Answer:
1.138789 is equivalent to 8 to the second power to the -4 power.
Hope this helps :)
Please Help! Brainliest Avaliable! Literally Multiple Choice!
It's very simple. Subract 554.26 from 866.32
then, we got the difference is
312.06
thank you
Brainlist please.
find x and y pls help
30 + 110 + 30 + 110 = 280
360-280 = 80
2y = 80
y = 40 degrees
If y is 40. Then the angle next to 30 is also y due to vertically opposite angles.
30 + 40 = 70
The line with 2 arrows is parallel to the line with x degrees. So, I use co-interior angles adds to 180.
In that c shaped, we got the bottom angle to be 70 & the top to be 110 because co-interior angles =180
Forget the c shape exists, and move onto the triangle that's visible. The top angle is 110 as found.
Angles in triangle add to 180.
180 - 110 - 30 = 40.
Thus, x = 40 degrees
There's a short cut I realise now because we can have alternate angles are equal; creating a z shape to find what x is equal to & that turns out to be the same value as y. ( due to vertically opposite angles)
Hope this helps!
Assignment
Slide the green dot from 0 to plot the number at the correct
location.
Plot-1.
-6 -5 4 -3 -2 -1 0 1
2
3 4
5
+
6
Use the interactive number line to find each sum to
complete the table.
A
1
-1
-4
-6
B
2
-2
1
-3
A + B
3
R
S
T
From the number line, the values which completes the sum in the table are:
R = -3.S = -3.T = -9.What is a number line?A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.
How to find each sum?From the table of values (see attachment), the values on the number line are represented as follows:
a + b = a + b
R = -1 - 2
R = -3.
a + b = a + b
S = -4 + 1
S = -3.
a + b = a + b
T = -6 - 3
T = -9.
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Complete the frequency table:
Method of Travel to School
Walk/Bike Bus Car Row totals
Under age 15 18 165
Age 15 and above 65 195
Column totals 152 110 98 360
What percentage of students age 15 and above travel to school by bus? Round to the nearest whole percent.
The percentage of students age 15 and above travel to school by bus is 47%
How to complete the table?The table of values is given as:
Method of Travel to School
Walk/Bike Bus Car Row totals
Under age 15 18 165
Age 15 and above 65 195
Column totals 152 110 98 360
Using the column total of column 1, we have:
Under age 15 + 65 = 152
This gives
Under age 15 = 87
Using the column total of column 2, we have:
Age 15 and above + 18 = 110
This gives
Age 15 and above = 92
Using the row total of row 1, we have:
Car + 87 + 18 = 165
This gives
Car = 60
Using the row total of row 2, we have:
Car + 65 + 92 = 195
This gives
Car = 38
So, the complete frequency table is
Method of Travel to School
Walk/Bike Bus Car Row totals
Under age 15 87 18 60 165
Age 15 and above 65 92 38 195
Column totals 152 110 98 360
The percentage of students age 15 and above travel to school by bus is:
Percentage = 92/195 * 100%
This gives
Percentage = 47%
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Question 1 (3 points)
Solve the following linear system:
y = -2x - 5
y = 2/3x + 3
as an ordered pair (x,y)
Answer:
Step-by-step explanation:
hello : y = -2x - 5
y = 2/3x + 3
means : -2x-5 = 2/3 x+3
-6x-15 = 2x +9
-8x=24 so : x = -3
put the value for : x in the first equation :y = -2(-3)-5 =1
the ordered pair (-3;1) is solution
In 2012, the population of a city was 6.38million. The exponential growth rate was 2.38% per year.
a) Find the exponential growth function.
b) Estimate the population of the city in 2018.
c) When will the population of the city be 9million?
d) Find the doubling time.
Question content area bottom
Part 1
a) The exponential growth function is P(t)
enter your response here, where t is in terms of the number of years since 2012 and P(t) is the population in millions.
The exponential growth function is P(t) = 6.38 million x (1.0238^t).
The population of the city in 2018 is 7.35 million.
The year the population would be 9 million is 14.46 years.
The doubling time is 29.12 years.
