Answer:
$47.60
Step-by-step explanation:
[tex]18+\frac{148}{5} =47.60[/tex] ($)
If a number is chosen at random from the numbers 1 to
20 inclusive, what is the probability that a single-digit
number will be picked? ( give your answer in simplified
fractions eg. 2/5 when necessary)
Answer:
1/20
Step-by-step explanation:
only a single number can be chosen out of 20. And 1/20 is the most simplified it can get.
The figure is a parallelogram. One diagonal measures 28 units.
A parallelogram is shown. It has side lengths 21, 20, 21, and 20. The length of a diagonal is 28.
Is the figure a rectangle? Explain.
Answer:
It is not a rectangle
Step-by-step explanation:
A rectangle is a shape with 4 sides, such that we have two pairs of parallel sides, where the length of the parallel sides is equal.
so we have two parallel sides with length L and two parallel sides with length L'.
In this figure ,we can see two sides with length 20 and other two with length 21, and this is a rectangle only if the sides meet at 90°degree angles (this would mean that the opposite sides are parallel)
To see this, we can think that the triangle formed by the diagonal and two sides is a triangle rectangle, then using the Pythagorean theorem we should have that:
20^2 + 21^2 = 28^2
841 = 784
So this is not a triangle rectangle, meaning that the angle between the side of 20 and the side of 21 is not a right triangle, then the figure is not a rectangle.
Therefore, it is not a rectangle
Hope u understand
Please mark the brainliest
Thank You
Which of the following sets of numbers could not represent the three sides of a right triangle?
Answer:
25, 32, 40 can not form a right angle triangle.
Step-by-step explanation:
By Pythagoras theorem,
⇒ (40)² = (25)² + (32)²
⇒ 1600 = 625 + 1024
⇒ 1600 ≠ 1689
Answer:
option b
Step-by-step explanation:
according to the pythagoras theorem to be right angled triangle the sum of square of two smaller sides must be equal to the square of hypotenuse.
so ,
20 and 21 are smaller sides and hypotenuse be 29
pythagoras theorem
a^2 + b^2 = c^2
20^2 + 21^2 = 29^2
400 + 441 = 841
841 = 841 (since both sides are equal it forms right angled triangle)
25 and 32 are smaller sides and 40 be hypotenuse
a^2 + b^2 = c^2
25^2 + 32^2 = 40^2
625 + 1024 = 1600
1649 = 1600 (both sides are not equal so it does not form right angle triangle)
30 and 72 are smaller sides whereas 78 is hypotenuse
a^2 + b^2 = c^2
30^2 + 72^2 = 78^2
900 + 5184 = 6084
6084 = 6084 (since both sides are equal it forms right angled triangle )
32 and 60 are smaller sides and 68 is hypotenuse
a^2 + b^2 = c^2
32^2 + 60^2 = 68^2
1024 + 3600 = 4624
4624 = 4624 (since both sides are equal it forms right angled triangle )
Which of following equations have a solution y = 8. A:4y + 3 = 32. B:6 + 5y = 46. C:9y ÷ 4 = 8. D:10y ÷ 4 = 20. E:65 - 3y = 27
A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two dice and recorded the larger number out of the two dice. Simulate this scenario (use 10000 long columns) and answer questions 10 to 13.
