 19-18=1

9.) Bring down the 7

10.) 2 Goes into 17 8 times

11.) 2x8= 16

12.) 17-16=1

13.) Add a zero onto the end, bring down that zero

14.) 2 goes into 10 5 times.

15.) Round answer to 2.99 because with money you only have two decimals

Answer:

no

Step-by-step explanation:

Answer:

96

Step-by-step explanation:

144/12= 12 ( each hour)

12( times)  8=96

Since they got 144 for 12 hours you have to divide the hours by the money to get the amount earned ever hour so you divide the total amount by the  hour then use the information you got and then you multiply the amount of money by 8

Answer:

2

Step-by-step explanation:

2

Answer:

25,428 this was a peice of pie

Step-by-step explanation:

Answer: 53

Step-by-step explanation: I just woke up I’m too tired to explain

Answer:

y = 2/3x + 1/2

Step-by-step explanation:

First, make the equation into a slope-intercept form:

2y + 3x = 1

2y = -3x + 1

y = -1.5x + 0.5

You can make it into a fraction:

y = -3/2x + 1/2

Now here's the equation:

y = 2/3x + 1/2

Hope this helps!

Let me know if I'm wrong :)

Answer:

200 minutes

Step-by-step explanation:

So we know that the speed is 92 km/h for the first car and 68 km/h for the second car. We do not know the time, but we do know that we need to convert it into minutes. The time for both cars would be x/60. Now we multiply speed by time and get distance. The first car would be 92 x/60 and the second would be 68 x/60, now we cross multiply and make an equation. 92x/60 - 68x/60 = 80, 24x = 80, x=200 minutes.

Answer:

Pi is a irrational number

Step-by-step explanation:

Pi is an irrational number because it never ends it keeps going on and one.

Pi is also 3.141592654.............. never ends

Answer:

I don’t think it’s neither less than it equal

Step-by-step explanation:

I could be wrong don’t listen to me :)

Answer: 27.688

Step-by-step explanation:

The critical chi-square value [tex]\chi^2_{(df,\alpha)}[/tex] depends on significance level ([tex]\alpha[/tex])  and degrees of freedom (df) .

Given significance level: ([tex]\alpha[/tex]) = 1% = 0.01

Degrees of freedom (df)= 13

From the chi-square table, the critical chi-square value for df = 13 and [tex]\alpha =0.01[/tex]

is [tex]\chi^2_{(df,\alpha)}=27.688[/tex]

Hence, the  required critical value = 27.688

Answer:

[tex]d = 5\sqrt{13}[/tex]

Step-by-step explanation:

Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Simply plug in the 2 coordinates into the distance formula to find distance d:

[tex]d = \sqrt{(-20-(-35))^2+(15-25)^2}[/tex]

[tex]d = \sqrt{(-20+35)^2+(-10)^2}[/tex]

[tex]d = \sqrt{(15)^2+100}[/tex]

[tex]d = \sqrt{225+100}[/tex]

[tex]d = \sqrt{325}[/tex]

[tex]d = 5\sqrt{13}[/tex]

Answer:

the answer is D

Step-by-step explanation:

hahahaha wht? lol sry im stupid tbh

Answer:

(x+5, y-2)

Step-by-step explanation:

Move right 5 units and moves down 2 units

The experiment is messed up. Business and rental drivers are usually much more careful in their driving patterns because the car isn't theirs. They are usually adults, experienced drivers who don't put themselves into risky driving situations. =  Speeding, cutting off others etc.. It also didn't tell how  much the cars were driven. There may have been a down turn in the economy and thus less business driving and same with the rentals. If they were used less after the installation then the study wasn't really valid. What was the price of gas before and after the instillation. Who did the study? Did the  previous testers have any reason to skew the study? Did they own stock in the third light business?  Was it the same people who did the study before who did the study afterwords? What was the average age of the drivers before and after? The study group may have aged and calmed down a bit more? What were the technology changes that occurred about the same time? Anti skid brakes, better material and tread designs for the tires, what about the design of the gages and their lighting.  How about the window styles and size..larger windows mean better view and potentially less accidents. What were the safety aspects of the cars before compared to the cars after, were they the same makes and Models or did the rental and business learn that certain cars were safer than others and move to the safer Models? so many variables to consider but did the tester consider them all-probably not. Random studies study only a certain percentage of the total. Who's to say the second random study didn't get less experienced drivers to study? All good what ifs'.