Let HALF-CLIQUE = {H: H is a graph with n nodes having a clique with at least n/2 nodes}. Show that HALF-CLIQUE is NP-complete. Hint: Use the following reduction function to show CLIQUE p HALF-CLIQL7E. Given (G, k), f(G, k) = H where H is constructed from G and k in one of two ways. Let n be the number of nodes in G. If k < n/2, form H by adding (n-2k) new nodes to G and connecting each new node to every other node in H. If k n/2, form H by adding (2k-n) new nodes to G. The new nodes are isolated, i.e., they have no edges connected to them. Your solution should include steps showing: a. HALF-CLIQUE NP b. f is computable in polynomial time. c. (G, k) CLIQUE f(G, k) HALF-CLIQUE d. (G, k) CLIQUE f(G, k) HALF-CLIQUE e. HALF-CLIQUE is NP-complete

Answer:

Nuclear codes allow the president to prove the individual is authorized to order the launch.

Explanation:

Hope this helps!

If not, I am sorry.

The policy orchestrator component that gathers the events from the managed systems and uploads them to the epo server is mcAfee agent.

The McAfee Agent can be described as the one that is distributed component of McAfee ePolicy Orchestrator (McAfee ePO).

It helps in downloads and enforcement of policies and it executes client-side tasks.

To find  find  McAfee agent, one can follow these steps:

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From the information given, the cache block size is 32. See explanation below.

Where the offset is 5 bits, the block size is given as:

2⁵ = 32.

Hence, the total number of blocks in the cache is 32.

Note that

Total cache size = No. of entries (No. of tag bits + data bits + valid bit)

Hence,

= 32 x (22+ 256 +1)

= 8, 928 bits

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Using the knowledge in computational language in JAVA it is possible to write a code that  print the respective minimum and maximum values as a single line

import java.io.*;

import java.util.*;

import java.text.*;

import java.math.*;

import java.util.regex.*;

public class Solution {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       long sum = 0;

       long max = Long.MIN_VALUE;

       long min = Long.MAX_VALUE;

       for (int i = 0; i < 5; i++){

           long n = in.nextLong();

           sum += n;

           max = Math.max(max, n);

           min = Math.min(min, n);

       }

       System.out.println((sum - max) + " " + (sum - min));

   }

}

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A firmware is installed in special, read-only memory in devices like printers or communication devices.

Firmware is known to be a kind of software that makes or produce the basic machine instructions that gives room for the hardware to act and be able to communicate with other kinds of software that is said to be running on a device.

Note that Firmware makes low-level control in for a lot of device's hardware and its example is microcontroller which is said to be an aspect of the microprocessor that informs the microprocessor the right actions to take.

Hence A firmware is installed in special, read-only memory in devices like printers or communication devices is the right answer.

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The connection that failed while opening file within cryptographic module - mbedtls_ssl_handshake returned -9984 ( X509 - Certificate verification failed, e.g. CRL, CA or signature check failed is known to be a kind of a TLS hanshake failing with EC.

These are known to be Software, hardware or what we call the firmware that is made up of one or a lot of cryptographic functions.

Note that a cryptographic product is one that is made up of a kind of cryptographic module and they also help to implements security functions (such as cryptographic algorithms),

Therefore, based on the above, The connection that failed while opening file within cryptographic module - mbedtls_ssl_handshake returned -9984 ( X509 - Certificate verification failed, e.g. CRL, CA or signature check failed is known to be a kind of a TLS hanshake failing with EC.

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The thing that has happened to the supply of rude confrontations is that  The supply has increased, shifting down and to the right.

Supply in economics is known to be seen as the full amount of a given product or service that a given  supplier is known to offers to consumers at a specific point in time and a given price level.

Hence, The thing that has happened to the supply of rude confrontations is that  The supply has increased, shifting down and to the right because Anonymity on the internet has lowered the cost of rudely confronting people.

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Anonymity on the Internet has lowered the cost of rudely confronting people. What has happened to the supply of rude confrontations? a) The supply has decreased, shifting up and to the left. b) The supply has increased, shifting up and to the left. C) The supply has decreased, shifting down and to the right. d) The supply has increased, shifting down and to the right. Question 46 (1 point) Figure: Supply Shift Saved Price $100-

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The outcome will be option b: ) CLIENT will have 6 records, AGENT will have 3 records.

Client record is known to be a form of a written composition of information that tells and documents the examination , diagnosis or others of a client.

Based on the above scenario, The outcome will be option b: ) CLIENT will have 6 records, AGENT will have 3 records.

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This is known as ASCII Art. The program that give the above output is given below.