What is the exponential growth function?FV = P (1 + r)^n
FV = Future populationP = Present populationR = rate of growthN = number of years6.38 million x (1.0238^t)
Population in 2018 = 6.38 million x (1.0238^6) = 7.35 million
Number of years when population would be 9 million : (In FV / PV) / r
(In 9 / 6.38) / 0.0238 = 14.46 years
Doubling time = In 2 / 0.0238 = 29.12 years
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A bagel shop sells coffee in a container shaped like a rectangular prism. A graphic designer who works for the bagel shop drew the net below to create a design for the container.
1598 cm square is the area of the container.
According to the statement
we have given that the container is rectangular prism
And Length of rectangular prism is 34cm
Width of rectangular prism is 17 cm
Height of rectangular prism is 20 cm
we use the below written formula to find the surface area
Surface area formula A=(wl+hl+hw)
To find the surface area of the container.
Substitute the values of Length, width and height in the formula then
A=(wl+hl+hw)
A=((17)(34)+(20)(34)+(20)(17))
After solving the values
A=(578+680+340)
A= 1598
So, 1598 cm square is the area of the container.
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solve for x by completing the square: x2 − 8x + 13 = 0. show all work
There are two real roots for the quadratic equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.
How to find the roots of a polynomial by completing the square
In this question we must apply algebraic handling to simplify a quadratic equation and find the roots that satisfy the expression. Completing the square consists in transforming part of the equation into a perfect square trinomial, and then we clear for x:
x² - 8 · x + 13 = 0
x² - 8 · x + 16 = 3
(x - 4)² = 3
x - 4 = ± √2
x = 4 ± √2
There are two real roots for the quadratic equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.
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3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared the insect endangered and transplanted the insect to protected area. The population P(t) (in thousands) of insects in t months after being transplanted is
a. [3 pts] Determine the number of months until the insect population reaches 40 thousand (round to 2 decimal places).
b. [3 pts] What is the limiting factor on the insect population as time progresses? Explain your answer.
c. [3 pts] Sketch a graph of the function using the window and. Be sure to indicated the scale on the graph, label the axes, at least 2 points on the graph, and any asymptotes.
The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.
Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).
(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get
P(t)=40
(50(1+0.05t))/(2+0.01t)=40
Cross multiply both sides, we get
50(1+0.05t)=40(2+0.01t)
Apply the distributive property a(b+c)=ab+ac, we get
50+2.5t=80+0.4t
Subtract 0.4t and 50 from both sides, we get
50+2.5t-0.4t-50=80+0.4t-0.4t-50
2.1t=30
Divide both sides with 2.1, we get
t=14.29 months
(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get
[tex]\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end[/tex]
(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.
Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.
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In the following activity, write an equation to represent each verbal statement, and use it to find the value of each unknown number. Then, put the solution values in order from smallest to largest. [Note: The smallest solution is "first", and the largest solution is "fifth".]
The solution values in order from smallest to largest are;
-13 - First-10 - Second-3.5 - Third-2 - Fourth-0.75 - FifthUnknown equationlet
the unknown number = x(x - 5)-2 = 14
-2x + 10 = 14
-2x = 14 - 10
-2x = 4
x = 4/-2
x = -2
4x - 5 = -8
4x = -8 + 5
4x = -3
x = -3/4
x = -0.75
(x + 3) / 5 = -2
x + 3 = -2(5)
x + 3 = -10
x = -10 - 3
x = -13
1/2x + 4 = -1
1/2x = -1 - 4
1/2x = -5
x = -5 ÷ 1/2
= -5×2/1
x = -10
x + 2 = 6/-4
-4(x + 2) = 6
-4x - 8 = 6
-4x = 6 + 8
-4x = 14
x = 14/-4
x = -3.5
Therefore, the smallest value is -13 and the largest value is -0.75.
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Some boys and girls are waiting for school buses. 25 girls get on the first bus. The ratio of boys to girls at the stop is now 3:2. 15 boys get on the second bus. There are now the same number of boys and girls at the bus stop. How many students were originally at the bus stop?
Answer:
100
Step-by-step explanation:
Forming algebraic equations and solving:
Let the number of boys originally at the stop = 'x'
Let the number of girls originally at the stop = 'y'
25 girls get on the first bus.
