Answers
Because the slope is rise 3 run 2 and the y-intercept is -1
Related Questions
529 as a desmil number
Answers
Answer:
529.000
Step-by-step explanation:
A decimal number is a number whose whole number and fraction part are separated by a decimal point.
529 represented as a decimal is 529.000
Also, you can add as many zeros as you want behind the decimal point.
Please pick as brainliest!
[tex] \displaystyle \rm\int_{0}^{ \infty } \left( \frac{ {x}^{2} + 1}{ {x}^{4} + {x}^{2} + 1} \right) \left( \frac{ ln \left(1 - x + {x}^{2} - {x}^3 + \dots + {x}^{2020} \right) }{ ln(x) } \right) \: dx[/tex]
Answers
Recall the geometric sum,
[tex]\displaystyle \sum_{k=0}^{n-1} x^k = \frac{1-x^k}{1-x}[/tex]
It follows that
[tex]1 - x + x^2 - x^3 + \cdots + x^{2020} = \dfrac{1 + x^{2021}}{1 + x}[/tex]
So, we can rewrite the integral as
[tex]\displaystyle \int_0^\infty \frac{x^2 + 1}{x^4 + x^2 + 1} \frac{\ln(1 + x^{2021}) - \ln(1 + x)}{\ln(x)} \, dx[/tex]
Split up the integral at x = 1, and consider the latter integral,
[tex]\displaystyle \int_1^\infty \frac{x^2 + 1}{x^4 + x^2 + 1} \frac{\ln(1 + x^{2021}) - \ln(1 + x)}{\ln(x)} \, dx[/tex]
Substitute [tex]x\to\frac1x[/tex] to get
[tex]\displaystyle \int_0^1 \frac{\frac1{x^2} + 1}{\frac1{x^4} + \frac1{x^2} + 1} \frac{\ln\left(1 + \frac1{x^{2021}}\right) - \ln\left(1 + \frac1x\right)}{\ln\left(\frac1x\right)} \, \frac{dx}{x^2}[/tex]
Rewrite the logarithms to expand the integral as
[tex]\displaystyle - \int_0^1 \frac{1+x^2}{1+x^2+x^4} \frac{\ln(x^{2021}+1) - \ln(x^{2021}) - \ln(x+1) + \ln(x)}{\ln(x)} \, dx[/tex]
Grouping together terms in the numerator, we can write
[tex]\displaystyle -\int_0^1 \frac{1+x^2}{1+x^2+x^4} \frac{\ln(x^{2020}+1)-\ln(x+1)}{\ln(x)} \, dx + 2020 \int_0^1 \frac{1+x^2}{1+x^2+x^4} \, dx[/tex]
and the first term here will vanish with the other integral from the earlier split. So the original integral reduces to
[tex]\displaystyle \int_0^\infty \frac{1+x^2}{1+x^2+x^4} \frac{\ln(1-x+\cdots+x^{2020})}{\ln(x)} \, dx = 2020 \int_0^1 \frac{1+x^2}{1+x^2+x^4} \, dx[/tex]
Substituting [tex]x\to\frac1x[/tex] again shows this integral is the same over (0, 1) as it is over (1, ∞), and since the integrand is even, we ultimately have
[tex]\displaystyle \int_0^\infty \frac{1+x^2}{1+x^2+x^4} \frac{\ln(1-x+\cdots+x^{2020})}{\ln(x)} \, dx = 2020 \int_0^1 \frac{1+x^2}{1+x^2+x^4} \, dx \\\\ = 1010 \int_0^\infty \frac{1+x^2}{1+x^2+x^4} \, dx \\\\ = 505 \int_{-\infty}^\infty \frac{1+x^2}{1+x^2+x^4} \, dx[/tex]
We can neatly handle the remaining integral with complex residues. Consider the contour integral
[tex]\displaystyle \int_\gamma \frac{1+z^2}{1+z^2+z^4} \, dz[/tex]
where γ is a semicircle with radius R centered at the origin, such that Im(z) ≥ 0, and the diameter corresponds to the interval [-R, R]. It's easy to show the integral over the semicircular arc vanishes as R → ∞. By the residue theorem,
[tex]\displaystyle \int_{-\infty}^\infty \frac{1+x^2}{1+x^2+x^4}\, dx = 2\pi i \sum_\zeta \mathrm{Res}\left(\frac{1+z^2}{1+z^2+z^4}, z=\zeta\right)[/tex]
where [tex]\zeta[/tex] denotes the roots of [tex]1+z^2+z^4[/tex] that lie in the interior of γ; these are [tex]\zeta=\pm\frac12+\frac{i\sqrt3}2[/tex]. Compute the residues there, and we find
[tex]\displaystyle \int_{-\infty}^\infty \frac{1+x^2}{1+x^2+x^4} \, dx = \frac{2\pi}{\sqrt3}[/tex]
and so the original integral's value is
[tex]505 \times \dfrac{2\pi}{\sqrt3} = \boxed{\dfrac{1010\pi}{\sqrt3}}[/tex]
Select the correct answer from each drop-down menu.