The codes that resort to the above output are given below:


public class ASCIIArt{

public static void main(String[] args) {

System.out.println(" /)___");

System.out.println(" / o|___");

System.out.println(" / )");

System.out.println("/ )___/");

}

}

The 95 readable characters from the total of 128 established by the ASCII Standard from 1963 and ASCII compliant character sets with proprietary extra characters make up ASCII art, a visual design style that leverages computers for display (beyond the 128 characters of standard 7-bit ASCII).

The phrase is also figuratively used to describe all forms of text-based visual art. Any text editor may be used to make ASCII graphics, which is frequently used with free-form languages.

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Full Question:

See attached image.

The method that the team propose in protecting the servers against explosives is Physical Security.

Physical security is known to be a key part as it acts in network security and tends to protect an organization and employees.

Note that   An organization's physical components is one that can have vulnerabilities that need to be mitigated by using appropriate physical security measures by:

Hence, The method that the team propose in protecting the servers against explosives is Physical Security.

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Answer:

Array of variables

Explanation:

This occurs when you group together related variables

At startup, Windows Server 2012 Core presents a command window.

Windows Server is known to be a kind of a group of operating systems that is made by Microsoft that aids enterprise-level management, data storage, applications, and others.

The Command window is known to be that which gives a person  the information, it also gives instructions, and gives room for one  to be able to enter commands usually at the Command prompt.

Therefore, note that at startup, Windows Server 2012 Core presents a command window as it is the first thing that will come up.

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Answer:

The second generation computer is based on the transistor whereas the third generation computer is based on the integrated chip.

Explanation:

Answer:

False

Explanation:

JavaScript is language used along with html documents.

Java is a full-fledged programming language that handles applications.

If a few bits in an hdd sector or nvm page are corrupted, the controller can recover the correct values using ecc only if option D) number of bits corrupted is low irrespective of where the corruption occurs in the sector/page.

In computer disk storage, a sector is known to be a kind of a subdivision that is made up of a track that can be seen on a magnetic disk or what we call the optical disc.

Note that Each sector is one that saves a fixed amount of what we call the user-accessible data.

Note that  the sector is seen as the smallest physical storage unit that can be found on the disk, and also on most file systems and thus when  a few bits in an hdd sector or nvm page are corrupted, the controller can recover the correct values using ecc only if option D) number of bits corrupted is low irrespective of where the corruption occurs in the sector/page.

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If a few bits in an HDD sector or NVM page are corrupted, the controller can recover the correct values using ECC only if

A) the bit corruption is limited to the data portion of the sector/page.

B) the bit corruption hasn't occurred in the ECC of the sector/page.

C) the bit corruption hasn't occurred in the ECC or the header of the sector/page.

D) number of bits corrupted is low irrespective of where the corruption occurs in the sector/page.

Answer:

Stack

Explanation:

Every time you call a method, the address to which the program should return at the completion of the method is stored in a memory location called the stack.

In the case of Mary and Billy, the above is called Negotiated farewell.

In the case of  Negotiated Farewell, one can say that couples are knonw to jointly create the story of the end to what we say their marriage.

Note that Negotiated Farewell is one that is made for emotionally immature or any kind of combative people. hence, In the case of Mary and Billy, the above is called Negotiated farewell.

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Explanation:

Computers in the form of personal desktop computers, laptops and tablets have become such an important part of everyday living that it can be difficult to remember a time when they did not exist. In reality, computers as they are known and used today are still relatively new. Although computers have technically been in use since the abacus approximately 5000 years ago,

Answer:

The Code:

def month(x):

    if (x==1):

        print ("January")

    if (x==2):

        print("February")

    if (x==3):

        print("March")

    if (x==4):

        print("April")

    if (x==5):

        print("May")

    if (x==6):

        print("June")

    if (x==7):

        print("July")

    if (x==8):

        print("August")

    if(x==9):

        print("September")

    if(x==10):

        print("October")

    if(x==11):

        print("November")

    if(x==12):

        print("December")

    if(x<1 or x>12):

        print("Wrong Input! Try again")

month = int(input("Enter the month number: "))

month(month)

Explanation:

The above program is written in the PYTHON programming language.

In this program, the user inputs the number of any month, showing the month name in the output. For example,

if user enters 1, month name = JANUARY

if user enters 5, month name = MAY

and if the user enters 13, then output = Wrong Input! try again

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Based on the given instructions:

1. you must set the display format for all values: %0.2f

2. use f-string in this format: f"{}" and add your value in {}

3. int: convert float to integer and round: round up the number

num1 = float(input())

num2 = float(input())

num3 = float(input())

average = (num1+num2+num3) / 3

your_value = num1*num2*num3

print('%0.0f %0.0f %0.2f %0.2f' % (int(average), int(your_value), average, your_value))

# or:

print(f"{int(average)} {int(your_value)} {round(average,2)} {round(your_value,2)}")

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Answer: /etc/cron.monthly

Explanation:

The three different types of hard drives are:

This was said to be Introduced in the year 2003, SATA (or Serial Advanced Technology Attachment) is known to be a kind of a default interface that was made for a lot of desktop and laptop hard drives.