⇒ The number of girls now at the stop = y -25
Ratio of boys to girls:
[tex]\sf \dfrac{x}{y -25}= \dfrac{3}{2}\\\\Cross \ multiply,\\\\2x = 3*(y- 25)\\\\2x = 3y - 3*25\\\\2x = 3y - 75 ------[/tex](I)
15 boys get on the second bus.
Now, the number of boys at the stop = x - 15
Number of girls at the stop = y - 25
Ratio of boys to girls,
[tex]\sf \dfrac{x - 15}{y -25} = \dfrac{1}{1}\\\\Cross \ multiply, \\\\x - 15 = y -25\\\\[/tex]
x = y -25 + 15
x = y - 10
Plugin x = y - 10 in equation (I)
2*(y-10) = 3y -75
2y - 20 = 3y -75
-20 = 3y - 75 - 2y
-20 = y -75
-20 +75 = y
[tex]\sf \boxed{\bf y = 55}[/tex]
Plugin y = 55 in equation (I)
x = 55 -10
[tex]\sf \boxed{\bf x = 45}[/tex]
Number of students originally at the stop = x + y
= 55 + 45
= 100
answer this please only the ones that are blank
Answer:
#3 5(2a+4)
#4 5(a+2+4)
#5 5a+5(2+4)
Step-by-step explanation:
I think so, I am probably wrong
Theodore invests $20,000 at 6% simple interest for 1 year. How much is in the account at the end of the 1
year period?
Answer:
Answer:
$21200
Step-by-step explanation:
6% × 20000 = 1200.
20000 + 1200 = 21200
basically yout find 6% of 20000 then add it the original 20000
Please help me put them in correct place
The inequalities that match the given expressions are
x ≤ 95
x > 100
5x ≤ 100
20 ≤ x ≤100
respectively
Writing linear inequalitiesFrom the question, we are to match the statements with the corresponding inequalities
Nora's height(x) is at least 5 cm less than Stacy who is 100 cm tallx ≤ 100 -5
x ≤ 95
Temperature(x) is greater than the boiling point of water (100 °C)x > 100
John buys x chocolates worth $5 each but he has only $100 in his pocket5x ≤ 100
Ronny decided not to exceed 100L of water usage and ends up using at least 1/5th of this limit every dayx ≤ 100
and
x ≥ 1/5 × 100
x ≥ 20 ≡ 20 ≤ x
∴ 20 ≤ x ≤100
Hence, the inequalities that match the given expressions are
x ≤ 95
x > 100
5x ≤ 100
20 ≤ x ≤100
respectively
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The plot below shows the volume of paint left in 444 cans.
All measurements are rounded to the nearest \dfrac12
2
1
start fraction, 1, divided by, 2, end fraction pint.
A line plot labeled Volume in pints shows, moving left to right, labeled tick marks at two, two and one-half, three, three and one-half, four, four and one-half, five, five and one half, and six. Dots are plotted as follows: 1 dot above two and one-half; 2 dots above four; and 1 dot above five and one-half.
A line plot labeled Volume in pints shows, moving left to right, labeled tick marks at two, two and one-half, three, three and one-half, four, four and one-half, five, five and one half, and six. Dots are plotted as follows: 1 dot above two and one-half; 2 dots above four; and 1 dot above five and one-half.
If we split the total amount of paint so that each can had the same amount, how much paint would be in each can?
The amount of paint that would be contained in each of the can would be 8.
How to solve for the amount of paint.
Using the information in the question we have the following
We have to solve the equation as
(2 1/2) + 2(4) + 1(5 1/2) =
2.5 + 8 + 5.5
= 16
Each of these would have to hold 16/2 = 8 pints.
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Answer:
4 pints
Step-by-step explanation:
the expert is wrong
Prove that (- 1 + i)^7 = -8(1 + i)
Convert [tex]-1+i[/tex] to polar form.