Answer:
(10) Person B
(11) Person B
(12) [tex]P(5\ or\ 6) = 60\%[/tex]
(13) Person B
Step-by-step explanation:
Given
Person A [tex]\to[/tex] 5 coins (records the outcome of Heads)
Person [tex]\to[/tex] Rolls 2 dice (recorded the larger number)
Person A
First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)
Next, we list out all number of heads in each roll (sorted)
[tex]Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}[/tex]
[tex]n(Head) = 32[/tex]
Person B
First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)
Next, we list out the highest in each toss (sorted)
[tex]Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}[/tex]
[tex]n(Dice) = 30[/tex]
Question 10: Who is likely to get number 5
From person A list of outcomes, the proportion of 5 is:
[tex]Pr(5) = \frac{n(5)}{n(Head)}[/tex]
[tex]Pr(5) = \frac{1}{32}[/tex]
[tex]Pr(5) = 0.03125[/tex]
From person B list of outcomes, the proportion of 5 is:
[tex]Pr(5) = \frac{n(5)}{n(Dice)}[/tex]
[tex]Pr(5) = \frac{8}{30}[/tex]
[tex]Pr(5) = 0.267[/tex]
From the above calculations: [tex]0.267 > 0.03125[/tex] Hence, person B is more likely to get 5
Question 11: Person with Higher median
For person A
[tex]Median = \frac{n(Head) + 1}{2}th[/tex]
[tex]Median = \frac{32 + 1}{2}th[/tex]
[tex]Median = \frac{33}{2}th[/tex]
[tex]Median = 16.5th[/tex]
This means that the median is the mean of the 16th and the 17th item
So,
[tex]Median = \frac{3+2}{2}[/tex]
[tex]Median = \frac{5}{2}[/tex]
[tex]Median = 2.5[/tex]
For person B
[tex]Median = \frac{n(Dice) + 1}{2}th[/tex]
[tex]Median = \frac{30 + 1}{2}th[/tex]
[tex]Median = \frac{31}{2}th[/tex]
[tex]Median = 15.5th[/tex]
This means that the median is the mean of the 15th and the 16th item. So,
[tex]Median = \frac{5+5}{2}[/tex]
[tex]Median = \frac{10}{2}[/tex]
[tex]Median = 5[/tex]
Person B has a greater median of 5
Question 12: Probability that B gets 5 or 6
This is calculated as:
[tex]P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}[/tex]
From the sample space of person B, we have:
[tex]n(5\ or\ 6) =n(5) + n(6)[/tex]
[tex]n(5\ or\ 6) =8+10[/tex]
[tex]n(5\ or\ 6) = 18[/tex]
So, we have:
[tex]P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}[/tex]
[tex]P(5\ or\ 6) = \frac{18}{30}[/tex]
[tex]P(5\ or\ 6) = 0.60[/tex]
[tex]P(5\ or\ 6) = 60\%[/tex]
Question 13: Person with higher probability of 3 or more
Person A
[tex]n(3\ or\ more) = 16[/tex]
So:
[tex]P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}[/tex]
[tex]P(3\ or\ more) = \frac{16}{32}[/tex]
[tex]P(3\ or\ more) = 0.50[/tex]
[tex]P(3\ or\ more) = 50\%[/tex]
Person B
[tex]n(3\ or\ more) = 28[/tex]
So:
[tex]P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}[/tex]
[tex]P(3\ or\ more) = \frac{28}{30}[/tex]
[tex]P(3\ or\ more) = 0.933[/tex]
[tex]P(3\ or\ more) = 93.3\%[/tex]
By comparison:
[tex]93.3\% > 50\%[/tex]
Hence, person B has a higher probability of 3 or more
Does the set of numbers form a Pythagorean triple? Explain.
Explanation:
Pythagorean Triples are sets of whole numbers for which the Pythagorean Theorem holds true. The most well-known triple is 3, 4, 5. This means that 3 and 4 are the lengths of the legs and 5 is the hypotenuse.
Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.
2 similar triangles. Triangle 1 has side lengths 16, 24, blank. Triangle 2 has side lengths 12, 18, blank.
a.
StartFraction 12 Over 24 EndFraction = StartFraction 18 Over 16 EndFraction = StartFraction 1 Over 2 EndFraction
b.
StartFraction 12 Over 18 EndFraction = StartFraction 16 Over 24 EndFraction = StartFraction 2 Over 3 EndFraction
c.
StartFraction 12 Over 16 EndFraction = StartFraction 18 Over 24 EndFraction = StartFraction 3 Over 4 EndFraction
d.
StartFraction 18 Over 12 EndFraction = StartFraction 24 Over 16 EndFraction = StartFraction 3 Over 2 EndFraction
Please select the best answer from the choices provided
A
B
C
D
Answer:
the correct answer is
C.
StartFraction 12 Over 16 EndFraction = StartFraction 18 Over 24 EndFraction = StartFraction 3 Over 4 EndFraction
Find the set of values of k for which the line y=kx-4 intersects the curve y=x²-2x at 2 distinct points?
