Write an essay comparing the two arguments made about whether dodgyball should be played in school. Use textual evidence from the article to support your answer. TITLE- A Dodgy call AUTHOR Tum Jones Introduction Hook- Bridge-​

Answer:

0

Step-by-step explanation:

((3/5 ^0)^-2)

3/5^0=0

0^-2= 0

The distance between two cars comes to be 4412.06 feet.

Find the attached diagram to visualize it better.

From the attached diagram

The Distance between two cars is x+y

The angle of elevation for the first car = 22 degrees

The angle of elevation for the second car = 65 degrees.

Height of the Goodyear blimp = 1500 feet

The tangent of an angle is the ratio of the opposite side to the adjacent side of that angle.

So, tan 22° = 1500/x

So, x= 1500/tan 22°

x = 3712.63 feet

tan 65° = 1500/y

So, y = 1500/tan 65°

y = 699.46 feet

x+y = 4412.06 feet

So, the distance between two cars =  4412.06 feet

Therefore, the distance between two cars comes to be 4412.06 feet.

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If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

[tex]\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx[/tex]

Let [tex]f(x) = \sqrt{1 + x^3}[/tex]. Compute the inverse:

[tex]f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}[/tex]

and we immediately notice that [tex]f^{-1}(x+1)=\sqrt[3]{x^2+2x}[/tex].

So, we can write the given integral as

[tex]\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx[/tex]

Splitting up terms and replacing [tex]x \to x-1[/tex] in the first integral, we get

[tex]\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}[/tex]

[tex] \qquad\begin{gathered} \begin{array}{ ||c|| c} \hline \\ \textsf { \huge{ \underline{lets\: \: solve}}} \\ \\ \: \: \sf6. \: \underline{ find \: measure \: of \: angle \: TSR}\: \: \\ \\ \textsf {As we know, diameter subtends 90° } \\ \textsf{ at an arc of same circle.} \\ \textsf{ hence we can conclude that :} \\ \\ \rm{ \therefore\angle \:TSR = 90 \degree } \\ \\ \\ \sf7. \: \underline{ find \: measure \: of \: angle \: subtended }\\ \: \underline{ \sf by \: arc \: ST \: at \: the \: centre \: of \: circle}\: \\ \\ \\ \textsf{Angle subtended by an arc at centre} \\ \textsf{ of the circle is double the angle} \\ \textsf{ subtended by the same arc on other } \\ \textsf{ part of circle, hence we can} \\ \textsf{conclude that :} \\ \\ \sf\angle SOT =2 \angle SRT \\ \\ \angle \sf SOT =2 \times 41\degree \\ \\ \sf \therefore\angle SOT = 82 \degree \\ \\ \\ \\ \hline \end{array} \end{gathered}[/tex]

Try this option, all the details are in the attachment. Note the equation a) is performed with green, the equation b) with red line.

With break green line is the cureve y= -x²; with break red line is y=2x².

[tex]\sf y=50\left(1.8\right)^{x}[/tex]

=================================

the first term : 50

crosses point : (0, 50), (1, 90)

solve for y,

[tex]\sf y=50\left(1.8\right)^{1}[/tex]

[tex]\sf y=90[/tex]

Graph:

Answer: the answer is 93.9

I hope this helps

Step-by-step explanation:

i know it its on k12

Answer:

93.9

Step-by-step explanation: I took the k12 test

the length of the line would be 1 inch

Opie created facial features with simple geometric shapes and lines. Option A

Julian Opie is a known as a renowned British artist known for his distinctive depictions of figures, portraits, and landscapes.

His earliest works was the painted steel sculptures, domestic appliances, architectural structures and geometrical shapes showing the relationship between visual and spatial observation

He created distinct facial shapes and forms on a flat surface by means of lines, colors and shadings.

Thus, Opie created facial features with simple geometric shapes and lines. Option A

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Using it's concept, it is found that the relative frequency of landing on heads is 0.48 and of landing on tails is 0.52.

A relative frequency is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, out of 50 flips, 24 landed on heads and 26 on tails, hence:

Fh = 24/50 = 0.48.

Ft = 26/50 = 0.52.

The relative frequency of landing on heads is 0.48. The relative frequency of landing on tails is 0.52.