On the day the link was emailed, trailer
Two days after the link was emailed, trailer
Four days after the link was emailed, trailer
had the most views.
had the most views.
had the most views.
Answers
Answer:
k
[tex]2xyy15 { { \div - \\ \sqrt[ {x. - - {?}^{?} }^{2} ]{?} }^{2} }^{2} [/tex]
Answer:
On the day the link was emailed, trailer
A
had the most views.
Two days after the link was emailed, trailer
A
had the most views.
Four days after the link was emailed, trailer
B
had the most views.
Step-by-step explanation:
The total number of views on the day the email was sent, two days later, and four days later are represented by the values of the functions when x = 0, 2, and 4.
Substitute these values into the equation:
Find these values in the table:
Apply the described rule:
So, on the day the link was emailed, trailer A had the most views.
Two days after the link was emailed, trailer A had the most views.
Four days after the link was emailed, trailer B had the most views.
solve step by step
1/x-1+1/y-2=1
3/x-1+5/y-2=4
Answers
Choose the multiplication problem that correctly shows partial products.
A) A
B) B
C) C
Answers
Answer:
B) B
Step-by-step explanation:
In this case, the first partial product will be 2 * 5 which is 10. The only option that shows this is option B, so this is our answer.
We can also check the answers as a whole,
2 * 5 = 10
80 * 5= 400
400 + 1 = 410
Again, only option B gives us this. This is means that option B is our answer.
Answer:
B
Step-by-step explanation:
82
5
--
5 x 2 = 0 (carry 1)
5 x 8 + 1 = 1 (carry 4 to bottom)
Evaluate 9 divided by 3 [(18-6)-2 to the second power]
Answers
Answer: 24
I hope this helped
A barn is shaped like a rectangular prism with a triangular prism on top as shown. The exterior four walls and two triangular faces need to be repainted. If one gallon of paint covers 232 square feet, how many gallons will it take to repaint the barn? Enter your answer in the box.
Answers
Answer:
23 gallons
Step-by-step explanation:
Given:
A barn is shaped like a rectangular prism with a triangular prism on top as shown.
The exterior four walls and two triangular faces need to be repainted.
To Find:
If one gallon of paint covers 232 square feet, how many gallons will it take to repaint the barn?
Solve:
[tex]12\cdot38\div2\cdot2+84\cdot20+38\cdot20\cdot2[/tex]
= [tex]5336\;square\;feet[/tex]
[tex]\frac{5336}{232}=23[/tex]
Hence 23 gallons to repaint the barn
~lenvy~
A relief worker needs to divide 1350 bottles of water and 144 cans of food into boxes that each contain the same number of items. Also, each box must contain the same type of item (bottled water or canned food). What is the largest number of relief supplies that can be put in each box?
Answers
The largest number of relief supplies that can be put in each box is 75 bottles and 8 cans of food respectively.
How to find highest common factorThe factors of:
1350 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 27, 30, 45, 50, 54, 75, 90, 135, 150, 225, 270, 450, 675 and 1350.
144 = 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, and 144.
The highest common factor of 1350 and 144 is 181350 bottles / 18
= 75 bottles per box
144 cans of food / 18
= 8 cans of food per box
So, there 18 boxes of items, each containing 75 bottles and 8 cans of food respectively.
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Carly needs $149 to buy a skateboard. She already has $52. She earns money washing cars for $20 a car.
Carly says that if she washes 5 cars she will have enough money to buy the skateboard.
Is Carly correct? Use the drop-down menus to explain.
Choose...
; If Carly washes 5 cars, she will have a total of
Choose...
. This is
Choose...
then the cost of the skateboard, so she
Choose...
have enough money.