Answer:
[tex]-6 < k < 2[/tex]
Step-by-step explanation:
Given
[tex]y = x^2 - 2x[/tex]
[tex]y =kx -4[/tex]
Required
Possible values of k
The general quadratic equation is:
[tex]ax^2 + bx + c = 0[/tex]
Subtract [tex]y = x^2 - 2x[/tex] and [tex]y =kx -4[/tex]
[tex]y - y = x^2 - 2x - kx +4[/tex]
[tex]0 = x^2 - 2x - kx +4[/tex]
Factorize:
[tex]0 = x^2 +x(-2 - k) +4[/tex]
Rewrite as:
[tex]x^2 +x(-2 - k) +4=0[/tex]
Compare the above equation to: [tex]ax^2 + bx + c = 0[/tex]
[tex]a = 1[/tex]
[tex]b= -2-k[/tex]
[tex]c =4[/tex]
For the equation to have two distinct solution, the following must be true:
[tex]b^2 - 4ac > 0[/tex]
So, we have:
[tex](-2-k)^2 -4*1*4>0[/tex]
[tex](-2-k)^2 -16>0[/tex]
Expand
[tex]4 +4k+k^2-16>0[/tex]
Rewrite as:
[tex]k^2 + 4k - 16 + 4 >0[/tex]
[tex]k^2 + 4k - 12 >0[/tex]
Expand
[tex]k^2 + 6k-2k - 12 >0[/tex]
Factorize
[tex]k(k + 6)-2(k + 6) >0[/tex]
Factor out k + 6
[tex](k -2)(k + 6) >0[/tex]
Split:
[tex]k -2 > 0[/tex] or [tex]k + 6> 0[/tex]
So:
[tex]k > 2[/tex] or k [tex]> -6[/tex]
To make the above inequality true, we set:
[tex]k < 2[/tex] or [tex]k >-6[/tex]
So, the set of values of k is:
[tex]-6 < k < 2[/tex]
Find the x-intercept of the graph of the linear equation y= - 1/3 x+3?
x-intercept =
Answer:
9
Step-by-step explanation:
Plug in 0 for y and solve for x.
0 = (-1/3)x + 3
(-1/3)x = -3
x = 9
Geometry is fun or ducks like water
Answer:
i am a duck and i can confirm water is pretty poggers
Step-by-step explanation:
PLEASE HELP ME FOR 15 POINTS AND BRAINLIEST QUICK! thanks.
Answer:
cumulative frequency
1
8
25
45
58
62
Answers:
Cumulative frequencies from top to bottom:
1825455862Other answers:
There are 62 golfers total mode = 72Median is between slots 31 and 32 Median = 72Refer to the diagram below
================================================
Explanation:
In the first row, the frequency is 1, so that's the cumulative frequency for that row. It's the total frequency so far.
In the second row, the cumulative frequency is now 8 because we add the two frequencies so far (1+7 = 8)
The third row will have a cumulative frequency of 1+7+17 = 25.
The rest of the rows will follow this pattern to fill out the table. Refer to the diagram below to see the filled out table.
----------------------------
At the very end, you should get 62 golfers total (the cumulative frequency for the bottom row).
The mode score is the most frequent value. In this case, that's the score 72 since it shows up the most times (ie has the largest frequency).
Because we have n = 62 people total, the median is between slots n/2 = 62/2 = 31 and 32
Go back to the table and note how 25 is the cumulative frequency for the third row. Since 25 is smaller than 31 and 32, this means that the median cannot be in the first three rows. Instead, it's in the fourth row because the frequency 17 here is more than enough to get us from slot 25 to slots 31 and 32.
In other words, the values 72 and 72 are in slots 31 and 32. The midpoint of which is 72.
The median is therefore 72.
Side note: the mode and median aren't always the same value.
(05.02)
Solve the following system of equations: (1 point)
x − 2y = 14
x + 3y = 9
Group of answer choices
(1, 12)
(−1, −12)
(12, −1)
(12, 1)
algebra help please answer
Answer:
Answer is 1st and Last
Step-by-step explanation:
Because if you use logic you should know why
Check if the point (-3, -5) lies on the line y= 2x -1
Plzzzzz hurry
Answer:
no
Step-by-step explanation:
To determine if the point lies on the line, substitute x = - 3 into the equation and if the value obtained equals - 5 then it lies on the line.
y = 2(- 3) - 1 = - 6 - 1 = - 7 ≠ - 5
Then the point (- 3, - 5 ) is not on the line
Find the value of x.