[tex]z = -1 + i \implies \begin{cases}|z| = \sqrt{(-1)^2 + 1^2} = \sqrt2 \\\\ \arg(z) = \pi + \tan^{-1}\left(\dfrac1{-1}\right) = \dfrac{3\pi}4 \end{cases}[/tex]
By de Moivre's theorem,
[tex]\left(-1+i\right)^7 = \left(\sqrt2 \, e^{i\,\frac{3\pi}4}\right)^7 \\\\ ~~~~~~~~ = \left(\sqrt2\right)^7 e^{i\,\frac{21\pi}4} \\\\ ~~~~~~~~ = 8\sqrt2 \, e^{-i\,\frac{3\pi}4} \\\\ ~~~~~~~~ = 8\sqrt2 \left(\cos\left(\dfrac{3\pi}4\right) - i \sin\left(\dfrac{3\pi}4\right)\right) \\\\ ~~~~~~~~ = 8\sqrt2 \left(-\dfrac1{\sqrt2} - \dfrac1{\sqrt2}\,i\right) \\\\ ~~~~~~~~ = -8 (1 + i)[/tex]
QED
The following are the ages (years) of 5 people in a room:
14
,
16
,
16
,
13
,
A person enters the room.
The mean age of the 6 people is now 21.
What is the age of the person who entered the room?
Answer:
67 years old. (you only gave 4 people and missed out one person)
Step-by-step explanation:
take all the ages first and put the unknown (age of the person who entered the room) as x.
14, 16, 16, 13, x
all of these numbers added to together would be:
59 + x
Because the question is talking about the mean age, to find mean:
add all the values in the data (ages) and divide by the total number of values on the list. (in your case would be 6 people (following your question) but you gave only 5 people including the x).
then (59 + x) / 6 = 21
21 x 6 = 126
126 = 59 + x
x = 67
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used
Match each statement with its contrapositive.
Option 4,option 6, and option 2 is the respective contrapositive to the statements given. This can be obtained by understanding what contrapositive is and converting the statements.
What is contrapositive? Contrapositive: A statement which is obtained by interchanging both the hypothesis and conclusion of a given statement after contradicting them. For "if p then q" the contrapositive is "if not-q,then not-p "For example,Statement = If a figure is a square, then it is a quadrilateral.
Contrapositive = If a figure is not a quadrilateral, then it is not a square.
Here,
Statement 1: If two figures are congruent, then their corresponding sides are equal.Contrapositive: If the corresponding sides of two figures aren't equal, then the two figures aren't congruent. (Option 4)
Statement 2: If two numbers are even, then their product is even.Contrapositive: If the product of two numbers isn't even, then the two numbers aren't even. (Option 6)
Statement 3: If a figure is a pentagon, then the sum of its interior angles is 540°.Contrapositive: If the sum of the interior angles of a figure isn't 540°, then the figure isn't a pentagon. (Option 2)
Hence Option 4,option 6, and option 2 is the respective contrapositive to the statements given.
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for this graph, mark the statements that are true.
Answer:
C,D
Step-by-step explanation:
C: Range refers to the y axis and all values shown on this graph (and even beyond the graph) are greater than 0
D: The domain refers to the x-axis. The line goes on forever both to the right and the left therefore meaning all x values are used.
Complete the table. Each column should contain equivalent values. One column has been completed for you. Make sure the fractions are stated in simplest form.
Fraction Decimal Percent
0.39 39%
0.82
22%
0.8
The complete table will be:
Fraction Decimal Percent
39/100 0.39 39%
82/100 0.82 82%
22/100 0.22 22%
3/4 0.75 75%
80/100 0.8 80%
Percentage
The percentage is the given definition for a fraction whose denominator is equal to 100. It is represented by %. See the following example:
[tex]\frac{25}{100} =0.25*100=25%[/tex]
The percentage is considered a math tool with several applications and areas, for example: medicine, engineering, investments, supermarkets, drugstores,banks etc.
Line 1Fraction Decimal Percent
39/100 0.39 0.39*100=39%
Line 2Fraction Decimal Percent
82/100 0.82 0.82*100=82%
Line 3
Fraction Decimal Percent
22/100 0.22 22%
Line 4
Fraction Decimal Percent
3/4 0.75 0.75*100=75%
Line 5
Fraction Decimal Percent
80/100 0.8 0.80*100=80%
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Help Me Please with this Math Money Question It Wont Me Screenshot But
Question: CD's are 5 for $30.00.