Answers
Answer:
$149 - price of the skateboard
$52 - Carly's money
$20 × 5 cars = $100
$100 + $52 = $152
$152 - $ 149 = $3
money left is $3
What is the domain for the following function?
y=-x+1
x²+x-6
X-
O A. {X-1
O B. (x*-3
O c. {# -3;x # 2)
OD. x+0)
Answers
Find Rate of change and y intercept in a graph and table y=3x-3
Answers
Answer:
x=6?
Step-by-step explanation:
I think it's this answer im not sure
A manufacturing company has two plants at different locations producing three different items equally within each plant. Based on the number of workers and the demand for the items in their respective locations, the number of items manufactured per day by each plant is listed in the table. Plant A Plant B Item 1 22 15 Item 2 8 12 Item 3 14 25 Select the observed and expected frequencies for Item 2 produced by Plant B.
Answers
Answer:
the answer would be 12-19+23=18 so you need a new calculator
Step-by-step explanation:
yes
Help picture below problem 12
Answers
180 - 35 - 90 = 55
The answer is 55 degrees
6. In June, Clarissa used 1 gigabytes
of data on her cell phone. Given that
June has 30 days, how much data did
she use on average per day?
Answers
Answer:
33.33 megabytes per day on average.
Step-by-step explanation:
If 30 days = 1 Gb
Then 1 day = 1/30 = 0.033333GB
0.033333GB = 33.333 MB
Hence she used 33.333MB each day
Fourth Grade
Memory Jogger Week 5 I need helppppp
Answers
Answer:
I can help you what you need help with
Step-by-step explanation:
Use a net to find the area of the entire surface of the solid.
A rectangular prism made of unit cubes. The length is 5 unit cubes, width 4 unit cubes, height 3 unit cubes.
The surface area of the prism is
square units.
Answers
Check the picture below.
[tex]\stackrel{\textit{\Large Areas}}{\stackrel{\textit{front and back}}{2(5\cdot 3)}~~ + ~~\stackrel{\textit{left and right}}{2(3\cdot 4)}~~ + ~~\stackrel{\textit{top and bottom}}{2(5\cdot 4)}}\implies 30+24+40\implies 94[/tex]
The area of the entire surface of the solid given is 94 units².
What is Surface Area?The area of a three dimensional object on it's outer surface is called the surface area of the object.
Given a rectangular prism.
It consists of 3 pairs of identical rectangular sides.
Area of a rectangle = length × width
Find the area of each rectangular sides to find the total area.
Total area = (5 × 3) + (5 × 3) + (5 × 4) + (5 × 4) + (4 × 3) + (4 × 3)
= 15 + 15 + 20 + 20 + 12 + 12
= 94 units²
Hence the area of the prism given is 94 units².
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A linear function has a y-intercept of 10 and a slope of . What is the equation of the line?
Answers
You forgot to include your slope but it should just follow the form y= mx+ b. where m is your slope and b is your y-intercept.
help please thank you
Answers
Answer:
hmm i think its
1/2(x + y)
Step-by-step explanation:
because well... this would be eaiser for me if it said "of the" because "of the" is mostly used for multiply, but since it just said "the..." i can only guess. I think this may be the answer tho?
Due to x and y being the quantity you would simply take one half of that as a whole.
7. A cylindrical tank can hold 2279.64 cubic feet of water. The radius of the tank is 11 feet. What is the height of the tank?
Answers
Answer:
r = 8.12
Step-by-step explanation:
The volume for a cylinder is V=πr^2h therefore,
v = 2279.64
h = 11ft
r = ?
2279.64 = πr^2 * 11
[tex]\frac{2279.64}{11}= {\pi r^2} \\[/tex]
207.24 = πr^2
[tex]\frac{207.24}{\pi} =r^2\\\\66 = r^2\\\\\sqrt{66} = r\\\\\\8.12 = r[/tex]
The length of a rectangle is 3 m more than twice the width, and the area of the rectangle is 54 mº. Find the dimensions of the rectangle.