42°
(5x + 2)
Answer:
x=8
Step-by-step explanation:
assuming this is what you mean:
(5x+2)=42
try to
isolate the variable by subtracting 2 from both sides
5x=40
continue to isolate the variable
divide by 5 on both sides
5x/5=40/5
x=8
What else would need to be congruent to show that ABC= DEF by ASA?
B
E
10
10
45
A
с
45
F
O A. ZBE ZE
B. AC = DF
C. ZA ZD
O D. BC = EF
Answer:
Option A
then you would have an angle, a side and another angle (ASA) next to each other
Opt.B would be a second sude (SAS)
Opt.C is already given
Opt.D seems to be like (A-S-S). no pun intended.
The additional information need to be added to show the given triangles congruent is angle B = angle E
What are congruent triangles?Triangles are said to be congruent if their corresponding sides and angles are congruent.
Given is a pair of triangles, Δ ABC and Δ DEF, in this angle A = angle D and AB = DE = 10,
We need to find one more reason to make them congruent by ASA rule,
In ASA rule of congruence, we have two corresponding angles congruent in the triangles and a side between them need to be congruent,
Here, the pair of two angles should be ∠ A and ∠ D and ∠ B and ∠ E, because the congruent sides AB and DE are in mid of them.
Hence, the additional information need to be added to show the given triangles congruent is angle B = angle E
Learn more about triangles congruent click;
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In 2001 , a youth clubs total income was £1000 the club spent 60% of its total income on renting a hall it further spent £250 on prizes work out the ratio
The amount spent on hall : amount spent on prizes
Answer:
12:5
Step-by-step explanation:
To calculate the ratio, we must first find the values of the two expenditures. The amount spent on renting a hall was 60% of £1000. To represent percentages in decimals, we can simply divide the percentage by 100, resulting in 0.6 here. We can then multiply this value by 1000 to get the amount spent on renting a hall, which comes out to £600
The ratio is then 600 : 250, 60 : 25 (divide both sides by 10) , or 12:5 (divide both sides by another 5)
10 POINTS!!! 1 to 16 please hurry and answer correctly
Answer:
1.false
2.true
3.true
4.true
5.120
6.105
7.85
8.100
9.115
10.40
11.13
12.30
13.36
14.65
15.35
16.75
Which ratios are equal to cos(B)? Choose the TWO ratios that apply.
Answer:2 and 5
Step-by-step explanation:
The ratios that are equal to [tex]cos(B)[/tex] : [tex]\bold{\frac{BC}{AB}}[/tex] and [tex]\bold{\frac{EF}{DE}}[/tex]
What are similar triangles?"Two triangles are said to be similar
- if corresponding angles are equal and the sides
- if corresponding sides of the triangles are in proportion."
What is cosine angle?In a right triangle,
cos(Ф) = (adjacent side of angle Ф) ÷ hypotenuse
For given example,
Triangles ABC and DEF are similar triangles.
This means, ∠A = ∠D, ∠B = ∠E, ∠C = ∠F
And, [tex]\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}[/tex] ..............(i)
For a right triangle ABC,
the cosine of angle B is,
[tex]cos(B)=\frac{BC}{AB}[/tex]
From (i),
[tex]\frac{BC}{AB}=\frac{EF}{DE}[/tex]
So, the cosine of angle B is,
[tex]cos(B)=\frac{EF}{DE}[/tex]
Therefore, the ratios that are equal to [tex]cos(B)[/tex] : [tex]\frac{BC}{AB}[/tex] and [tex]\frac{EF}{DE}[/tex]
Learn more about similar triangles here:
https://brainly.com/question/25882965
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Does 12, 24, 36 form a right triangle?
Answer:
no bc pythagorean
Step-by-step explanation:
How do i solve 1+1=0
Answer:
Logically that's not possible but if you want to prove it then, you have to use a trick.
Step-by-step explanation:
1 + 1 = 1 + [tex]\sqrt{1}[/tex]
= 1 + [tex]\sqrt{(-1) * (-1)}[/tex]
= 1 + [tex]\sqrt{(-1)}[/tex] * [tex]\sqrt{(-1)}[/tex]
= 1 + [tex]\sqrt{i^2}[/tex] * [tex]\sqrt{i^2}[/tex]
= 1 + i * i
= 1 + i^2
= 1 + (-1)
= 1 - 1
= 0
So, 1 + 1 = 0
Hope this will help. Please give me brainliest.
Joshua wants to buy a flat-screen TV that’s costs $625.he save $62.50 each week to buy the TV. In how many weeks will he have enough money to make his purchase?
Answer:
in 10 weeks because if you multiply 62.50 10 times you get 625
Answer:
The answer is 10
I hope this helps
find the volume of this cone. round to the nearest tenth. l=10 r-6
Answer:
376.8
Step-by-step explanation:
Formula Volume Cone = πr² * h/3
Volume = 3.14 * 36 * 3 1/3
Volume ≈ 376.8
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Answer: 301.6
-------------------
answer above isn't right this is, trust me.
Complete the proof. PROVE:△VWY≅△UXY
Answer:
D.) SAS or Side angle Sideosjdjaidbsojaanod
The two triangles are similar.
What is the value of x?
Enter your answer in the box HELP PLS
The Above triangles are similar, Therefore the corresponding sides would be proportional.
that is : -
[tex] \dfrac{16}{12} = \dfrac{6x}{5x - 2} [/tex][tex]16 \times (5x - 2) = 12 \times 6x[/tex][tex]80x - 32 = 72x[/tex][tex]80x - 72x = 32[/tex][tex]8x = 32[/tex][tex]x = 32 \div 8[/tex][tex]x = 4[/tex][tex]\mathfrak{best \: \: of \: \: luck \: \: for \: \: your \: \: assignment}[/tex]
Which equation shows how to use equivalent fractions to evaluate 5/7 + 1/2.
Choose 1 answer:
Answer:
last one
Step-by-step explanation:
[tex]\frac{5}{7}[/tex] = [tex]\frac{10}{14}[/tex]
[tex]\frac{1}{2}[/tex] = [tex]\frac{7}{14}[/tex]
need common denominators to add fractions.
what ever is multiplied to the bottom needs to be multiplied to the top
for example : [tex]\frac{5}{7}[/tex] x [tex]\frac{2}{2}[/tex] = [tex]\frac{10}{14}[/tex]
solve the equation (log base 3^x)^2_6log base 3^x+9=0
Step-by-step explanation:
the answer is in the above image
5 1 point In the standard form of a circle (x – h)^2 + (y - k)^2 = r^2, which of the following represents the center of the circle?
A:(h,k)
B:r
C:(x,y)
D:r^2
Option C with h and k
see screenshot for an example
general formula is
r² = (x - x-center)² + (y - y-center)²
How much will this trash can hold? It is 4 feet tall and has a base radius of 1 foot.
_____ cubic feet
Answer:
volume = 12.56 cubic feet
Step-by-step explanation:
[tex]volume = \pi r^2 \times h \\\\volume = 3.14 \times 1 ^2 \times 4 = 3.14 \times 4 = 12. 56 \ cubic \ feet[/tex]
Helpppp and explain :)
Answer:
Problem 1: 25
Problem 2: 693
Step-by-step explanation:
Problem 1:
f(x) = -5n + 1
g(x) = -6n + 2
(f + g)(-2) = f(-2) + g(-2)
f(-2) = -5(-2) + 1
f(-2) = 10 + 1
f(-2) = 11
g(-2) = -6(-2) + 2
g(-2) = 12 + 2
g(-2) = 14
(f + g)(-2) = 11 + 14
(f + g)(-2) = 25
Problem 2:
f(x) = 7 + 2x
g(x) = 5x - 2
fg(7) = f(7) × g(7)
f(7) = 7 + 2(7)
f(7) = 7 + 14
f(7) = 21
g(x) = 5(7) - 2
g(x) = 35 - 2
g(x) = 33
Therefore:
fg(7) = 21 × 33
fg(7) = 693