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Answer:

49

Step-by-step explanation:

[tex](b)^{2} - 4(a)(c) \\(9)^{2} - 4(2)(4) \\81 - 4(2)(4) \\81 - 32 \\49[/tex]

Answer:

Step-by-step explanation:

if quadratic

(-3)²+5=9+5=14

so f(x)=x²+5

or

if linear

(-3)+17=14

f(x)=x+17

if  cubic

(-3)³-2(-3)²-3(-3)+14=14

f(x)=x³-2x²-3x+14

so on.

Answer:

B. Multiply each term in the 1st equation by 3

Step-by-step explanation:

Step-by-step explanation:

step 1

Multiply each term in the second equation with 4

step 2

Add equation 1 to equation 2

step 3

make x subject of formula and obtain value of X

step 4

substitute value of X in equation 1 and find Y

[tex] \frac{1}{8} = 0.125[/tex]

[tex]3 = 3[/tex]

[tex] \frac{1}{3} = 0.333[/tex]

[tex]8 = 8[/tex]

Answer:

A. y=1/8x^

Step-by-step explanation:

The bottle that holds more water has the larger volume

Beau's water bottle holds more water

The given parameters are:

Drew

Beau

The volumes of their bottles is calculated using:

V = πr^2h

So, we have:

Drew = 3.14 * (3/2)^2 * 7

Drew = 49.46

Beau = 3.14 * (2)^2 * 9

Beau = 113.04

By comparison, 113.04 is greater than 49.46

Hence, Beau's water bottle holds more water

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Explanation:

First we need the slope

[tex](x_1,y_1) = (-4,2) \text{ and } (x_2,y_2) = (3,-5)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-5 - 2}{3 - (-4)}\\\\m = \frac{-5 - 2}{3 + 4}\\\\m = \frac{-7}{7}\\\\m = -1\\\\[/tex]

Then we can find the y intercept using the coordinates of (x,y) = (-4,2)

y = mx+b

2 = -1(-4)+b

2 = 4+b

2-4 = b

-2 = b

b = -2

Alternatively, you can use the other point (x,y) = (3,-5) and m = -1.

Because m = -1 and b = -2, we go from y = mx+b to y = -1x+(-2) which simplifies to y = -x-2

The number of stickers John and Ken have in the end is 6 and 18 respectively.

let

New stickers

x + x - 12 = 3x + 5x

2x - 12 = 8x

-12 = 8x - 6x

-12 = -2x

x = 12/2

x = 6

So,

Ken stickers = x

= 6 stickers

John stickers = 3x

= 3 × 6

= 12 stickers

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Answer:

D. would be the correct answer

[tex]\left(2 + \sqrt 2 \right)\left(2-\sqrt 3 \right)\\\\=4- 2\sqrt 3 + 2 \sqrt 2 - \sqrt 6\\\\=0.91484.....[/tex]

Answer:

there are 36 part time employees and there are 144 full time employees

Step-by-step explanation: multiply 45 by 4

then multiply 180 by 0.2 to get 36 and 180 by 0.8 and get 144

[tex]\text{L.H.S}\\\\=4\sin(-x) \cos(-x)\\\\=-4\sin x \cos x\\\\=-2 \cdot 2 \sin x \cos x\\\\=-2 \sin 2x\\\\=\text{R.H.S}\\\\\text{The identity is true.}[/tex]

Answer:

1

Step-by-step explanation:

42/7 + 14 - 4 × 5

7 + 14 - 4 × 5

7 +14 - 20

20 - 20

0

Answer:0

because 42 divided by 7 is 6 and 6 + 14 is 20 and 4 times 5 is 20 som then 20 -20 = 0

Answer:

Ans might be a+b+c

Step-by-step explanation:

Hope the picture will help

Answer:

Do the math

Step-by-step explanation:

If you do the math you get answer

Answer:

Step-by-step explanation:

1 2/3 -(-1/2)

=5/3+1/2

[tex]=\frac{10+1}{6} \\=\frac{11}{6} \\=1\frac{5}{6}[/tex]

Answer:

1, 2, 3, 4, 6, and 12, because each of those divides 12 without leaving a remainder (or each of those is a counting number that can be multiplied by another counting number to make 12).

Step-by-step explanation:

hope this helps.

one shell stores CDs:6422/26

246

Answer:

when 12 pieces say =1/12

so 8 pieces say = 1/8

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

fraction of remaining part=8/12 (divided with 4)

=2/3