Answers
Answer:
The dimensions of rectangle are 12 m and 4.5 mStep-by-step explanation:
Given that, The length of a rectangle is 3 m more than twice the width, and the area of the rectangle is 54 m²
Let's assume width of rectangle be x m and length be 3 + 2x m respectively. To find the dimensions of the rectangle we will use the formula of Perimeter of rectangle
[tex] \\ { \underline{ \boxed{ \pmb{ \sf{ \purple{Area _{(rectangle)} = Length × width}}}}}} \\ \\ [/tex]
Substituting values in above formula:
[tex] \\ \dashrightarrow \sf \: \: (3 + 2x)(x) = 54 \\[/tex]
[tex]\dashrightarrow \sf \: \: 3x + 2x^2 = 54 \\ [/tex]
[tex]\dashrightarrow \sf \: \: - 54 + 3x + 2x^2 = 0 \\ [/tex]
[tex]\dashrightarrow \sf \: \: 2x^2 + 3x - 54 = 0\\ [/tex]
[tex]\dashrightarrow \sf \: \: 2x^2 + 12x - 9x - 54 = 0\: [/tex]
[tex]\dashrightarrow \sf \: \: 2x(x + 6) -9(x + 6) = 0\\ [/tex]
[tex]\dashrightarrow \sf \: \: (2x -9)(x+6) = 0 \\ [/tex]
[tex]\sf{x=}{\sf{\dfrac{9}{2}}}{\sf{\: or\: -6}} [/tex]
[tex]\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{\purple{ x = 4.5 }}}}}}[/tex]
Hence,
Length of rectangle = 3 + 2x = 3 + 2(4.5) = 12 mWidth of the rectangle = x = 4.5m[tex] \\ { \underline{ \pmb{ \frak{ \therefore Length \: and \: width \: of \: the \: rectangle \: is \:12 \: m \: and \: 4.5 \: m}}}} \\ [/tex]
Answer:
The dimensions of rectangle are 12 m and 4.5 mStep-by-step explanation:
Given :-
The length of a rectangle is 3 m more than twice the width the area of the rectangle is 54 m²To find :-
Dimensions of rectangleSolution:-
According to the question ,
Let the width of rectangle be x and length of rectangle be 2x+3 m
Area of rectangle :- L×B
L×B = 54m²
(2x+3) * x = 54m²
x = 4.5 m
By putting the value of x , we get
Length :- 2x+3 = 12 m
Width :- 4.5 m
Could anyone help me on this?
Answers
Answer:
117
Step-by-step explanation:
we should subtract 63 from 180
so 180 - 63 = 117°
answer correctly thanks
Answers
Answer:
Angle CBD is 65°
Step-by-step explanation:
All of these angles add up to 180:
So, we can make this equation: (x is CBD)
46 + 21 + 48 + x = 180
115 + x = 180
-115 -115
x = 65
Hope this helps
Answer:
∠CBD = 65 degrees
Step-by-step explanation:
Please open the attached image!!
Pl help me on this WORTH A LOT OF POINTS!!!!
What is the total area of the patio, walkway, and garden?
Answers
Answer:
82 ft²
Step-by-step explanation:
Area of the patio:
5 x 9 =45
Area of the walkway:
2 x 8 =16
Area of the garden:
3 x 7 =21
Total:
45+16+21 = 82
What is the range of this data set? 12.5, 10.1, 11.4, 17.3, 17.9, 12.1, 14.1, 14.4, 20.4, 19.1, 12.4, 18.9
Answers
The range of a dataset is the distance between the maximum value and the minimum value. The range is found by subtracting the minimum value from the maximum value: maximum - minimum = range.
Maximum value of this dataset = 20.4
Minimum value of this dataset = 10.1
20.4 - 10.1 = 10.3
Range = 10.3
Hope this helps!
Answer:
10.3
Step-by-step explanation:
Given set of values
12.5, 10.1, 11.4, 17.3, 17.9, 12.1, 14.1, 14.4, 20.4, 19.1, 12.4, 18.9Maximum value
The number with the greatest value in the data set⇒ 20.4Minimum value
The number with the least value in the data set⇒ 10.1Range
Maximum value - Minimum value20.4 - 10.110.3
The lengths of the legs of a right triangle are 4 and 5. What is the length
of the hypotenuse
Answers
Answer:
[tex] \sqrt{41} [/tex]
Step-by-step explanation:
[tex]let \: the \: hypothenuse =\: x \\ by \: pythagoras \: theorem \\ x {}^{2} = 4 {}^{2} + 5 {}^{2} \\ x {}^{2} = 16 + 25 \\ x {}^{2} = 41 \\ sqare \: root \: bothsides \\( \sqrt{x}) {}^{2} = \sqrt{41} \\ x = \sqrt{41} \\ lenght \: of \: the \: hypothenus = \sqrt{41} [/tex]
Find the value of x
What is the answer
Answers
Answer:
35
Step-by-step explanation:
well, you know the angles of a triangle add up to 180 degrees, and you have the other 2 degrees right there, so all you have to do is add both of the other angles 111+34= 145 and then subtract by 180, 180-145=35 so your answer is 35
A farmer wants to know how many of his cows have no spots. He has 200 cows total. He takes a random sample of 40 cows. Of these, 11 of the cows have no spots. What can the farmer predict about the entire population?
The farmer can predict that 11 cows in the entire population have no spots
The farmer can predict that 55 cows in the entire population have no spots
The farmer can predict that 40 cows in the entire population have no spots
The farmer can predict that all of the cows have no spots
Answers
Answer:
The farmer can predict that 55 cows in the entire population have no spots.
Step-by-step explanation:
The farmer can predict that 40 cows in the entire population have no spots, the correct option is C.
How to find the confidence interval for population proportion from large sample?Suppose we're given that:
Favourable Cases X (in count, in sample)
Sample Size N
Level of significance =[tex]\alpha[/tex]
Then, the sample proportion of favorable cases is:
[tex]\hat{p} = \dfrac{X}{N}[/tex]
The critical value at the level of significance[tex]\alpha is Z_{1- \alpha/2}[/tex]
The corresponding confidence interval is:
[tex]CI = & \displaystyle \left( \hat p - z_c \sqrt{\frac{\hat p (1-\hat p)}{n}}, \hat p + z_c \sqrt{\frac{\hat p (1-\hat p)}{n}} \right)[/tex]
The given information;
The farmer took a random sample of 40 cows out of 200 total cows and found that 11 of those cows have no spots. We can use this sample data to make a prediction about the entire population using statistical inference.
Now,
Plugging in the values, we get:
CI = 0.275 ± 1.96sqrt((0.275(1-0.275))/40)
CI = 0.275 ± 0.139
CI = (0.136, 0.414)
This means that we can be 95% confident that the true proportion of cows with no spots in the entire population lies between 0.136 and 0.414.
the farmer can predict that between 13.6% and 41.4%
Therefore, by confidence interval the answer will be farmer can predict that 40 cows in the entire population have no spots
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Sandra can buy 6 tomato seed packets for $2. If all the tomato seed packets cost the same amount of money, how many packets can Sandra buy for $10
A. 12
b.20
c. 24
d.30
Answers
Answer:
D. 30
Step-by-step explanation:
Notice how $2 buys 6 packets. This means that if Sandra had $1, she could buy 3 packets.
If she had $10, you must multiply 3 (packets) by 10. Sandra can buy 30 packets with $10.
Answer:
The answer is 20 (I think)
Step-by-step explanation:
The question says 6 tomato seeds at $2
So, 10*2=20
hence proved
Jemima was arranging 400 packets of biscuits for a sale. She put 52 packets into a basket and displayed 25% of the remaining packets on the shelves. What percentage of all the packets of biscuits did Jemima display on the shelves?
Answers
Answer:
87% of all the packets of biscuits Jemima displayed on the shelves.
Step-by-step explanation:
400-52=348
so, 348*25%
348*25/100
87
A cup of chocolate chips weigh about 6 ounces. A recipe calls for 31 4 cups of chocolate chips which is about how many ounces?
Answers
The recipe calls for 3 1/4 cups of chocolate chips.
We need to multiply 6 by 3 which is 18 ounces plus the 1/4 which is 6 times 1/4 = 1.5 ounces
18 + 1.5 = 19.5 ounces of chocolate chip needed
[tex]3\frac{1}{4}[/tex] cups of chocolate chips is 19.5 ounces.
If one cup of chocolate chips weighs about 6 ounces
we can find out the weight of [tex]3\frac{1}{4}[/tex] cups by multiplying it by the weight of one cup.
[tex]3\frac{1}{4}[/tex] cups = 3 cups + 1/4 cup
= 3 + 0.25
= 3.25 cups
Weight of 3.25 cups = 3.25 cups × 6 ounces/cup
Weight of 3.25 cups = 19.5 ounces
Therefore, [tex]3\frac{1}{4}[/tex] cups of chocolate chips is 19.5 ounces.
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