What is the price of 3 CD's?
Answers:
A) $18.00
B) $15.00
C) $6.00
D) $3.00
Answer:
A
Step-by-step explanation:
$30.00 ÷ 5 = $6.00
$6.00 × 3 = $18.00
I NEED ANSWER ASAP please and thank you
Answer:
hexagon and pentagon structure. also known as a truncated icosahedron
Step-by-step explanation:
hope that gives you a good enough description.
Question is attached as an image
The general solution of the logistic equation is [tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex].
The particular solution of the logistic equation is [tex]y(t) = \frac{14}{1 + 0.4 \cdot e^{-\frac{14\cdot t}{3} }}[/tex].
What are the general and particular solutions of the logistic equation?
In this question we are before a type of ordinary differential equation known as equation with separable variables, that is to say, that variables t and y can be separated at each side of the expression in order to find a solution:
dy / dt = 3 · y · (1 - y /14)
dy / [(- 3 / 14 ) · y · (y - 14)] = dt
Then, we simplify the expression by partial fractions and integrate the resulting expression:
- (1 / 14) ∫ dy / y + (1 / 14)∫ dy / (y - 14) = - (14 / 3)∫ dt
- (1 / 14) · ㏑ |y| + (1 / 14) · ㏑ |y - 14| = - (14 / 3) · t + C, where C is the integration constant.
㏑ |(y - 14) / y| = - (14 / 3) · t + C
[tex]1 - \frac{14}{y} = C\cdot e^{-\frac{14\cdot t}{3} }[/tex]
[tex]\frac{14}{y} = 1 - C \cdot e^{-\frac{14\cdot t}{3} }[/tex]
[tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex]
The general solution of the logistic equation is [tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex].
If y(0) = 10, then the particular solution of the differential equation is:
10 = 14 /(1 - C)
1 - C = 1.4
C = - 0.4
The particular solution of the logistic equation is [tex]y(t) = \frac{14}{1 + 0.4 \cdot e^{-\frac{14\cdot t}{3} }}[/tex].
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Which is the graph of the inequality?
5y+x>−10
Number graph ranging from negative twenty to twenty in increments of two on the x and y axes. A dotted line with a positive slope is drawn in the fourth quadrant of the graph. The area above the line is shaded gray.
Number graph ranging from negative ten to ten on the x and y axes. A solid line passes through (negative one, zero) and (zero, three). The area to the left of the line is shaded gray.
Number graph ranging from negative twenty to twenty in increments of two on the x and y axes. A solid line passes through (zero, negative fourteen) and (two, zero). The area to the right of the line is shaded gray.
Number graph ranging from negative ten to ten on the x and y axes. A dotted line passes through (zero, negative two) and (five, negative three). The area above the line is shaded gray.
We can simplify the inequality to:
y > (-1/5)*x - 2
From that, we conclude that the correct option is the last one.
Which is the graph of the given inequality?
Here we have the inequality:
5y + x > -10
If we isolate y, we get:
y > (-10 - x)/5
y > (-1/5)*x - 2
Then the inequality will be a dashed/dotted line with a negative slope, that passes through the point (0, -2), such that the region above and to the right of the line is shaded.
From that we conclude that the correct option is the last one:
"Number graph ranging from negative ten to ten on the x and y axes. A dotted line passes through (zero, negative two) and (five, negative three). The area above the line is shaded gray."
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Which equation can be used to solve for b?
Triangle A B C is shown. Angle B C A is a right angle and angle C A B is 30 degrees. The length of side B C is 5 centimeters, the length of B A is 10 centimeters, and the length of C A is b.
tan(30o) = StartFraction 5 Over b EndFraction
tan(30o) = StartFraction b Over 5 EndFraction
tan(30o) = StartFraction 10 Over b EndFraction
tan(30o) =
Answer:
[tex]tan(30) = \frac{5}{b} [/tex]
Step-by-step explanation:
Trigonometric Ratios.
To solve for b, we check the parameters that are given in the triangle.
If we're considering 30°, we can see that the opposite is given as 5cm and the adjacent is b.
Applying:
[tex]tan \alpha = \frac{oppsite}{adjacent} \\ \\ tan \: (30) = \frac{5}{b} [/tex]
Answer:
a
Step-by-step explanation:
just did the quiz!!!!
Sets A,B , and C are subsets of the universal set U.
These sets are defined as follows.
U= {f,g,h,p.q.r.x.y.z}
A={f,h,p.q.r}
B={q,r,y,z}
C={g,h,p,q,y}
Find (B' U A) ∩ C.
Write your answer in roster form or as Ø.
[tex]B'=\{f,g,h,p,x\}\\B'\cup A=\{f,g,h,p,q,r,x\}\\(B'\cup A)\cap C=\{g,h,p,q\}[/tex]
Calculate the geometric center of the grapg under the function
The geometric center of the graph under the function is 5/3
How to determine the geometric center of the graph under the function?The equation of the function is given as:
f(x) = 3 - |x - 2|
The interval is given as:
x ∈ [0, 3]
The geometric center (gc) of the graph under the function is calculated using
gc = ∫x f(x) dx/∫f(x) dx
Substitute the known values in the above equation
gc = ∫x * (3 - |x - 2|) dx/∫3 - |x - 2| dx
Integrate the numerator and the denominator of the above equation
gc = [-1/6(x - 2)((2|x -2| - 9)x + 2|x - 2| - 18)]/[3x - 1/2[|x - 2|(x - 2)]]
Recall that the interval is given as x ∈ [0, 3]
Substitute the interval values in the above equation.
The equation is then simplified using a graphing calculator.
So, we have
gc = (65/6)/(13/2)
Express the quotient expression as a product
gc = (65/6) * (2/13)
Divide 65 by 13
gc = 5/6 * 2
Divide 2 by 6
gc = 5/3
Hence, the geometric center of the graph under the function is 5/3
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find the value of x and y
just need b1 and b2
brainliest to whoever answers
50 points
Step-by-step explanation:
b1) Any line parallel to the x-axis is horizontal. If we look at the graph of a horizontal line, we see that for any x-value you give, the y-value will be the same. In this case, the y-value is -1. Hence, the equation for the line is [tex]y=-1[/tex], as y will be -1 no matter the x.
The gradient for a horizontal line is 0, as the "rise" of the function is 0. If we use the formula [tex]\frac{rise}{run}[/tex], we would have 0 on the top, which makes the whole fraction 0.
b2) Any line parallel to the y-axis is vertical. If we look at the graph of a vertical line, we see that for any y-value, the x-value will be the same. In this case, the x-value is -1. Hence, the equation for the line is [tex]x=-1[/tex], as x will be -1 no matter the y.
The gradient for a vertical line is undefined, as the "run" of the function is 0. If we use the formula [tex]\frac{rise}{run}[/tex], we would be dividing by 0, which is undefined.
Officially, variable names in Python can be any length and can consist of uppercase and lowercase letters ( A-Z, a-z ), digits ( 0-9 ), and the underscore character ( _ ). An additional restriction is that, although a variable name can contain digits, the first character of a variable name cannot be a digit. Python’s most-followed style guide, PEP8 also suggests we limit each line to 79 characters, so, to be extra careful, we will assume variables can be of at most 7 characters in length.How many variable names can there be in Python if we abide by these two rules?
Abiding by the two rules, the number of variable names we can have in Python are; 63
How to name variables in Python Programming?The rules for python are given as;
1) Variable names in Python can be any length and can consist of uppercase and lowercase letters ( A-Z, a-z ), digits ( 0-9 ), and the underscore character ( _ ).
1b) An additional restriction is that, although a variable name can contain digits, the first character of a variable name cannot be a digit.
2) We limit each line to 79 characters, so, to be extra careful, we will assume variables can be of at most 7 characters in length.
Now, abiding by the two rules above, the number of variable names we can have in Python are;
26( A-Z) + 26(a-z) + 10(0-9) + 1 ( _ ) = 63 variable names
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