Hence, The three different types of hard drives are:

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Using the computational knowledge in python it is possible to write a code that Given a name and a Python list of Cow objects

def load_cows(filename):

     cow_dict = dict()

   f = open(filename, 'r')

   for line in f:

       line_data = line.split(',')

       cow_dict[line_data[0]] = int(line_data[1])

   return cow_dict

def greedy_cow_transport(cows, limit=10):

      trips = []

   cowsCopy = cows.copy()

   sortedCows = sorted(cowsCopy.items(), key=lambda x: x[1], reverse = True)

   while sum(cowsCopy.values()) > 0:

       ship = []

       total = 0

       for cow, value in sortedCows:

           if cowsCopy[cow] != 0 and value + total <= limit:

               ship.append(cow)

               total += value

               cowsCopy[cow] = 0

       trips.append(ship)

   return trips

def brute_force_cow_transport(cows,limit=10):

    trips = []

    possibilities = []

   for i in power_list:

       ship = []

       for j in i:

           ship_weights = []

           for k in j:

               ship_weights.append(cows[k])

               #print(ship_weights)

           ship.append(sum(ship_weights))

           #print(ship)

       if all(d <= limit for d in ship):

           possibilities.append(i)

     pruned_possibilities = []

   for k in possibilities:

       if k not in pruned_possibilities:

           pruned_possibilities.append(k)

   # now find the minimum list length:

   min_list_len = min(map(len, pruned_possibilities))

   for l in pruned_possibilities:

       if len(l) == min_list_len:

           return l

def compare_cow_transport_algorithms():

      greedy_start = time.time()

   greedy_results = greedy_cow_transport(cows, limit = 10)

   greedy_end = time.time()

   print('Greedy Algorithm time:', greedy_end -greedy_start)

   brute_force_start = time.time()

   brute_force_results = brute_force_cow_transport(cows, limit = 10)

   brute_force_end = time.time()

   print('Brute force time:', brute_force_end - brute_force_start)

   print('Greedy Algorithm results:', greedy_results)

   print('Number of trips returned by Greedy Algorithm:', len(greedy_results))

   print('Brute Force Algorithm results:', brute_force_results)

   print('Number of trips returned by Brute Force Algorithm:', len(brute_force_results))

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You need a stand alone player to play an mp3 audio file on a desktop or laptop computer.

The standalone player is known to be a device that gives room for a person or is one that allows a Blender game to be able to run without one trying to load the Blender system.

Note that in the above, You need a stand alone player to play an mp3 audio file on a desktop or laptop computer.

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Deploying an application across multiple regions can help build a robust architecture for an application that needs to have an up-time of at least 99.5.

The Multi-Region Infrastructure Deployment is known to be one that aids customers a lot to be able to easily control updates in regards to infrastructure needed for applications that are said to be deployed in all of primary and secondary Regions.

Hence, Deploying an application across multiple regions can help build a robust architecture for an application that needs to have an up-time of at least 99.5.

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In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.

A bridge protocol data unit (BPDU) is known to be a kind of a data message that is known to be often  transmitted in a local area network to be able to know or find loops in that given network topologies.

Hence, in the case above, In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.

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. In order to prevent ports that are serving network hosts from being considered as best paths, what should be enabled to block BPDUs?

a. BPDU filter

b. BPDU guard

c. root guard

d. BPDU drop

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Every time a user enters a different web page url into a browser, the same web page appears. the issue that can help is the use of firewall.

The term firewall is known to be that which helps protect a person's network from attackers.

Note that A firewall shields one's network because it work in a 24/7 filter window, and this is one that often works by scanning the data that tries to enter your network and hinder anything that may act or looks suspicious from getting through.

Hence, in the case above, Every time a user enters a different web page url into a browser, the same web page appears. the issue that can help is the use of firewall.

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Horizontal Scaling is the act of increasing capacity by adding nodes or units while increasing capacity by upgrading individual resources to be more powerful is called Vertical Scaling.

Horizontal scaling is known to be the act of  adding more nodes while vertical scaling is a term that connote the act of adding a lot of power to one's current machines.

Therefore, Horizontal Scaling is the act of increasing capacity by adding nodes or units while increasing capacity by upgrading individual resources to be more powerful is called Vertical Scaling.

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The purpose of adding updates to your computer are as follows: